CS 61C L2.1.1 Memory Management (1) K. Meinz, Summer 2004 © UCB CS61C : Machine Structures Lecture 2.1.1 Memory Management 2004-06-28 Kurt Meinz inst.eecs.berkeley.edu/~cs61c.

Slides:



Advertisements
Similar presentations
Dynamic Memory Management
Advertisements

The Linux Kernel: Memory Management
Lecture 10: Heap Management CS 540 GMU Spring 2009.
1 Optimizing Malloc and Free Professor Jennifer Rexford COS 217 Reading: Section 8.7 in K&R book
CPSC 388 – Compiler Design and Construction
Chapter 8 Runtime Support. How program structures are implemented in a computer memory? The evolution of programming language design has led to the creation.
Stacks and HeapsCS-3013 A-term A Short Digression on Stacks and Heaps CS-3013 Operating Systems A-term 2008 (Slides include materials from Modern.
CS 61C L07 More Memory Management (1) Garcia, Fall 2004 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C.
CS61C L05 C Structures, Memory Management (1) Garcia, Spring 2005 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c.
CS 61C L06 Memory Management (1) A Carle, Summer 2006 © UCB inst.eecs.berkeley.edu/~cs61c/su06 CS61C : Machine Structures Lecture #6: Memory Management.
Digression on Stack and Heaps CS-502 (EMC) Fall A Short Digression on Stacks and Heaps CS-502, Operating Systems Fall 2009 (EMC) (Slides include.
CS61C L4 C Memory Management (1) Beamer, Summer 2007 © UCB Scott Beamer, Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture #4.
Memory Allocation. Three kinds of memory Fixed memory Stack memory Heap memory.
1 1 Lecture 4 Structure – Array, Records and Alignment Memory- How to allocate memory to speed up operation Structure – Array, Records and Alignment Memory-
CS 536 Spring Run-time organization Lecture 19.
Memory Management Memory Areas and their use Memory Manager Tasks:
CS 61C L06 C Memory Management (1) Garcia, Spring 2004 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C.
CS61C L06 C Memory Management (1) Garcia, Spring 2008 © UCB Lecturer SOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C :
CS61C L06 C Memory Management (1) Garcia, Spring 2007 © UCB Lecturer SOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C :
CS 61C L4 Structs (1) A Carle, Summer 2005 © UCB inst.eecs.berkeley.edu/~cs61c/su05 CS61C : Machine Structures Lecture #4: Strings & Structs
CS61CL L02 Dynamic Storage (1) Huddleston, Summer 2009 © UCB Jeremy Huddleston inst.eecs.berkeley.edu/~cs61c CS61CL : Machine Structures Lecture #3 -
CS61C L06 C Memory Management (1) Garcia, Spring 2005 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C.
CS61C L06 C Memory Management (1) Garcia, Fall 2006 © UCB Lecturer SOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C : Machine.
1 Inner Workings of Malloc and Free Professor Jennifer Rexford COS 217.
CS61C L5 Memory Management; Intro MIPS (1) Beamer, Summer 2007 © UCB Scott Beamer, Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures.
CS61C Midterm Review on C & Memory Management Fall 2006 Aaron Staley Some material taken from slides by: Michael Le Navtej Sadhal.
CS 61C L06 C Memory Management (1) Garcia, Fall 2004 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C :
CS 61C L04 C Structures, Memory Management (1) Garcia, Fall 2004 © UCB Lecturer PSOE Dan Garcia inst.eecs.berkeley.edu/~cs61c.
CS61C L07 More Memory Management (1) Garcia, Spring 2008 © UCB Lecturer SOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C.
