Basic Laws Instructor: Chia-Ming Tsai Electronics Engineering National Chiao Tung University Hsinchu, Taiwan, R.O.C.
Contents Ohm’s Law (resistors) Nodes, Branches, and Loops Kirchhoff’s Laws Series Resistors and Voltage Division Parallel Resistors and Current Division Wye-Delta Transformations Applications
Ohm’s Law Resistance R is represented by R v +_+_ i 1 = 1 V/A Cross-section area A Meterial resistivity ohm
Resistors R = 0 v = 0 +_+_ i R = v +_+_ i = 0 Variable resistorPotentiometer (pot) Open circuitShort circuit
Nonlinear Resistors i v Slope = R v i Slope = R(i) or R(v) Linear resistorNonlinear resistor Examples: lightbulb, diodes All resistors exhibit nonlinear behavior.
Conductance and Power Dissipation Conductance G is represented by 1 S = 1 = 1 A/V siemens mho A positive R results in power absorption. A negative R results in power generation.
Nodes, Branches, & Loops Brach: a single element (R, C, L, v, i) Node: a point of connection between braches (a, b, c) Loop: a closed path in a circuit (abca, bcb, etc) –A independent loop contains at least one branch which is not included in other indep. loops. –Independent loops result in independent sets of equations. + _ a c b + _ c ba redrawn
Continued Elements in parallelElements in series –(10V, 5 ) Elements in parallel –(2 , 3 , 2A) Neither –((5 /10V), (2 /3 /2A)) 10V 55 22 33 2A2A + _
Kirchhoff’s Laws Introduced in 1847 by German physicist G. R. Kirchhoff ( ). Combined with Ohm’s law, we have a powerful set of tools for analyzing circuits. Two laws included, Kirchhoff’s current law (KCL) and Kirchhoff’s votage law (KVL)
Kirchhoff’s Current Law (KCL) i1i1 i2i2 inin Assumptions –The law of conservation of charge –The algebraic sum of charges within a system cannot change. Statement –The algebraic sum of currents entering a node (or a closed boundary) is zero.
Proof of KCL
Example 1 i1i1 i3i3 i2i2 i4i4 i5i5
Example 2 I1I1 I2I2 I3I3 ITIT ITIT
Case with A Closed Boundary Treat the surface as a node
Kirchhoff’s Voltage Law (KVL) Statement –The algebraic sum of all voltages around a closed path (or loop) is zero. v1v1 + _ v2v2 + _ vmvm + _
Example 1 v4v4 v1v1 v5v5 + _ + _ + _ v2v2 + _ v3v3 + _ Sum of voltage drops = Sum of voltage rises
Example 2 V3V3 V2V2 V1V1 V ab + _ + _ + _ + _ a b + _ + _ a b
Example 3 Q: Find v 1 and v 2. Sol: v1v1 + _ v2v2 + _ 20V 22 33 + _ i
Example 4 Q: Find currents and voltages. Sol: v1v1 + _ 30V 88 33 + _ i1i1 66 + _ v3v3 i3i3 i2i2 Loop 1Loop 2 a + _ v2v2 b
Series Resistors v1v1 + _ v R1R1 + _ i v2v2 + _ R2R2 a b v + _ i v + _ R eq a b
Voltage Division v1v1 + _ v R1R1 + _ i v2v2 + _ R2R2 a b v + _ i v + _ R eq a b
Continued v + _ i v + _ R eq a b v1v1 + _ v R1R1 + _ i v2v2 + _ R2R2 a b vNvN + _ RNRN
Parallel Resistors i a b R1R1 + _ R2R2 v i1i1 i2i2 i a b R eq or G eq + _ v v
Current Division i a b R1R1 + _ R2R2 v i1i1 i2i2 i a b R eq or G eq + _ v v
Continued i a b R eq or G eq + _ v v i a b R1R1 + _ R2R2 v i1i1 i2i2 RNRN iNiN
Brief Summary i a b R1R1 +_ R2R2 v i1i1 i2i2 RNRN iNiN v1v1 + _ v R1R1 + _ i v2v2 + _ R2R2 a b vNvN + _ RNRN
Example R eq R eq 14.4
How to solve the bridge network? R1R1 +_ vSvS R2R2 R3R3 R4R4 R5R5 R6R6 Resistors are neither in series nor in parallel. Can be simplified by using 3-terminal equivalent networks.
Wye (Y)-Delta ( ) Transformations R3R3 R1R1 R2R R3R3 R1R1 R2R RbRb RcRc RaRa RbRb RcRc RaRa Y T
to Y Conversion R3R3 R1R1 R2R Y RbRb RcRc RaRa
Y- Transformations
Example R ab a b R ab a b 35 R ab a b R ab a b
Applications: Lighting Systems
Applications: DC Meters Parameters: I FS and R m
Continued
Voltmeters Single-range Multiple-range
Ammeters Single-range Multiple-range