Esters Organic compound formed by the condensation reaction of a carboxylic acid and an alcohol. O O R-C-OH + R-OH R-C-O-R’ + H2O (ester)

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Presentation transcript:

Esters Organic compound formed by the condensation reaction of a carboxylic acid and an alcohol. O O R-C-OH + R-OH R-C-O-R’ + H2O (ester)

Esters R-C-O-R’ O Naming: Parent chain “R” (including the C bonded to the oxygens) Name the parent as an alkane Take off the “e”. Add –oate Branches Identify alkyl group, R’ Add alkyl name in front of parent chain.

O C-C-O-C-C-C Example Parent: ethane ethanoate Branch: propyl Final name: propyl ethanoate

O C-C-C-C-O-C-C Example Parent: butane butanoate Branch: ethyl Final name: ethyl butanoate

Draw: pentyl hexanoate O C-C-C-C-C-C-O-C-C-C-C-C

O C-O-C-C-C Name: Parent: propane propanoate Branch: methyl Final name: methyl propanoate

Amines R’ Organic compounds that are derivatives of ammonia (NH3 ). R-N-R” R’ Naming: Name the branches (R, R’, R”) in alphabetical order; they can also be halogens. Add the word amine at the end.

Primary amine methyl amine H (1 hydrogen is replaced by an alkyl group) C-N-H H methyl amine

Secondary amine ethyl methyl amine H (2 hydrogens are replaced by alkyl groups) C-N-C-C H ethyl methyl amine

ethyl methyl propyl amine Tertiary amine (3 hydrogens are replaced by alkyl groups) C-N-C-C C-C-C ethyl methyl propyl amine

Draw: pentyl propyl amine C-C-C-C-C-N-C-C-C H