Scientific & Chemical Fundamentals Applications: Precision & Accuracy Density Dr. Ron Rusay © Copyright 2003-2010 R.J. Rusay Refer to Lab Manual & Worksheets.

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Scientific & Chemical Fundamentals Applications: Precision & Accuracy Density Dr. Ron Rusay © Copyright R.J. Rusay Refer to Lab Manual & Worksheets

Precision QUESTION: Rank the images from best to worst precision. A) a > b > c B) b > c > a C) c > a > b D) c > b > a A) a > b > c B) b > c > a C) c > a > b D) c > b > a

Precision Answer: Rank the images from best to worst precision. A) a > b > c B) b > c > a C) c > a > b D) c > b > a A) a > b > c B) b > c > a C) c > a > b D) c > b > a

Accuracy QUESTION: Rank the images from best to worst accuracy. A) a > b > c B) b > c > a C) c > a > b D) c > b > a A) a > b > c B) b > c > a C) c > a > b D) c > b > a

Accuracy Answer: Rank the images from best to worst accuracy. A) a > b > c B) b > c > a C) c > a > b D) c > b > a A) a > b > c B) b > c > a C) c > a > b D) c > b > a

QUESTION Two Chem 120 students are each drinking a can of cranberry juice after class. The printed label indicates that the respective volume of both containers is 375 milliliters. Euna remarks that the Federal Trade Commision (FTC) requires bottlers to be very precise. Mike correctly responded: A. If precision were the only requirement, bottlers could claim any volume as long as it was always very nearly the same volume. B.Since precision is a requirement, bottlers have to get exactly 375 mL in every can. C.Bottlers must have a precise average of all of the containers in a case of soft drinks equal to 375 mL. D. If there were a difference of no more than +/- 1 mL between containers, the bottlers can sell their beverage.

Answer Two Chem 120 students are each drinking a can of cranberry juice after class. The printed label indicates that the respective volume of both containers is 375 milliliters. Euna remarks that the Federal Trade Commision (FTC) requires bottlers to be very precise. Mike correctly responded: A. If precision were the only requirement, bottlers could claim any volume as long as it was always very nearly the same volume. B.Since precision is a requirement, bottlers have to get exactly 375 mL in every can. C.Bottlers must have a precise average of all of the containers in a case of soft drinks equal to 375 mL. D. If there were a difference of no more than +/- 1 mL between containers, the bottlers can sell their beverage.

The melting point of pure benzoic acid is 122°C. Data obtained by four students in a laboratory experiment are shown below. Which student’s data are precise but not accurate? Student AStudent BStudent CStudent D 115°C119°C122°C118°C 112°C118°C121°C120°C 118°C119°C122°C 124°C 116°C120°C121°C126°C A) Student AB) Student B A) Student AB) Student B C) Student CD) Student D C) Student CD) Student D QUESTION

The melting point of pure benzoic acid is 122°C. Data obtained by four students in a laboratory experiment are shown below. Which student’s data are precise but not accurate? Student AStudent BStudent CStudent D 115°C119°C122°C118°C 112°C118°C121°C120°C 118°C119°C122°C 124°C 116°C120°C121°C126°C A) Student AB) Student B A) Student AB) Student B C) Student CD) Student D C) Student CD) Student D Answer

Precision & Accuracy (The Following Measured Data is for Volume in mL)

Precision (Average Deviation vs. Standard Deviation) The distribution of data (individual data points) in a set is not considered by the Average Deviation. Standard Deviation, which relative to its average (mean), is commonly used to do this. The distribution of data (individual data points) in a set is not considered by the Average Deviation. Standard Deviation, which is the square root of the data set’s variance relative to its average (mean), is commonly used to do this.square root variance

Precision (Standard Deviation) Standard Deviation relative to its average (mean). Mathematically: Standard Deviation is the square root of the data set’s variance relative to its average (mean). Mathematically:square root variance Where σ is the data’s average (mean), N is the total number of data points, and x i is the individual data point. Where σ is the Standard Deviation, μ is the data’s average (mean), N is the total number of data points, and x i is the individual data point.

