Electrostatic Formula
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Force F = 1 q 1 q 2 = k q 1 q 2 4 e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = C 2 4 e o 4 8.85x C 2 N m 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E = Volts q d meter
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance C = Q V C = KA o d K= dielectric constant A = area in m 2 x C 2 N m 2 d = distance between plates in m
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11=1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11=1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11=1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11=1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J
Capacitance 1 = C series C 1 C 2 C 3 2 F 4 F 6 F 1/C = 1/2 F 1/4 F + 1/6 F 1/C = 11/12 F = 12 F/11= 1.09 F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J