Quiz 5-5 Solve for the missing angle and sides of Triangle ABC where B = 25º, b = 15, C = 107º Triangle ABC where B = 25º, b = 15, C = 107º 1. A = ? 2.

Slides:



Advertisements
Similar presentations
SOLVING FOR THE MISSING PART OF AN OBLIQUE TRIANGLE
Advertisements

The Law of Cosines February 25, 2010.
Law of Sines The Ambiguous Case
The Law of Sines and The Law of Cosines
 Think back to geometry. Write down the ways to prove that two triangles are congruent.
The Law of Sines and The Law of Cosines
Module 8 Lesson 5 Oblique Triangles Florben G. Mendoza.
Math 112 Elementary Functions Section 1 The Law of Sines Chapter 7 – Applications of Trigonometry.
Math 112 Elementary Functions Section 2 The Law of Cosines Chapter 7 – Applications of Trigonometry.
19. Law of Sines. Introduction In this section, we will solve (find all the sides and angles of) oblique triangles – triangles that have no right angles.
Assignment Trig Ratios III Worksheets (Online) Challenge Problem: Find a formula for the area of a triangle given a, b, and.
9.4 The Law of Cosines Objective To use the law of cosines to find unknown parts of a triangle.
The Law of SINES.
Essential Question: What is the law of cosines, and when do we use it?
Work out problems on board Add visuals (ranges of arccos and arcsin) to show why you use LOC for big angles and LOS for small angles.
Law of Cosines Trigonometry MATH 103 S. Rook. Overview Section 7.3 in the textbook: – Law of Cosines: SAS case – Law of Cosines: SSS case 2.
Ambiguous Case Triangles
Laws of Sines. Introduction  In the last module we studied techniques for solving RIGHT triangles.  In this section and the next, you will solve OBLIQUE.
Warm – Up Solve the following triangles for the missing side or angle: 1) 2) 3) 9 10 x 27° 32° 14 8 x 48°
Chapter 5: Trigonometric Functions Lesson: Ambiguous Case in Solving Triangles Mrs. Parziale.
LAW OF SINES: THE AMBIGUOUS CASE. Review Identify if the given oblique triangle can be solved using the Law of Sines or the Law of Cosines 1. X = 21 0,
Law of Cosines MATH Precalculus S. Rook. Overview Section 6.2 in the textbook: – Law of Cosines 2.
Law of Sines & Law of Cosines
Solve a triangle for the AAS or ASA case
6.2 The Law of Cosines.
Trigonometry January 6, Section 8.1 ›In the previous chapters you have looked at solving right triangles. ›For this section you will solve oblique.
9.5 Apply the Law of Sines When can the law of sines be used to solve a triangle? How is the SSA case different from the AAS and ASA cases?
Law of Sines Trigonometry MATH 103 S. Rook. Overview Sections 7.1 & 7.2 in the textbook: – Law of Sines: AAS/ASA Case – Law of Sines: SSA Case 2.
5.5 Law of Sines. I. Law of Sines In any triangle with opposite sides a, b, and c: AB C b c a The Law of Sines is used to solve any triangle where you.
If none of the angles of a triangle is a right angle, the triangle is called oblique. All angles are acute Two acute angles, one obtuse angle.
In section 9.2 we mentioned that by the SAS condition for congruence, a triangle is uniquely determined if the lengths of two sides and the measure of.
Notes Over 8.1 Solving Oblique Triangles To solve an oblique triangle, you need to be given one side, and at least two other parts (sides or angles).
Chapter 6.  Use the law of sines to solve triangles.
EXAMPLE 2 Solve the SSA case with one solution Solve ABC with A = 115°, a = 20, and b = 11. SOLUTION First make a sketch. Because A is obtuse and the side.
Lesson 6.1- Law of Sines Provided by Vivian Skumpija and Amy Gimpel.
1 What you will learn  How to solve triangles by using the Law of Cosines  How to find the area of triangles if the measures of the three sides are given.
Section 4.2 – The Law of Sines. If none of the angles of a triangle is a right angle, the triangle is called oblique. An oblique triangle has either three.
Law of Sines AAS ONE SOLUTION SSA AMBIGUOUS CASE ASA ONE SOLUTION Domain error NO SOLUTION Second angle option violates triangle angle-sum theorem ONE.
Quiz 13.5 Solve for the missing angle and sides of Triangle ABC where B = 25º, b = 15, C = 107º Triangle ABC where B = 25º, b = 15, C = 107º 1. A = ? 2.
The Law of COSINES. Objectives: CCSS To find the area of any triangle. To use the Law of Cosine; Understand and apply. Derive the formula for Law of Cosines.
Law of Cosines HOMEWORK: Lesson 12.4/ Who's Law Is It, Anyway?  Murphy's Law: Anything that can possibly go wrong, will go wrong (at the worst.
Sullivan Algebra and Trigonometry: Section 9.2 Objectives of this Section Solve SAA or ASA Triangles Solve SSA Triangles Solve Applied Problems.
Law of Sines  Use the Law of Sines to solve oblique triangles (AAS or ASA).  Use the Law of Sines to solve oblique triangles (SSA).  Find the.
Law of Sines.
Make it a great day!! The choice is yours!! Complete the Do Now.
Law of Sines Day 65.
Law of Sines.
Section T.5 – Solving Triangles
Oblique Triangles.
If none of the angles of a triangle is a right angle, the triangle is called oblique. All angles are acute Two acute angles, one obtuse angle.
6.1 Law of Sines Objectives:
Law of Sines.
6-3: Law of Cosines
Ambiguous Case Triangles
Re:view Use the Law of Sines to solve: Solve ABC
The Law of Sines.
19. Law of Sines.
50 a 28.1o Warm-up: Find the altitude of the triangle.
Objectives Determine the area of a triangle given side-angle-side information. Use the Law of Sines to find the side lengths and angle measures of a triangle.
Section 6.1.
Law of Sines AAS ONE SOLUTION SSA AMBIGUOUS CASE ASA ONE SOLUTION
13. Law of Sines.
Law of Cosines.
Law of Sines Chapter 9.
7.1, 7.2, 7.3 Law of Sines and Law of Cosines
Ambiguous Case Triangles
7.2 The Law of Sines.
Law of Sines (Lesson 5-5) The Law of Sines is an extended proportion. Each ratio in the proportion is the ratio of an angle of a triangle to the length.
The Law of Sines.
Section 6.1 The Law of Sines
Presentation transcript:

Quiz 5-5 Solve for the missing angle and sides of Triangle ABC where B = 25º, b = 15, C = 107º Triangle ABC where B = 25º, b = 15, C = 107º 1. A = ? 2. a = ? 3. c = ? 4. Are there 0, 1, or 2 triangles for this case? A = 36.9º, b = 5, a = 4

HOMEWORK  Section 5-6 (page 494) (evens) 2, 6 -10, 14, 18, 20, 26-30, 38, 48 (12 problems)

5.6 The Law of Cosines

What you’ll learn about  Solving Triangles (SAS, SSS)  Triangle Area Applications … and why The Law of Cosines is an important extension of the Pythagorean theorem, with many applications.

Your turn: 1. Which of the cases above can be solved using the Law of Sines? 2. Which of the cases is the “ambiguous case” for the Law of Sines? AAA, AAS, ASA, SSS, SAS, SSA AAS, ASA, SSA SSA

A B a C There is a pattern for Law of Cosines c There are six possible unknowns in a triangle (3 sides, 3 angles). b A problem will give you three of the six unknowns. After labeling the triangle with the given information, draw the following pattern (loop the the given information, draw the following pattern (loop the 1 side and its opposite angle and the 2 other sides. 1 side and its opposite angle and the 2 other sides. If three of the four items circled are known, use law of cosines.

