Stoichiometry.

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Limiting Reactants and Stoichiometry

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Presentation transcript:

Stoichiometry

10 steps to stoich Write word equation Write formula equation Balance Write given info under it in equation Write what you solving for under it in equation Convert given info into moles Use the mole ratio Convert moles into g, parts, … Calculate answer Write answer with correct sig figs and units

If 21.0 g of silver nitrate (169.9) was added to excess calcium chloride (110.98), how many grams of solid silver chloride (143.35) should have formed? What is the other product? Silver nitrate + calcium chloride  silver chloride + calcium nitrate AgNO3 (aq) + CaCl2 (aq)  AgCl (s) + Ca(NO3)2 (aq) 2 2 21.0 g ? g 7 8 6 = 17.7 g AgCl Always 1 mol in step 6 and 8 Numbers come from balanced equation

AgNO3 (aq) + CaCl2 (aq)  AgCl (s) + Ca(NO3)2 (aq) North side convert 21.0 g AgNO3  ? g CaCl2 South side convert 17.7 g AgCl  ? g CaCl2 2 2 ? g 21.0 g 17.7 g 6.86 g CaCl2 Different do to rounding off only 6.85 g CaCl2