CS61C L4 C Pointers (1) Chae, Summer 2008 © UCB Albert Chae Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture #4 –C Strings,
Memory Allocation CS Introduction to Operating Systems.
The memory allocation problem Define the memory allocation problem Memory organization and memory allocation schemes.
COP4020 Programming Languages
Operating System Chapter 7. Memory Management Lynn Choi School of Electrical Engineering.
CS61C L05 C Memory Management (1) Pearce, Summer 2010 © UCB inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture 5 – C Memory Management
CS 61C L2.1.2 MM and MIPS (1) K. Meinz, Summer 2004 © UCB CS61C : Machine Structures Lecture Garbage Collection & Intro to MIPS Kurt Meinz.
Dynamic Memory Allocation Questions answered in this lecture: When is a stack appropriate? When is a heap? What are best-fit, first-fit, worst-fit, and.
CS 11 C track: lecture 5 Last week: pointers This week: Pointer arithmetic Arrays and pointers Dynamic memory allocation The stack and the heap.
Heap Management. What is really stored on the heap? Housekeeping Users Data Buffer Next Block Data Housekeeping 0x7000 0x7008 int main() { int *x,*y;
University of Washington Today Finished up virtual memory On to memory allocation Lab 3 grades up HW 4 up later today. Lab 5 out (this afternoon): time.
CS 326 Programming Languages, Concepts and Implementation Instructor: Mircea Nicolescu Lecture 9.
Chapter 17 Free-Space Management Chien-Chung Shen CIS, UD
Operating Systems ECE344 Ashvin Goel ECE University of Toronto Memory Management Overview.
CS61C L5 Memory Management; Intro MIPS (1) Garcia, Fall 2005 © UCB Lecturer PSOE, new dad Dan Garcia inst.eecs.berkeley.edu/~cs61c.
1 Lecture07: Memory Model 5/2/2012 Slides modified from Yin Lou, Cornell CS2022: Introduction to C.
LECTURE 13 Names, Scopes, and Bindings: Memory Management Schemes.
CS 241 Discussion Section (12/1/2011). Tradeoffs When do you: – Expand Increase total memory usage – Split Make smaller chunks (avoid internal fragmentation)
Dynamic Memory Management Jennifer Rexford 1. 2 Goals of this Lecture Dynamic memory management techniques Garbage collection by the run-time system (Java)
CS61C L07 More Memory Management (1) Garcia, Spring 2010 © UCB Lecturer SOE Dan Garcia inst.eecs.berkeley.edu/~cs61c CS61C.
CS61C L05 C Memory Management (1) Chae, Summer 2008 © UCB Albert Chae Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture 5 – C.
Chapter 17 Free-Space Management
Storage Allocation Mechanisms
Memory Management Memory Areas and their use Memory Manager Tasks:
CS 326 Programming Languages, Concepts and Implementation
Inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture 7 – More Memory Management Lecturer PSOE Dan Garcia
Dynamic Memory Allocation
Run-time organization
Memory Management Memory Areas and their use Memory Manager Tasks:
The Hardware/Software Interface CSE351 Winter 2013
Optimizing Malloc and Free
CS Introduction to Operating Systems
Lecturer SOE Dan Garcia
Memory Allocation CS 217.
Memory Management Overview
There is one handout today at the front and back of the room!
Operating System Chapter 7. Memory Management
Lecturer PSOE Dan Garcia
Memory Management Memory Areas and their use Memory Manager Tasks:
Inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture 7 – More Memory Management Lecturer PSOE Dan Garcia
Topic 2b ISA Support for High-Level Languages
Presentation transcript:

