Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x 10 -5.

Slides:



Advertisements
Similar presentations
Precipitation Equilibria. Solubility Product Ionic compounds that we have learned are insoluble in water actually do dissolve a tiny amount. We can quantify.
Advertisements

Chapter 19 - Neutralization
Solubility Products Consider the equilibrium that exists in a saturated solution of BaSO 4 in water: BaSO 4 (s) Ba 2+ (aq) + SO 4 2− (aq)
Aqueous Equilibria Entry Task: Feb 28 th Thursday Question: Provide the K sp expression for calcium phosphate, K sp = 2.0 x From this expression,
Lecture 71/31/07. Solubility vs. Solubility constant (K sp ) What is the difference? BaSO 4 (s) ⇄ Ba 2+ (aq) + SO 4 2- (aq) Ba 2+ (aq) + SO 4 2- (aq)
Solubility. Solubility “Insoluble” salts are governed by equilibrium reactions, and are really sparingly soluble. There is a dynamic equilibrium between.
The Solubility Product Principle. 2 Silver chloride, AgCl,is rather insoluble in water. Careful experiments show that if solid AgCl is placed in pure.
The K sp of chromium (III) iodate in water is 5.0 x Estimate the molar solubility of the compound. Cr(IO 3 ) 3 (s)  Cr 3+ (aq) + 3 IO 3 - (aq)
Chapter 17 SOLUBILITY EQUILIBRIA (Part II) 1Dr. Al-Saadi.
PRECIPITATION REACTIONS Chapter 19 Copyright © 1999 by Harcourt Brace & Company All rights reserved. Requests for permission to make copies of any part.
Lecture 72/1/06. Precipitation reactions What are they? Solubility?
1 Salt Solubility Chapter Solubility product constant K sp K sp Unitless Unitless CaF 2(s)  Ca 2+ (aq) + 2F - (aq) CaF 2(s)  Ca 2+ (aq) + 2F -
Solubility Product Constant
Solubility Equilibrium In saturated solutions dynamic equilibrium exists between undissolved solids and ionic species in solutions Solids continue to dissolve.
Solubility Product Constant
Unless otherwise stated, all images in this file have been reproduced from: Blackman, Bottle, Schmid, Mocerino and Wille, Chemistry, 2007 (John Wiley)
Solubility Equilibria. Write solubility product (K sp ) expressions from balanced chemical equations for salts with low solubility. Solve problems involving.
PRECIPITATION REACTIONS Chapter 17 Part 2 2 Insoluble Chlorides All salts formed in this experiment are said to be INSOLUBLE and form precipitates when.
Ksp and Solubility Equilibria
Chapter 16 Lesson 1 Solubility and Complex Ion Equilibria.
Solubility Allows us to flavor foods -- salt & sugar. Solubility of tooth enamel in acids. Allows use of toxic barium sulfate for intestinal x-rays.
Solubility Lesson 8 Titrations & Max Ion Concentration.
Chapter 18 The Solubility Product Constant. Review Quiz Nuclear Chemistry Thermochemistry –Hess’s Law –Heats (Enthalpies) of…
Solubility Lesson 8 Review Notes. Adding a Crystal to a Saturated Solution Consider the saturated solution Cl - Ag +
Aqueous Equilibria Entry Task: Feb 17 th Wednesday Notes on Precipitate and ions HW: Precipitate and ions ws MAYHAN.
Solubility Chapter 17. No only do acids and bases dissolve in aqueous solutions but so do ionic compounds –Many ionic compounds tend to be strong electrolytes.
Chapter 17 sections 4-7 Solubility Equilibria © 2012 Pearson Education, Inc.
Solubility Equilibrium Chapter 10. What happens to an insoluble salt when it is added to some water? What would you see? What does it mean to be “insoluble”?
