Mole Island Diagram

How Big is a Mole? One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles. One mole of $1 bills stacked one on top of another would reach from the Sun to Pluto and back 7.5 million times. It would take light 9500 years to travel from the bottom to the top of a stack of 1 mole of $1 bills.

Amedeo Avogadro 1 mole = 602213673600000000000000 or 6.022 x 1023 ? quadrillions thousands trillions billions millions 1 mole = 602213673600000000000000 or 6.022 x 1023

Welcome to Mole Island 1 mol = molar mass 1 mole = 22.4 L @ STP 6.02 x 1023 particles

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mass Mountain Mass Mole Island Volume Mole Mole Volume V Liter Lagoon Particles Particles P Particle Place Stoichiometry Island Diagram

Stoichiometry Mole Island Diagram When in doubt…convert to moles! Known Unknown Substance A Substance B Mass Mass 1 mole = molar mass (g) 1 mole = molar mass (g) Use coefficients from balanced chemical equation Volume Mole Mole Volume 1 mole = 22.4 L @ STP 1 mole = 22.4 L @ STP (gases) (gases) 1 mole = 6.022 x 1023 particles (atoms or molecules) 1 mole = 6.022 x 1023 particles (atoms or molecules) Particles Particles

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mass Mountain Mass Volume Mole Mole Volume V Liter Lagoon Particles Particles P Particle Place Stoichiometry Island Diagram

Mass, Volume, Mole Relationship

A. Using Mole Island Zn + 2HCl  ZnCl2 + H2 79.1 g ? L 79.1 g Zn 1 mol Just watch, don’t write: If you have 79.1 g of Zn to react with excess HCl (enough HCl to keep reacting as long as you need), how many Liters of H2 gas will be produced? Zn + 2HCl  ZnCl2 + H2 79.1 g ? L 79.1 g Zn 1 mol Zn 65.39 g Zn 1 mol H2 Zn 22.4 L H2 1 mol = 27.1 L H2

B. Using Mole Island Zn + 2HCl  ZnCl2 + H2 ? L 79.1 g 79.1g HCl 1 mol Now write this one for practice: If you instead have 79.1 g of HCl to react with excess Zinc (enough Zinc to keep reacting as long as you need), how many Liters of H2 gas will be produced? Zn + 2HCl  ZnCl2 + H2 ? L 79.1 g 79.1g HCl 1 mol HCl 36.5g HCl 1 mol H2 2 mol HCl 22.4 L H2 1 mol = 24.3 L H2

Zn + 2HCl  ZnCl2 + H2 79.1 g 79.1 g HCl 1 mol HCl 36.5 g Zn 1 mol H2 Other possibilities: Still starting with 79.1 grams of HCl, how many molecules of H2 gas are produced? Or what mass of H2 gas is produced? How would these questions change your calculations? Zn + 2HCl  ZnCl2 + H2 79.1 g ? mc Or ? g Same conversion to moles, same mole to mole ratio, different last conversions… 79.1 g HCl 1 mol HCl 36.5 g Zn 1 mol H2 2 mol HCl 6.02 x 1023 mc H2 1 mol H2 = 6.5 x 1023 mc H2 = 2.17 g H2