Lesson 3 Menu Five-Minute Check (over Lesson 10-2) Main Ideas and Vocabulary Targeted TEKS Example 1: Variable in Radical Example 2: Radical Equation with.

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Presentation transcript:

Lesson 3 Menu Five-Minute Check (over Lesson 10-2) Main Ideas and Vocabulary Targeted TEKS Example 1: Variable in Radical Example 2: Radical Equation with an Expression Example 3: Variable on Each Side

Lesson 3 MI/Vocab radical equation extraneous solution Solve radical equations. Solve radical equations with extraneous solutions.

Lesson 3 Ex1 FREE-FALL HEIGHT An object is dropped from an unknown height and reaches the ground in 5 seconds. From what height is it dropped? Variable in Radical Original equation Replace t with 5. Multiply each side by 4.

Lesson 3 Ex1 Square each side. 400 = h Simplify. Check by substituting 400 for h in the original equation. Answer: 400 ft Variable in Radical

A.A B.B C.C D.D Lesson 3 CYP1 A.28 ft B.11 ft C.49 ft D.784 ft

Lesson 3 Ex2 Radical Equation with an Expression x = 52Add 3 to each side. Answer: The solution is 52. Original equation Subtract 8 from each side. Square each side.

Lesson 3 CYP2 1.A 2.B 3.C 4.D A.64 B.60 C.4 D.196

Lesson 3 Ex3 Variable on Each Side 2 – y =y 2 Simplify. 0=y 2 + y – 2Subtract 2 and add y to each side. 0=(y + 2)(y – 1)Factor. y + 2=0 or y – 1 = 0Zero Product Property y=–2 y = 1Solve. Original equation Square each side.

Lesson 3 Ex3 Variable on Each Side Check Answer: Since –2 does not satisfy the original equation, 1 is the only solution. ?? ? ? X

1.A 2.B 3.C 4.D Lesson 3 CYP3 A.3 B.–1 C.0 D.–3