Application of QuickField Software to Heat Transfer Problems i j k By Dr. Evgeni Volpov
Basic Formulations for GIS HT model Boundary Conditions 1. T(S) = T 0 Const Temperature T(S) = T 0 + k.S Linear Temp. T(S) = T 0 + k.S Linear Temp. 2. F n = -q s Flux F n (+) - F n (-) = -q s F n (+) - F n (-) = -q s 3. F n = a(T - T 0 ) Convection a - film coefficient T 0 – temperature of contacting medium F n = b.K sb (T 4 - T 0 4 ) Radiation 4. F n = b.K sb (T 4 - T 0 4 ) Radiation K sb - Stephan-Boltzmann constant; b - emissivity coefficient Classical Heat Transfer Equations
Boundary conditions & domain characterization Volume element Surface element Point-Source element
Joule losses distribution at central conductor 1000 A 1920 W/m W/m 3 Electric Field distribution in GIS compartment 100 kV AC enclosure 2.3 MV/m epoxy spacer 53 C 31 C HV conductor current 1000 A P SF6 = 0.6 MPa Air Spacer deformation under SF6 pressure epoxy spacer enclosure Coupling Problems solution for SF6 GIS 170 kV Thermo-static field mapping in GIS compartment
SF6 GIS HT Model Parameters 1. SF6 Thermal Conductivity g = W/m.K 2. Air Thermal Conductivity a = W/m.K 3. Epoxy Thermal Conductivity e ( ) W/m.K 4. Aluminum Thermal Conductivity al ( ) W/m.K 5. Copper Thermal Conductivity cu = 380 W/m.K 6. Convection Parameters: 6.1. Internal SF6 space: k = 0.133(Gr.Pr) 0.28 ( ) 10 3 < Gr.Pr < 10 6 (for SF6 GIS) 6.2. External Air space: a c (2-10) W/K.m 2 ; T 0 (20-25 C) 7. Radiation Parameters: equivalent emissivity coefficient : b e ( )
GIS Geometric Model examples Symmetry Axis Air layer (a) L L (b) Hot-spot
- r - r r - Z r - Z Geometric Models & results presentation
Thermal Field mapping for BB model 1.2 m T 0 (ambient) = 20 C 28.8 C28.8 C29.8 C 64 C60.1 C 64 C54.0 C 28.1 C29.7 C Conductivity only 23.0 C23.8 C 64 C63.0 C 1.2 m1.2 m Hot-spot Flange 1000 A Conductivity + convection Conductivity + convection+ radiation
29.1 C31.0 C 64 C54.1 C 23.1 C23.9 C 64 C62.6 C 26.8 C29.5 C 64 C43.0 C 2.3 m Conductivity + convection Conductivity + convection+ radiation Conductivity only Flange T 0 (ambient) = 20 C 1000 A Thermal Field mapping for BB model 2.3 m Hot-spot
T max C T C BB length 2 m BB length 1 m Including radiation Enclosure overheating as a function of Hot-spot temperature Hot-spot temperature Temperature drop along the enclosure
L [m] Max temperature on the enclosure Enclosure length T max C 50 kW/m kW/m 3 Specific Joule loss in the damaged contact R = 100 I = 1000 A V = 1000 cm 3 Enclosure temperature with no damaged contact T 0 (ambient) = 20 C Enclosure overheating as a function of the BB length Conductivity + convection Conductivity + convection+ radiation
T C 3 sec 2.3 m Q 2 = 2 kW/m 3 Q 1 = 100 kW/m 3 HT Transients for BB model g k = 0.10 Conductivity + convection Steady State distribution Initial distribution 1000 A 0 A T 0 (ambient) = 20 C