Equations with variables on each side. -2 + 10p = 8p -1p = 0.5 3w + 2 = 7w w = 1/2 s/2 + 1 = ¼ s - 6s = - 28 8 + 5s = 7s - 2 s = 5.

Slides:



Advertisements
Similar presentations
Solving Equations with Variables on Both Sides
Advertisements

Equal Values Method. Since we want to know when the weights (y) are equal, the right sides need to be equal too. Example: Chubby Bunny Barbara has a bunny.
Equations with the Variable on Both Sides
Math Journal −3
Math Journal 9-30 − 5 8
Do Now: Solve the following equations
EOC Practice EOC Practice Continues.
Warm Up Simplify. 1. 4x – 10x 2. –7(x – 3) 3. –6x – (x – 2)
2.4 Solving Equations with Variables on both sides
Check it out! 1.3.1: Creating and Graphing Linear Equations in Two Variables 1.
Holt Algebra Solving Equations by Adding or Subtracting Over 20 years, the population of a town decreased by 275 people to a population of 850. Write.
Solve Equations With Variables on Both Sides
2-3 Solving Multi-Step Equations Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview.
Bell Work: Be ready to hand in your signed course syllabus, and have your notebook out, open, and ready for notes!!!
Warm-up Use the distributive property to rewrite the expression without parentheses. 1.) 8(x + 5)2.) 4(y – 7)3.) (x – 4)(2) 4.) –6(r – 1)5.) (m – 7)( –3)
9 Weeks Test Review 8 TH GRADE. Simplify…if possible3  3 y + 2 y + y y.
ALGEBRA 1 Lesson 3-5 Warm-Up. ALGEBRA 1 Lesson 3-5 Warm-Up.
1. Jon and Sara are planting tulip bulbs. Jon has planted 60 bulbs and is planting at a rate of 44 bulbs per hour. Sara has planted 96 bulbs and is planting.
Solve Equations With Variables on Both Sides. Example 1 3x + 4 = 5x – 8 Since the x’s are on opposite sides of the equal sign, you must “get rid” of one.
To solve an equation with variables on both sides, use inverse operations to "collect" variable terms on one side of the equation. Helpful Hint Equations.
Preview Warm Up California Standards Lesson Presentation.
2-4 Solving Equations with Variables on Both Sides Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation.
Holt Algebra Solving Linear Equations and Inequalities Section 2.1 Solving Linear Equations and Inequalities.
2-3 Solving Multi-Step Equations. 2-3 Solving Multi-Step Equations Objective: SWBAT write and solve multi-step equations using inverse operations.
Chapter Prerequisite Skills Chapter Prerequisite Skills Chapter 3 Multi-Step Equations and Inequalities.
U Try ( -2,9) 5x + y = -1 6x + 2y = 4 Show why the point is not a solution to the system.
Sec. 1-5 Day 1 HW pg (16-26 even, 33-36). An identity is an equation that is true for all values of the variable. An equation that is an identity.
Holt Algebra Solving Two-Step and Multi-Step Equations Solve equations in one variable that contain more than one operation. Objective.
CONFIDENTIAL 1 Grade 8 Pre-Algebra Solving Equations with Variables on Both Sides.
Section 3.4 Solving Equations with Variables on Both Sides Objectives: Collect variables on one side of an equation.
Holt CA Algebra 1 Copyright © by Holt, Rinehart and Winston. All Rights Reserved. Which expression always represents an odd number? A. n B. 2n +
Opener: Find three consecutive odd integers whose sum is -63 Integer #1 = n Integer #2 = n + 2 Integer #3 = n + 4 (n) + (n + 2) + (n + 4) = -63 3n + 6.
Chapter 3 – Solving Linear Equations Algebra I A - Meeting 14 Homework # 10 – Word Problems pg 152 # 40 To qualify for a lifeguard training course, you.
1.) Consecutive integers are integers that follow each other in order (for example 5, 6, 7). Find three consecutive integers whose sum is ) You have.
SOLVING EQUATIONS WITH VARIABLES ON BOTH SIDES Wednesday Sept. 9, 2015 Algebra.
CONFIDENTIAL 1 Algebra1 Solving Two-Step and Multi-Step Inequalities.
Holt Algebra Solving Equations with Variables on Both Sides Warm Up Simplify. 1. 4x – 10x 2. –7(x – 3) – (x – 2) Solve. 5. 3x + 2 = 8 6.
To solve an equation with variables on both sides, use inverse operations to "collect" variable terms on one side of the equation. Helpful Hint Equations.
Solving Equations with Variables on Both Sides 2-4
Solving Equations with Variables on Both Sides
Solve Equations With Variables on Both Sides
Solving Equations with Variables on Both Sides 1-5
Solving Equations with Variables on Both Sides 3.2
The learner will solve equations with variables on both sides
Unit 1 Day 3: Solving Equations with variables on both sides
Unit 1 Day 7: Solving Inequalities with Variables on Both Sides
Preview Warm Up California Standards Lesson Presentation.
Solve Equations With Variables on Both Sides
Solving Equations with variables on each side
Solving Equations with Variables on Both Sides
Solving Equations with Variables on Both Sides
Solving Equations with Variables on Both Sides
Equations with Variables on Both Sides
Solving Equations with Variables on Both Sides
Solving Equations with Variables on Both Sides 1-5
Solving Equations with Variables on Both Sides 2-4
Solving Equations with Variables on Both Sides 2-4
Solving Equations with Variables on Both Sides 1-5
Solving Equations with Variables on Both Sides 1-5
Solving Equations with Variables on Both Sides 2-4
4-2 Word Problems again!!! Goal:
Warm Up Simplify. 1. 4x – 10x 2. –7(x – 3) Solve. 3. 3x + 2 = 8.
Solving Equations with Variables on Both Sides 2-4
Solving Equations with Variables on Both Sides 1-5
2-3 Equations With Variables on Both Sides
Solving Equations with Variables on Both Sides 1-5
Solving Equations with Variables on Both Sides 2-4
Solving Equations with Variables on Both Sides 2-4
Preview Warm Up California Standards Lesson Presentation.
Solving Equations with Variables on Both Sides 2-4
Presentation transcript:

Equations with variables on each side p = 8p -1p = 0.5 3w + 2 = 7w w = 1/2 s/2 + 1 = ¼ s - 6s = s = 7s - 2 s = 5

Variables Both Sides Grade: Subject: Algebra Date:

120c + 5 = 5c + 65

2(3/8) - (1/4)t = (1/2)t - (3/4)

·4(2r - 8) = (1/7)(49r + 70)r = 42 ·8s - 10 = 3(6 - 2s) s = 2 ·7(n - 1) = -2(3 + n) n = 1/9

Distribute Grade: Subject: Algebra Date:

13(a - 5) = -6

26 = 3 + 5(d - 2)

·2m + 5 = 5(m - 7)m = (40/3) ·3(r + 1) - 5 = 3r - 2identity; true for all values of r ·7x + 5(x - 1) = xall numbers ·6(y - 5) = 2(10 + 3y)no solution

Grade: Subject: Algebra Date: None or All Numbers

15 + 2(n + 1) = 2n A no solutions B all real numbers C 4

27 - 3r = r - 4(2 + r) A no solutions B all numbers C 1

314v + 6 = 2(5 + 7v) - 4 A no solution B all numbers C 0

45h - 7 = 5(h - 2) + 3 A no solution B all numbers C 0

Extra Equation Practice ·One half of a number increased by 16 is four less than two thirds of the number. Find the number. 120 ·The sum of one half of a number and 5 equals one third of the number. What is the number? - 30 · Two less than one third of a number equals 3 more than one fourth of the number. Find the number. 60 ·Two times a number plus 6 is three less than one fifth of the number. What is the number? - 5

At a local gym, there is a joining fee of $59.95 and a monthly membership fee. Sara and Martin both joined this gym. Their combined cost for 12 months was $ How much is the monthly fee? $50

Lily and 4 of her friends want to enroll in a yoga class. After enrollment, the studio requires a $7 processing fee. The 5 girls pay a total of $ How much does the class cost? $18.15

Four times Greg's age, decreased by 3 is equal to 3 times Greg's age, increased by 7. How old is Greg? 10 years old

The long-distance phone rates of two phone companies are shown in the table. How long is a call that costs the same amount no matter which company is used? What is the cost of that call? The cost of a 12-minute call through either company is $0.72.

Joe and Sara are planting tulip bulbs. Joe has planted 60 bulbs and is planting at a rate of 44 bulbs per hour. Sara has planted 96 bulbs and is planting at a rate of 32 bulbs per hour. In how many hours will Joe and Sara have planted the same number of bulbs? How many bulbs will that be? 3 hours; 192 bulbs

Justin and Tyson are beginning an exercise program to train for football season. Justin weighs 150 lbs and hopes to gain 2 lbs per week. Tyson weighs 195 lbs and hopes to lose 1 lb per week. If the plan works, in how many weeks will the boys weigh the same amount? What will that weight be? 15 weeks; 180 lbs.

Equation Practice Grade: Subject: Algebra Date:

13k - 5 = 7k - 21

25t - 9 = - 3t + 7

38s + 9 = 7s + 6

43 - 4q = 10q + 10

5(3/4)n + 16 = 2 - (1/8)n

61/4 - (2/3)y = 3/4 - (1/3)y

7(c + 1)/8 = c/4

8(3m - 2)/5 = 7/10

98 = 4(3c + 5)

107(m - 3) = 7

116( r + 2) - 4 = -10

125 - (½)(x - 6) = 4

134(2a - 1) = -10(a - 5)

142(w - 3) + 5 = 3(w - 1)