Unit 17. Dissolution: the process in which an ionic solid dissolves in a polar liquid. AgCl (s) ↔ Ag + (aq) + Cl - (aq) Precipitation: the process in.
Solutions and Equilibrium. Heterogeneous Equilibrium Reaction occurs in more than one phase K EQ = Products Reactants Solids and liquids are not included.
Which of the following solubility product expressions is incorrect?
Chemistry 1011 Slot 51 Chemistry 1011 TOPIC Solubility Equilibrium TEXT REFERENCE Masterton and Hurley Chapter 16.1.
Solubility Rules. The terms soluble and insoluble are relative terms. soluble insoluble solute Solubility: the maximum amount of solute needed to make.
Solubility Equilibrium Solubility Product Constant Ionic compounds (salts) differ in their solubilities Most “insoluble” salts will actually dissolve.
1 PRECIPITATION REACTIONS Solubility of Salts Section 18.4.
Solubility Lesson 6 Changing solubility/Common Ion Effect.
Chapter 17 Acids, Bases and Buffers. Overview strong acid : strong base strong acid : weak base weak acid : strong base weak acid : weak base common ion.
Philip Dutton University of Windsor, Canada N9B 3P4 Prentice-Hall © 2002 General Chemistry Principles and Modern Applications Petrucci Harwood Herring.
DO NOW: What is dissolution. What is precipitation
…concentrations are ________ constant …forward and reverse rates are ________ equal At Equilibrium…
11 ANALYTICAL CHEMISTRY Chem. 243 Chapter 7 Precipitation Titration.
Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x
CHE1102, Chapter 17 Learn, 1 Chapter 17 Solubility and Simultaneous Equilibria.
Solubility and Complexation Equilibria Chapter 18.
1 PRECIPITATION REACTIONS Solubility of Salts Section 18.4.
E 12 Water and Soil Solve problems relating to removal of heavy –metal ions and phosphates by chemical precipitation
Solubility Equilibria.  Write a balanced chemical equation to represent equilibrium in a saturated solution.  Write a solubility product expression.
If 36.2 mL of M CaCl 2 solution is added to 37.5 mL of M Na 2 CO 3, what mass of calcium carbonate, CaCO 3, will be precipitate? CaCl 2 (aq)
Solubility Constant (Ksp). © 2009, Prentice-Hall, Inc. Solubility of Salts (Ksp) Consider the equilibrium that exists in a saturated solution of BaSO.
Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x
Chapter 16 Solubility Equilibria. Saturated solutions of “insoluble” salts are another type of chemical equilibria. Ionic compounds that are termed “insoluble”
Solubility 1 Saturated Solutions 1.Cannot dissolve any more solute 2.Contain undissolved solid 3.Ex: BaSO 4 BaSO 4 (s)  Ba 2+ (aq) + SO 4 2- (aq) K sp.
Chapter 17 Solubility and Simultaneous Equilibria
Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 Ka for HQ = 3.0 x 10-5.
Solubility and Complexation Equilibria
Solubility Constants: Ksp
Solubility Equilibria
Lesson 6: The Solubility Product
The Solubility Product Constant (Ksp)
Solubility.
Solubility Lesson 5 Trial Ion Product.
Solubility Lesson 8 Titrations & Max Ion Concentration.
Solubility Common Ion Effect.
Solubility Lesson 8 Review Notes.
Solubility Product KSP.
Solubility Lesson 7 Changing solubility.
Solubility Equilibria
Solubility Product Constant
Chem 30: Solubility The Common Ion Effect.
Solubility Product Constant
Presentation transcript:

Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 K a for HQ = 3.0 x 10 -5

Drill: Calculate [H 2 Q], [HQ - ], [Q -2 ], [H + ], & pH of 0.20 M KHQ. Ka 1 = 2.0 x Ka 2 = 8.0 x 10 -9

Solubility

The amount of one substance that will dissolve in another

Precipitation When dissolved particles join together forming a new phase and exit the solution

Precipitate (ppt) The new phase that forms and leaves the solution

Ppt Examples Water vapor combining to form rain Dissolved ions combining to form a solid

Saturated Solution When the maximum amount of one substance is dissolved in another

Precipitation When more than the maximum amount of solute is added to a solution, a ppt will form

Write the equilibrium expression for AgCl (s) Ag + + Cl -

Solubility Product MX (s) M + (aq) + X - (aq) Ksp =[M + ][X - ]

Solubility Product MX 2(s) M +2 (aq) + 2 X - (aq) Ksp =[M +2 ][X - ] 2

Drill: Write the equilibrium expression for: Al 2 (SO 4 ) 3

Drill: Write the reaction & equilibrium expression when solid Fe 2 (SO 4 ) 3 is added to water.

Solubility Calculations

Calculate the solubility of BaSO 4(s) Ksp = 1.2 x

Solubility Product BaSO 4(s) Ba +2 (aq) + SO 4 -2 (aq) Ksp =[Ba +2 ][SO 4 -2 ]

Calculate the solubility of SrCr 2 O 7(s) Ksp = 2.5 x

Calculate the solubility of PbI 2(s) K sp = 8.0 x 10 -9

Calculate the solubility of Mn 2 S 3(s) K sp = 1 x

Drill: Calculate the solubility of M 3 X 4 K sp for M 3 X 4 = 6.9 x

Solubility Concepts AgI (s) Ag + + I - K sp = [Ag + ][I - ] at Eq. Q sp = [Ag + ][I - ] init.

Solubility Concepts If Q sp > K sp a precipitate will form If Q sp < K sp no precipitate will form

150 mL M KI is added to 100 mL M Pb(NO 3 ) 2. K sp for PbI 2 = 8.0 x Will a ppt form?

AP CHM HW Read: Chapter 16 Problem: 13 Page: 463

CHM II HW Read: Chapter 20 Problem: 17 Page: 843

Drill: 10.0 mL M KCl is added to 15 mL M Pb(NO 3 ) 2. K sp = 1.7 x Will a ppt form?

Drill: Calculate the solubility of AgI (s) K sp = 1.5 x

Common Ion Solubility Calculations

Calculate the solubility of AgI (s) in 0.10 M NaI K sp = 1.5 x

Common Ion Effect Solubility of a solid is reduced when one of its ions is already in solution

Calculate the solubility of MZ 2(s) in 0.20 M M(NO 3 ) 2 K sp = 2.0 x

Calculate the solubility of M 2 Z 3(s) in 0.20 M M(NO 3 ) 3 K sp = 2.0 x

AP CHM HW Read: Chapter 16 Problems: 18 Page: 463

CHM II HW Read: Chapter 20 Problems: 19 Page: 844

Drill: Calculate the solubility of CaCO 3 in water. K sp = 4.9 x

Calculate the solubility of PbI 2(s) in M NaI K sp = 3.2 x 10 -8

Aqueous NaI is added (dropwise) to a solution of 0.10 M AgNO 3(s) & 0.10 M CuNO 3 AgI K sp = 1.0 x CuI K sp = 5.1 x

Aqueous KCl is added (dropwise) to a solution of 0.10 M AgNO 3 & 0.10 M Cu(NO 3 ) 2 AgCl K sp = 1.8 x Cu Cl 2 K sp = 5.1 x

Test on Thursday or Friday

Drill: Calculate the solubility of PbS (s) K sp = 1.0 x

Review

Calculate the solubility of PbCl 2(s) K sp = 1.6 x 10 -5

Calculate the solubility of Sc(OH) 3(s) K sp = 2.7 x

Calculate the pH of Ca(OH) 2 in solution. K sp = 4.0 x 10 -6

Calculate the pH of LiCO 3 in soln K sp = 8.2 x K a1 = 4.4 x K a2 = 4.7 x

Calculate the solubility of AgI (s) in 0.20 M NaI K sp = 1.5 x

The solubility of MX 2(s) is 2.0 x M. Calculate its K sp

Aqueous MgCl 2 is added (dropwise) to a solution of 0.10 M KOH & 0.10 M K 2 SO 4 Mg(OH) 2 K sp = 6.0 x Mg SO 4 K sp = 5.6 x 10 -5

Drill: The solubility of YF 3 is 2.0 x Calculate the value of K sp.