TopicSlidesMinutes 1 Displacement 927 2 1339 3 Kinematics 1339 4 Graphs 1030 5 Energy 1030 6 Power 515 7 Springs 412 8 Shadows 39 9 Field of Vision.

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Presentation transcript:

TopicSlidesMinutes 1 Displacement Kinematics Graphs Energy Power Springs Shadows 39 9 Field of Vision Colors Concave mirrors Convex mirrors Refraction Lenses Optical Power 618 Vectors

The word “component” means a “part” of a system. When dealing with vectors, the word “components” refers to the vector parts that “add up” or constitute a vector. Note well that while any vector may have many component vectors, there are two “special” vectors that that when added together result in the given vector. Horizontal Component The horizontal component of a given vector is that part which acts along the horizontal axis (x-axis). Vertical Component The vertical component of a given vector is that part which acts along the vertical axis (y-axis). Click FHFH FHFH FVFV FVFV

Together, the horizontal and vertical components make up a vector. Vector Vertical axis Horizontal axis Vertical component Horizontal component Vector = Horizontal component + Vertical component REMEMBER All vectors can be represented by their Horizontal and Vertical components.

Remember Next “North” is “Up” “South” is “Down” “East” is “Right” “West” is “Left” N (Up) S (Down) E (Right) (Left) W

Click Calculate and sketch the horizontal and vertical components for each of the given forces: 200 N [West] F H = ____________________F V = ____________________ 200 N [West] 0 N (or Up) S (or Down) E (or Right)W (or Left) Vectors Slide:

N S EW Click Calculate and sketch the horizontal and vertical components for each of the given forces: 500 N [North] F H = ____________________F V = ____________________ 0500 N [North] Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 500 N [Southeast] F H = ____________________F V = ____________________ 354 N [East]354 N [South] F H = 500 N Cos 45 o = 354 NF V = 500 N Sin 45 o = 354 N REMINDER Southeast means at 45 o between South and East. NOTE Round off your answers to the nearest whole number. 45 o Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 400 N [25 o from the horizontal] F H = ____________________F V = ____________________ 363 N [East] 169 N [North] F H = 400 N Cos 25 o = 363 N F V = 400 N Sin 25 o =169 N 25 o 400 N Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 290 N [S 60 o E] F H = ____________________F V = ____________________ 251 N [East] 145 N [South] This means “from the South, 60 o East” 60 o F H = 290 N Sin 60 o = 251 NF V = 290 N Cos 60 o = 145 N 290 N Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 600 N [W 60 o S] F H = ____________________F V = ____________________ 300 N [West] 520 N [South] This means “from the West, 60 o South” F V = 600 N Sin 60 o = 520 N 60 o F H = 600 N Cos 60 o = 300 N 600 N Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 400 N [E 35 o N] F H = ____________________F V = ____________________ 328 N [East] 229 N [North] This means “from the East, 35 o North” 35 o F H = 400 N Cos 35 o = 328 N F V = 400 N Sin 35 o = 229 N 400 N Vectors Slide:

Click Calculate and sketch the horizontal and vertical components for the following force: 500 N [S 20 o W] F H = ____________________F V = ____________________ 171 N [West] 470 N [South] This means “from the South, 20 o West” 20 o F H = 500 N Sin 20 o = 171 NF V = 500 N Cos 20 o = 470 N 500 N Vectors Slide:

Click The diagram on the right illustrates four forces acting on a cart that is free to move in any direction. Which of the following forces will place the system in equilibrium? A)3.00 N at 0 o from horizontal B)12.2 N at 180 o from horizontal C)12.2 N at 0 o from horizontal D)3.00 N at 180 o from horizontal E)22.4 N at 0 o from horizontal FRFR Click 180 o FEFE Vectors Slide:

Click Vectors Slide: 2. 10

Click An electron is subjected to a magnetic force of 2.6 x 10 ‑ 24 N acting horizontally and an electric force of 3.0 x 10 ‑ 24 N acting vertically. Determine the equilibrant force. Vectors Slide: 2. 11

Click An object is suspended by a cord which is 5.2 m long. As shown in the diagram, the horizontal force, F, is 75 N East. Calculate the mass of the object. A) 18 kg B) 1.8 kg C) 39 kg D) 28 kg E) 46.5 kg F H = 75 N A First we find the angle Click 11 o Click 11 o 386 N Next we find the weight Click Finally we find the mass w Click Vectors Slide: 2. 12

When a weight is hung in the middle of a 20 m long wire, the wire sags 3 m. If the tension in the wire is 270 N, determine the weight. A) 155 N B) 102 N C) 78 N D) 48 N E) 26 N Click Step-1 Draw all the forces acting on the system. T = 270 N w w/2 Click Step-2 Find the angle. 3 m 10 m Click 73.3 o Step-3 Find the weight. With reference to the shaded triangle: Click Vectors Slide: 2. 13

… and good luck!