Precision & Accuracy Provide the Standard Deviation (The Following Measured Data is for Volume in mL) Standard deviation +/ / / /- 0.57(Avg. Dev)+/- 0.03(Avg. Dev)+/- 0.04

QUESTION A) Precision: a > c > bB) Precision: b > c > a C) Precision: a = b > cD) Precision: a > b > c Average a)b)c) Standard deviation a)b)c) +/ / / Rank the relative precision of the three sets of data: a), b) and c). The accepted value is 8.08 mL. Answer:

QUESTION A) Accuracy: a > c > bB) Accuracy: b > c > a C) Accuracy: c > a = b D) Accuracy: a = b > c Average a)b)c) Standard deviation a)b)c) +/ / / Rank the relative accuracy of the three sets of data: a), b) and c). The accepted value is 8.08 mL. Answer:

Density Density = Mass / Volume [g/mL or g/cm 3 ; g/L] Refer to Lab Manual/Worksheets Densest known substance: a White Dwarf teaspoon = 3.0 T (metric tons); Calculate its density: D = ? g/cm 3 (1 tsp = 4.93 mL; 1 mL = 1 cm 3 ; 1 metric ton = 1,000 kg ) D = 610,000 g/cm 3 ( 6.1 x 10 5 g/cm 3 ) © Copyright R.J. Rusay

Density Density = Mass / Volume [g/mL or g/cm 3 ; g/L] Refer to Lab Manual/Worksheets Least dense man-made solid substance: Aerogel PS 277 has a volume of ~220 yd 3. When filled with Aerogel, the total weight of Aerogel is ~ 1100 lbs. What is the density of Aerogel? D = ? g/cm 3 D = 3.0 x g/cm 3 ) © Copyright R.J. Rusay

A metal sample is hammered into a rectangular sheet with an area of 31.2 ft 2 and an average thickness of 2.30 × 10 −6 cm. If the mass of this sample is g, predict the identity of the metal. The density of the metal is shown in parenthesis. Useful information: 1 in = 2.54 cm A) Aluminum (2.70 g/cm 3 )B) Copper (8.95 g/cm 3 ) A) Aluminum (2.70 g/cm 3 )B) Copper (8.95 g/cm 3 ) C) Gold (19.3 g/cm 3 )D) Zinc (7.15 g/cm 3 ) C) Gold (19.3 g/cm 3 )D) Zinc (7.15 g/cm 3 ) QUESTION

A metal sample is hammered into a rectangular sheet with an area of 31.2 ft 2 and an average thickness of 2.30 × 10 −6 cm. If the mass of this sample is g, predict the identity of the metal. The density of the metal is shown in parenthesis. Useful information: 1 in = 2.54 cm A) Aluminum (2.70 g/cm 3 )B) Copper (8.95 g/cm 3 ) A) Aluminum (2.70 g/cm 3 )B) Copper (8.95 g/cm 3 ) C) Gold (19.3 g/cm 3 )D) Zinc (7.15 g/cm 3 ) C) Gold (19.3 g/cm 3 )D) Zinc (7.15 g/cm 3 ) Answer

Densities of Various Common Substances* at 20° C

Density Density = Mass / Volume [g/mL or g/cm 3 ; g/L] Refer to Lab Manual/Worksheets How many pounds of air are there in PS 277? It has a volume of ~220 yd 3. D air = 1.22 x g/cm 3 (1.22 g/L) Mass = Density x Volume Mass = 450 lbs © Copyright R.J. Rusay

QUESTION Which would provide more grams of NaCl, sample one with a mass of 2,350 mg, or sample two, a solid with a volume of 2.00 cm 3 ? (The density of solid salt is 2.16 g/cm 3.) Select the most massive sample and its mass in grams. A. Sample two; 1.08 grams B. Sample two; 4.32 grams C. Sample one; 2.35 grams D. Sample one; grams

Answer Which would provide more grams of NaCl, sample one with a mass of 2,350 mg, or sample two, a solid with a volume of 2.00 cm 3 ? (The density of solid salt is 2.16 g/cm 3.) Select the most massive sample and its mass in grams. A. Sample two; 1.08 grams B. Sample two; 4.32 grams C. Sample one; 2.35 grams D. Sample one; grams The mass of sample two is obtained from its density and volume by multiplying 2.00 cm 3 × 2.16 g/cm 3.

QUESTION The volume of any material can be obtained from its density and mass. If the mass of a sample of acid from a battery were 5.00 grams and its density was 1.2 g/mL, what would the correct reported volume in mL with the proper number of significant digits? A.6.0 mL B.6.00 mL C.4.2 mL D.4.17 mL

Answer The volume of any material can be obtained from its density and mass. If the mass of a sample of acid from a battery were 5.00 grams and its density was 1.2 g/mL, what would the correct reported volume in mL with the proper number of significant digits? A.6.0 mL B.6.00 mL C.4.2 mL D.4.17 mL Volume from mass and density is V = m/D. Significant digits in the answer, which involves division in the calculation, is limited to the same number of significant digits as the least number in any of the values used in the calculation.