CS 61C L2.1.1 Memory Management (1) K. Meinz, Summer 2004 © UCB CS61C : Machine Structures Lecture Memory Management Kurt Meinz inst.eecs.berkeley.edu/~cs61c

CS 61C L2.1.1 Memory Management (2) K. Meinz, Summer 2004 © UCB Memory Management (1/2) Variable declaration allocates memory outside a procedure -> static storage inside procedure -> stack -freed when procedure returns. Malloc request Pointer: static or stack Content: on heap int myGlobal; main() { int myTemp; int *f= malloc(16); }

CS 61C L2.1.1 Memory Management (3) K. Meinz, Summer 2004 © UCB Memory Management (2/2) A program’s address space contains 4 regions: stack: proc frames, grows downward heap: space requested for pointers via malloc() ; resizes dynamically, grows upward static data: variables declared outside main, does not grow or shrink code: loaded when program starts, does not change code static data heap stack For now, OS somehow prevents accesses between stack and heap (gray hash lines). Wait for virtual memory ~ FFFF FFFF hex ~ 0 hex

CS 61C L2.1.1 Memory Management (4) K. Meinz, Summer 2004 © UCB The Stack (1/4) Environment frames from 61a  Really exist in memory Laid out using stack structure from 61b Terminology: Stack is composed of frames A frame corresponds to one procedure invocation Stack frame includes: -Return address of caller -Space for other local variables frame $SP

CS 61C L2.1.1 Memory Management (5) K. Meinz, Summer 2004 © UCB The Stack (2/4) Implementation: By convention, stack grows down in memory. Stack pointer ($SP) points to next available address PUSH: On invocation, callee moves $SP down to create new frame to hold callee’s local variables and RA -(old SP – new SP)  size of frame POP: On return, callee moves $SP back to original, returns to caller frame $SP

CS 61C L2.1.1 Memory Management (6) K. Meinz, Summer 2004 © UCB The Stack (3/4) Last In, First Out (LIFO) memory usage main () { a(0); } void a (int m) { b(1); } void b (int n) { c(2); } void c (int o) { d(3); } void d (int p) { } stack Stack Pointer

CS 61C L2.1.1 Memory Management (7) K. Meinz, Summer 2004 © UCB Pointers in C allow access to deallocated memory, leading to hard-to-find bugs ! int *ptr () { int y; y = 3; return &y; } main () { int *stackAddr; stackAddr = ptr(); printf("%d", *stackAddr); /* 3 */ printf("%d", *stackAddr); /* XXX */ } The Stack (4/4): Dangling Pointers main ptr() (y==3) SP main SP main printf() (y==?) SP

CS 61C L2.1.1 Memory Management (8) K. Meinz, Summer 2004 © UCB Static and Code Segments Code (Text Segment) Holds instructions to be executed Constant size Static Segment Holds global variables whose addresses are known at compile time -Cf. Heap (malloc calls) where address isn’t known

CS 61C L2.1.1 Memory Management (9) K. Meinz, Summer 2004 © UCB The Heap (Dynamic memory) Large pool of memory, not allocated in contiguous order back-to-back requests for heap memory could result blocks very far apart where Java new command allocates memory In C, specify number of bytes of memory explicitly to allocate item int *ptr; ptr = (int *) malloc(4); /* malloc returns type (void *), so need to cast to right type */ malloc() : Allocates raw, uninitialized memory from heap

CS 61C L2.1.1 Memory Management (10) K. Meinz, Summer 2004 © UCB Memory Management How do we manage memory? Code, Static storage are easy: they never grow or shrink Stack space is also easy: stack frames are created and destroyed in last-in, first-out (LIFO) order Managing the heap is tricky: memory can be allocated / deallocated at any time

CS 61C L2.1.1 Memory Management (11) K. Meinz, Summer 2004 © UCB Heap Management Requirements Want malloc() and free() to run quickly. Want minimal memory overhead Want to avoid fragmentation – when most of our free memory is in many small chunks In this case, we might have many free bytes but not be able to satisfy a large request since the free bytes are not contiguous in memory.

CS 61C L2.1.1 Memory Management (12) K. Meinz, Summer 2004 © UCB Heap Management An example Request R1 for 100 bytes Request R2 for 1 byte Memory from R1 is freed Request R3 for 50 bytes R2 (1 byte) R1 (100 bytes)

CS 61C L2.1.1 Memory Management (13) K. Meinz, Summer 2004 © UCB Heap Management An example Request R1 for 100 bytes Request R2 for 1 byte Memory from R1 is freed Request R3 for 50 bytes R2 (1 byte) R3?