Law of Cosines

Triangle Review If the following information is given: C a “Walk around the block” Start at the first side or angle that is known then list the order of the known then list the order of the known items. known items. Side, Angle, side  SAS Law of Sines will not work for SAS but Law of Cosines will º B

SAS The “nice one” C a º B 1 st step: Law of Cosines: 2 nd step: either Law of Sines or Law of cosines. Law of cosines. For SAS: generally use Law of Sines to solve for one of the two remaining angles (because inverse sine function can distinguish between obtuse and acute angles. between obtuse and acute angles.

B a C There is a pattern for Law of Cosines If it is not already given, draw and label a triangle Draw the Law of Cosines pattern. (loop the 1 side and its opposite angle and the 2 other sides. If three of the four items circled are known, use law of cosines. 20º

B 6.5 C 11 5 Use Law of Sines to solve for one of the two remaining angles (because inverse sine function can distinguish inverse sine function can distinguish between obtuse and acute angles. between obtuse and acute angles.

B º 144.8º 15.2º

Your turn: 3. a = ? 4. C = ? 5. B = ? B a C º A

B 5.6 C 4 6 Use Law of Sines to solve for one of the two remaining angles (because inverse sine function can distinguish inverse sine function can distinguish between obtuse and acute angles. between obtuse and acute angles.

5 Triangle Review If the following information is given: C 7 9 “Walk around the block” Start at the first side or angle that is known then list the order of the known then list the order of the known items. known items. Side, side, side  SSS Law of Sines will not work for SSS but Law of Cosines will.

5SSS This is the “sticky second step” C st step: Law of Cosines (pick the biggest angle 1 st ) AND 2 nd Step: do Law of Cosines AGAIN!!!!!

B 9 C There is a pattern for Law of Cosines 7 5 If three of the four items circled are known, use law of cosines. 50.7º

A 9 Try Law of sines (for the 2 nd step) º

9 A Try Law of Cosines (for the 2 nd Step) º 2 nd step Law of Sines: 2 nd step Law of Cosines: Which one is correct?!!!

Your turn: 6. Solve the triangle. 23 C B A 33.5º

Your turn: 6. Solve the triangle. 23 C B A 33.5º SSS: This is the “silly second step”

C a “Walk around the block” Side, Angle, side  SAS Law of Sines will not work for SAS but Law of Cosines will º B A

C 6.5  SAS º B A

B 6.5 Draw the cosine pattern º Find the last angle. C = 180 – 20 – 14.8 B = 14.8º 14.8° C A C = °

Your turn: 7. c = ? 8. A = ? 9. B = ?

C “The shortest distance between two points is a straight line.” B A SSS: does it form a triangle? AB represents the distance between points A and B. “Going from “A” directly to “B” is shorter than going from “A” to “B” via “C”.

C B A SSS: does it form a triangle? AB = 1 1 BC = 2 AC = 3 23 check check NO!!! 3 = 3

Your turn: 10. AB = 4, AC = 6, BC = AB = 19, AC = 14, BC = 3

Summary SSS 1. Always solve for the largest angle first 2. Use Law of Cosines to find the second angle 3. Calculate third angle SAS 1. Use Law of cosines to find missing side. 2. Use Law of sines to find the second angle 3. Calculate third angle

Area of a Triangle C B 6.5 5A 144.5º Area = ½(5)(6.5)sin(144.5) Area = 9.4 Area = ½*b*c*sin A Area = ½*a*c*sin B Area = ½*a*b*sin C A = 144.5º, b = 5, c = 6.5

Your turn: C B 8 7A 25º Area = ½(7)(8)sin(25) Area = 11.8 Area = ½*b*c*sin A Area = ½*a*c*sin B Area = ½*a*b*sin C A = 25º, b = 7, c = Find the area of triangle ABC