Chapter 2: Kinematics in one Dimension Displacement Velocity Acceleration HW2: Chap. 2: pb.3,pb.8,pb.12,pb.22,pb.27,pb.29,pb.46 DUE on Wednesday, Sept.

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Chapter 2: Kinematics in one Dimension Displacement Velocity Acceleration HW2: Chap. 2: pb.3,pb.8,pb.12,pb.22,pb.27,pb.29,pb.46 DUE on Wednesday, Sept 9

Instantaneous Velocity Example 2-3: Given x as a function of t. A jet engine moves along an experimental track (which we call the x axis) as shown. We will treat the engine as if it were a particle. Its position as a function of time is given by the equation x = At 2 + B, where A = 2.10 m/s 2 and B = 2.80 m. (a) Determine the displacement of the engine during the time interval from t 1 = 3.00 s to t 2 = 5.00 s. (b) Determine the average velocity during this time interval. (c) Determine the magnitude of the instantaneous velocity at t = 5.00 s.

Acceleration Acceleration is the rate of change of velocity. Example 2-4: Average acceleration. A car accelerates along a straight road from rest to 90 km/h in 5.0 s. What is the magnitude of its average acceleration?

Acceleration Conceptual Example 2-5: Velocity and acceleration. (a) If the velocity of an object is zero, does it mean that the acceleration is zero? (b) If the acceleration is zero, does it mean that the velocity is zero? Think of some examples.

Average acceleration from a graph of v x (t) v1v1 t1t1 v2v2 t2t2 t vxvx

Acceleration Example 2-6: Car slowing down. An automobile is moving to the right along a straight highway, which we choose to be the positive x axis. Then the driver puts on the brakes. If the initial velocity (when the driver hits the brakes) is v 1 = 15.0 m/s, and it takes 5.0 s to slow down to v 2 = 5.0 m/s, what was the car’s average acceleration ?

Acceleration There is a difference between negative acceleration and deceleration: Negative acceleration is acceleration in the negative direction as defined by the coordinate system. Deceleration occurs when the acceleration is opposite in direction to the velocity.

Review Question The slope of a velocity vs. time graph is A) the displacement B) the velocity C) the acceleration D) the time

Instantaneous acceleration from a graph of v x (t) v t Time (t) t v ∆t

Acceleration Example 2-7: Acceleration given x(t). A particle is moving in a straight line so that its position is given by the relation x = (2.10 m/s 2 )t 2 + (2.80 m). Calculate (a) its average acceleration during the time interval from t 1 = 3.00 s to t 2 = 5.00 s, and (b) its instantaneous acceleration as a function of time.

The average velocity of an object during a time interval t is The acceleration, assumed constant, is Motion at Constant Acceleration

In addition, as the velocity is increasing at a constant rate, we know that Combining these last three equations, we find:

Motion at Constant Acceleration We can also combine these equations so as to eliminate t: We now have all the equations we need to solve constant-acceleration problems.

Solving Problems Example 2-11: Air bags. Suppose you want to design an air bag system that can protect the driver at a speed of 100 km/h (60 mph) if the car hits a brick wall. Estimate how fast the air bag must inflate to effectively protect the driver. How does the use of a seat belt help the driver?

Freely Falling Objects Near the surface of the Earth, all objects experience approximately the same acceleration due to gravity. This is one of the most common examples of motion with constant acceleration.