Quadratic Equation Quadratic equations, such as x = v i t + ½ a t 2 can be tricky to solve. 3 strategies 1.Factoring (doesn’t usually work well with physics) 2.Quadratic Equation solution (always works, but you need to memorize) 3.Trial & Error / Plugging in values (can be useful for multiple choice) We will talk about #2 and #3.

Quadratic Equation Solution First, put your equation into this form: 0 = at 2 + bt + c for example, x = v i t + ½ at 2 becomes 0 = ½ at 2 +v i t – x so, a = ½ a b = v i c = -x Then, use this equation to solve for t

Quadratic Equation Solution – We do A ball is launched upward with a speed of 15 m/s from an intial height of 5 m. What are the two approximate times that the object will be located at the height of 10 m above the ground?

Quadratic Equation Solution – We do A ball is launched upward with a speed of 15 m/s from an intial height of 5 m. What are the two approximate times that the object will be located at the height of 10 m above the ground? 0 = ½ at 2 +v i t – x so, a = ½ a = ½ * m/s 2 = -4.9 m/s b = v i = 15 m/s c = -x = -10 m tt = 0.5 sec and 1 sec

Plugging in Numbers Sometimes, you can just plug in numbers into the equation to find the solution. Works best with multiple choice.

Plugging in Numbers Sometimes, you can just plug in numbers into the equation to find the solution. Works best with multiple choice. Example – WE DO A car and truck start from the same position. The car has a constant velocity of 20 m/s. The truck has an initial velocity of zero, but accelerates 3 m/s. At approximately what time does the truck overtake the car? A. 6.6 s B s C s D S

Plugging in Numbers Sometimes, you can just plug in numbers into the equation to find the solution. Works best with multiple choice. Example – WE DO A car and truck start from the same position. The car has a constant velocity of 20 m/s. The truck has an initial velocity of zero, but accelerates 3 m/s. At approximately what time does the truck overtake the car? A. 6.6 s B s C s D S Use x = v i t + ½ at 2 for each car and compare x. At which answer choice does the truck final reach the car?

Plugging in Numbers Sometimes, you can just plug in numbers into the equation to find the solution. Works best with multiple choice. Example – WE DO A car and truck start from the same position. The car has a constant velocity of 20 m/s. The truck has an initial velocity of zero, but accelerates 3 m/s. At approximately what time does the truck overtake the car? A. 6.6 s B s C s D S Use x = v i t + ½ at 2 for each car and compare x. At which answer choice does the truck final reach the car?

Quadratic Equation – You do A ball is dropped from 15 ft. At what time will the ball be 5 ft from the ground? Car 1 and Car 2 start at the same position. Car 1 has an initial velocity of 10 m/s and an acceleration of 5 m/s 2. Car 2 has an initial velocity of 15 m/s and an acceleration of 2 m/s 2. At one time will car 2 overtake car one? A. 1.2 sec B. 2.5s C. 3.4 s D. 4.2 s

Exit ticket & Homework Exit ticket: write facts about circular motion Homework: Circular acceleration problems Review problems Extra credit: Write 3 challenging physics problems and solve them on another sheet of paper. Upcoming: CFA Wed / Thur next week. Exam right after break.