Solve
27 grams of carbs 10 grams of fat 4 grams of protein Answer: 27 x 4 =108 kcals 10 x 9 = 90 kcals 4 x 4 = 16 kcals 214 kcals
5 grams of fat 11 grams of protein 33 grams of carbs Answer: 9 x 5 = 45 kcals 33 x 4 = 132 kcals 177 kcals
Starting temp is 77 0 C Ending temp is C Answer: T =T 2 -T 1 T = T = C T x V = calories V = 10ml 171 x 10 = 1,710 1,710/1,000= 1.710
Starting temperature is 45 0 C Ending temperature is C T =T 2 -T 1 313 – 45 = C
39 grams of carbohydrates 12 grams of fat 13 grams of protein 12g x 9 kcals/g = 108 kcals
Starting temp is 80 0 C Ending temp is C Answer: T =T 2 -T 1 T = T = C T x V = calories V = 10ml 250 x 10 = 2,500
7g x 4 kcal/g = 28 kcals 4g x 4 kcal/g = 16 kcals 3g x 9 kcal/g = 27 kcals 71 kcals
T = T 2 – T 1 175º C - 70 C = T T = 105 ºC
T x V = calories 105 ºC x 10mL = calories 1050 calories
T = T 2 – T 1 T = 185 ºC - 65 ºC T = 120 ºC T x V = 120 x 10 = 1,200
71g x 4 kcal/g =284 kcals of carbs 10g x 9 kcal/g = 90 kcals of fat 5g x 4 kcal/g = 20 kcals of protein
23g x 4 kcal/g =92 kcals of carbs 4g x 4 kcal/g = 16 kcals of protein 5g x 9 kcal/g = 45 kcals of fat Total = 153 kcals
20g x 4 kcal/g =80 kcals of carbs 7g x 4 kcal/g = 28 kcals of protein Carbs + protein = 108kcals
Starting temp is 35 0 C Ending temp is 54 0 C Answer: T =T 2 -T 1 T =54-35 T = 19 0 C T x V = calories V = 30ml 19 x 30 = 570 calories 570/1,000=.57 Kcals
Starting temp is 45 0 C Ending temp is 55 0 C Answer: T =T 2 -T 1 T =55-45 T = 10 0 C