Assigned work: pg. 443 #2,3ac,5,6-9,10ae,11,12 Recall: We have used a direction vector that was parallel to the line to find an equation. Now we will use.

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Presentation transcript:

Assigned work: pg. 443 #2,3ac,5,6-9,10ae,11,12 Recall: We have used a direction vector that was parallel to the line to find an equation. Now we will use a vector perpendicular to the line called “the Normal Vector”, to find an equation of the line. S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane Scalar Equation of a Line in a Plane: S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane Ex1: Find the scalar equation of the line that passes through points P(8,2) and has a normal S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane Ex2: Find the Cartesian equation of each of the following: a) The line S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane b) The line passes through (-6,3) and parallel to the line 2x-3y+5=0 S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane S. Evans The distance formula from a point,Q, to a line can be derived (below ) from the Scalar Projection of

8.2 Scalar or Cartesian Equation of a Line in a Plane S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane Distance Formula from a point (x 1, y 1 ) to the line Ax+By+Cz=0 is: S. Evans

8.2 Scalar or Cartesian Equation of a Line in a Plane Ex 3: Find the distance from P(-4,2) to the line S. Evans