Solve  27 grams of carbs  10 grams of fat  4 grams of protein  Answer:  27 x 4 =108 kcals  10 x 9 = 90 kcals  4 x 4 = 16 kcals  214 kcals.

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Presentation transcript:

Solve

 27 grams of carbs  10 grams of fat  4 grams of protein  Answer:  27 x 4 =108 kcals  10 x 9 = 90 kcals  4 x 4 = 16 kcals  214 kcals

 5 grams of fat  11 grams of protein  33 grams of carbs  Answer:  9 x 5 = 45 kcals  33 x 4 = 132 kcals  177 kcals

 Starting temp is 77 0 C  Ending temp is C  Answer:   T =T 2 -T 1   T =   T = C   T x V = calories  V = 10ml  171 x 10 = 1,710  1,710/1,000=  1.710

 Starting temperature is 45 0 C  Ending temperature is C   T =T 2 -T 1  313 – 45 =  C

 39 grams of carbohydrates  12 grams of fat  13 grams of protein  12g x 9 kcals/g =  108 kcals

 Starting temp is 80 0 C  Ending temp is C  Answer:   T =T 2 -T 1   T =   T = C   T x V = calories  V = 10ml  250 x 10 =  2,500

 7g x 4 kcal/g = 28 kcals  4g x 4 kcal/g = 16 kcals  3g x 9 kcal/g = 27 kcals  71 kcals

  T = T 2 – T 1  175º C - 70  C =  T   T = 105 ºC

  T x V = calories  105 ºC x 10mL = calories  1050 calories

  T = T 2 – T 1   T = 185 ºC - 65 ºC   T = 120 ºC   T x V =  120 x 10 = 1,200

 71g x 4 kcal/g =284 kcals of carbs  10g x 9 kcal/g = 90 kcals of fat  5g x 4 kcal/g = 20 kcals of protein

 23g x 4 kcal/g =92 kcals of carbs  4g x 4 kcal/g = 16 kcals of protein  5g x 9 kcal/g = 45 kcals of fat  Total = 153 kcals

 20g x 4 kcal/g =80 kcals of carbs  7g x 4 kcal/g = 28 kcals of protein  Carbs + protein = 108kcals

 Starting temp is 35 0 C  Ending temp is 54 0 C  Answer:   T =T 2 -T 1   T =54-35   T = 19 0 C   T x V = calories  V = 30ml  19 x 30 = 570 calories  570/1,000=.57 Kcals

 Starting temp is 45 0 C  Ending temp is 55 0 C  Answer:   T =T 2 -T 1   T =55-45   T = 10 0 C