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Probability of Compound Events
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Presentation transcript:

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learning goal Find probabilities of independent and dependent events. Find probabilities of mutually exclusive events. Then/Now

Concept

Independent Events TRAVEL Rae is flying from Birmingham to Chicago on a flight with a 90% on-time record. On the same day, the chances of rain in Denver are predicted to be 50%. What is the probability that Rae’s flight will be on time and that it will rain in Denver? Example 1

P(A and B) = P(A)●P(B) = 0.9 ● 0.5 = 0.45 Independent Events Probability of independent events P(A and B) = P(A)●P(B) P(on time and rain) = P(on time) ● P(rain) = 0.9 ● 0.5 90% = 0.9 and 50% = 0.5 = 0.45 Multiply. Answer: The probability that Rae’s flight will be on time and that it will rain in Denver is 45%. Example 1

Two cities, Fairfield and Madison, lie on different faults Two cities, Fairfield and Madison, lie on different faults. There is a 60% chance that Fairfield will experience an earthquake by the year 2020 and a 40% chance that Madison will experience an earthquake by 2020. Find the probability that both cities will experience an earthquake by 2020. A. 60% B. 40% C. 24% D. 100% Example 1

Concept

Dependent Events A. GAMES At the school carnival, winners in the ring-toss game are randomly given a prize from a bag that contains 4 sunglasses, 6 hairbrushes, and 5 key chains. Three prizes are randomly drawn from the bag and not replaced. Find P(sunglasses, hairbrush, key chain). The selection of the first prize affects the selection of the next prize since there is one less prize from which to choose. So, the events are dependent. Example 2

Dependent Events First prize: Second prize: Third prize: Example 2

Answer: or about 4.4%. Substitution Multiply. Dependent Events P(sunglasses, hairbrush, key chain) = P(sunglasses)●P(hairbrush)●P(key chain) Substitution Multiply. Answer: or about 4.4%. Example 2

Dependent Events B. GAMES At the school carnival, winners in the ring-toss game are randomly given a prize from a bag that contains 4 sunglasses, 6 hairbrushes, and 5 key chains. Three prizes are randomly drawn from the bag and not replaced. Find P(hairbrush, hairbrush, not a hairbrush). After two hairbrushes are selected, there are 13 prizes left. Since both of the prizes are hairbrushes, there are still 9 prizes that are not hairbrushes. Example 2

P(hairbrush, hairbrush, not a hairbrush) Dependent Events P(hairbrush, hairbrush, not a hairbrush) = P(hairbrush) ● P(hairbrush) ● P(not a hairbrush) ● = Answer: The probability is or about 9.9%. Example 2

Concept

Mutually Exclusive Events A. A card is being drawn from a standard deck. Find the probability of P(7 or 8). Since a card cannot show a 7 and an 8 at the same time, these events are mutually exclusive. ← ← Example 3

P(7 or 8) = P(7) + P(8) Probability of mutually exclusive events. Substitution Add. Answer: The probability of drawing a 7 or 8 is or about 15.4%. Example 3

Mutually Exclusive Events B. A card is being drawn from a standard deck. Find the probability of P(neither club nor heart). You can find the probability of drawing a club or a heart and then subtract this from 1. ← ← Example 3

Mutually Exclusive Events P(club or heart) = P(club) + P(heart) Probability of mutually exclusive events. Substitution Add. Answer: The probability of not drawing a club or a heart is 1 – = or 50%. Example 3

A. The French Club has 16 seniors, 12 juniors, 15 sophomores, and 21 freshmen as members. What is the probability that a member chosen at random is a junior or a senior? A. B. 1 C. D. 0 Example 3

B. The French Club has 16 seniors, 12 juniors, 15 sophomores, and 21 freshmen as members. What is the probability that a member chosen at random is not a senior? A. B. C. D. Example 3

Concept

Events that are Not Mutually Exclusive GAMES In the game of bingo, balls or tiles are numbered 1 through 75. These numbers correspond to columns on a bingo card, as shown in the table. A number is selected at random. What is the probability that it is a multiple of 5 or is in the N column? Example 4

P(multiple of 5) P(N column) P(multiple of 5 and N column) = Events that are Not Mutually Exclusive Since a tile can be a multiple of 5 and in the N column, the events are not mutually exclusive. P(multiple of 5) P(N column) P(multiple of 5 and N column) = = P(multiple of 5 or N column) = P(multiple of 5) + P(N column) – P(multiple of 5 and N column) Example 4

Answer: The probability is or 36%. Events that are Not Mutually Exclusive Substitution Simplify. Answer: The probability is or 36%. Example 4

In Mrs. Kline’s class, 7 boys have brown eyes and 5 boys have blue eyes. Out of the girls, 6 have brown eyes and 8 have blue eyes. If a student is chosen at random from the class, what is the probability that the student will be a boy or have brown eyes? A. B. C. D. Example 4

End of the Lesson