CS 61C L2.1.1 Memory Management (14) K. Meinz, Summer 2004 © UCB K&R Malloc/Free Implementation From Section 8.7 of K&R Code in the book uses some C language features we haven’t discussed and is written in a very terse style, don’t worry if you can’t decipher the code Each block of memory is preceded by a header that has two fields: size of the block and a pointer to the next block All free blocks are kept in a linked list, the pointer field is unused in an allocated block

CS 61C L2.1.1 Memory Management (15) K. Meinz, Summer 2004 © UCB K&R Implementation malloc() searches the free list for a block that is big enough. If none is found, more memory is requested from the operating system. free() checks if the blocks adjacent to the freed block are also free If so, adjacent free blocks are merged (coalesced) into a single, larger free block Otherwise, the freed block is just added to the free list

CS 61C L2.1.1 Memory Management (16) K. Meinz, Summer 2004 © UCB Choosing a block in malloc() If there are multiple free blocks of memory that are big enough for some request, how do we choose which one to use? best-fit: choose the smallest block that is big enough for the request first-fit: choose the first block we see that is big enough next-fit: like first-fit but remember where we finished searching and resume searching from there

CS 61C L2.1.1 Memory Management (17) K. Meinz, Summer 2004 © UCB Tradeoffs of allocation policies Best-fit: Tries to limit fragmentation but at the cost of time (must examine all free blocks for each malloc). Leaves lots of small blocks (why?) First-fit: Quicker than best-fit (why?) but potentially more fragmentation. Tends to concentrate small blocks at the beginning of the free list (why?) Next-fit: Does not concentrate small blocks at front like first-fit, should be faster as a result.

CS 61C L2.1.1 Memory Management (18) K. Meinz, Summer 2004 © UCB Administrivia (1/2) HW Grading: Submit by 8pm Sundays Solutions on Monday Graded by Tuesday Lecture Sign up for f2f in lab -<40/100: 30 Minutes -<90/100: 15 Minutes -Bring paper copy and understanding of what you got wrong. -Reader will give you points for your demonstration of better understanding/effort. (up to 90/100)

CS 61C L2.1.1 Memory Management (19) K. Meinz, Summer 2004 © UCB Administrivia (2/2) Projects will be similar No cheating the system! You have to earn the points back. Getting points back is dependent on you trying on the initial submission. -If you submit garbage thinking that you’ll get all the points back in f2f, you are wrong! Office Hours 1- 2pm I House

CS 61C L2.1.1 Memory Management (20) K. Meinz, Summer 2004 © UCB Slab Allocator A different approach to memory management (used in GNU libc ) Divide blocks in to “large” and “small” by picking an arbitrary threshold size. Blocks larger than this threshold are managed with a freelist (as before). For small blocks, allocate blocks in sizes that are powers of 2 e.g., if program wants to allocate 20 bytes, actually give it 32 bytes

CS 61C L2.1.1 Memory Management (21) K. Meinz, Summer 2004 © UCB Slab Allocator Bookkeeping for small blocks is relatively easy: just use a bitmap for each range of blocks of the same size Allocating is easy and fast: compute the size of the block to allocate and find a free bit in the corresponding bitmap. Freeing is also easy and fast: figure out which slab the address belongs to and clear the corresponding bit.

CS 61C L2.1.1 Memory Management (22) K. Meinz, Summer 2004 © UCB Slab Allocator 16 byte blocks: 32 byte blocks: 64 byte blocks: 16 byte block bitmap: byte block bitmap: byte block bitmap: 00

CS 61C L2.1.1 Memory Management (23) K. Meinz, Summer 2004 © UCB Slab Allocator Tradeoffs Extremely fast for small blocks. Slower for large blocks But presumably the program will take more time to do something with a large block so the overhead is not as critical. Minimal space overhead No fragmentation (as we defined it before) for small blocks, but still have wasted space!

CS 61C L2.1.1 Memory Management (24) K. Meinz, Summer 2004 © UCB Internal vs. External Fragmentation With the slab allocator, difference between requested size and next power of 2 is wasted e.g., if program wants to allocate 20 bytes and we give it a 32 byte block, 12 bytes are unused. We also refer to this as fragmentation, but call it internal fragmentation since the wasted space is actually within an allocated block. External fragmentation: wasted space between allocated blocks.

CS 61C L2.1.1 Memory Management (25) K. Meinz, Summer 2004 © UCB Buddy System Yet another memory management technique (used in Linux kernel) Like GNU’s “slab allocator”, but only allocate blocks in sizes that are powers of 2 (internal fragmentation is possible) Keep separate free lists for each size e.g., separate free lists for 16 byte, 32 byte, 64 byte blocks, etc.

CS 61C L2.1.1 Memory Management (26) K. Meinz, Summer 2004 © UCB Buddy System If no free block of size n is available, find a block of size 2n and split it in to two blocks of size n When a block of size n is freed, if its neighbor of size n is also free, combine the blocks in to a single block of size 2n Buddy is block in other half larger block Same speed advantages as slab allocator buddiesNOT buddies

CS 61C L2.1.1 Memory Management (27) K. Meinz, Summer 2004 © UCB Allocation Schemes So which memory management scheme (K&R, slab, buddy) is best? There is no single best approach for every application. Different applications have different allocation / deallocation patterns. A scheme that works well for one application may work poorly for another application.

CS 61C L2.1.1 Memory Management (28) K. Meinz, Summer 2004 © UCB Automatic Memory Management Dynamically allocated memory is difficult to track – why not track it automatically? If we can keep track of what memory is in use, we can reclaim everything else. Unreachable memory is called garbage, the process of reclaiming it is called garbage collection. So how do we track what is in use?

CS 61C L2.1.1 Memory Management (29) K. Meinz, Summer 2004 © UCB Tracking Memory Usage Techniques depend heavily on the programming language and rely on help from the compiler. Start with all pointers in global variables and local variables (root set). Recursively examine dynamically allocated objects we see a pointer to. We can do this in constant space by reversing the pointers on the way down How do we recursively find pointers in dynamically allocated memory?

CS 61C L2.1.1 Memory Management (30) K. Meinz, Summer 2004 © UCB Tracking Memory Usage Again, it depends heavily on the programming language and compiler. Could have only a single type of dynamically allocated object in memory E.g., simple Lisp/Scheme system with only cons cells (61A’s Scheme not “simple”) Could use a strongly typed language (e.g., Java) Don’t allow conversion (casting) between arbitrary types. C/C++ are not strongly typed. Here are 3 schemes to collect garbage

CS 61C L2.1.1 Memory Management (31) K. Meinz, Summer 2004 © UCB Bonus Slides The following material wasn’t covered in lecture, but I leave it here for your enjoyment.

CS 61C L2.1.1 Memory Management (32) K. Meinz, Summer 2004 © UCB Intel 80x86 C Memory Management A C program’s 80x86 address space : heap: space requested for pointers via malloc() ; resizes dynamically, grows upward static data: variables declared outside main, does not grow or shrink code: loaded when program starts, does not change stack: local variables, grows downward code static data heap stack ~ hex

CS 61C L2.1.1 Memory Management (33) K. Meinz, Summer 2004 © UCB Linked List Example Let’s look at an example of using structures, pointers, malloc(), and free() to implement a linked list of strings. struct Node { char *value; struct Node *next; }; typedef Node *List; /* Create a new (empty) list */ List ListNew(void) { return NULL; }

CS 61C L2.1.1 Memory Management (34) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } list: string: “abc” …… NULL

CS 61C L2.1.1 Memory Management (35) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } node: list: string: “abc” …… NULL ? ?

CS 61C L2.1.1 Memory Management (36) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } node: list: string: “abc” …… NULL ? “????”

CS 61C L2.1.1 Memory Management (37) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } node: list: string: “abc” …… NULL ? “abc”

CS 61C L2.1.1 Memory Management (38) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } node: list: string: “abc” …… NULL “abc”

CS 61C L2.1.1 Memory Management (39) K. Meinz, Summer 2004 © UCB Linked List Example /* add a string to an existing list */ List list_add(List list, char *string) { struct Node *node = (struct Node*) malloc(sizeof(struct Node)); node->value = (char*) malloc(strlen(string) + 1); strcpy(node->value, string); node->next = list; return node; } node: …… NULL “abc”