1 Chapter 11 Gases 11.7 Volume and Moles (Avogadro’s Law) Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.

Slides:



Advertisements
Similar presentations
Gases Volume and Moles (Avogadro’s Law)
Advertisements

Volume and Moles (Avogadro’s Law)
Pressure and Volume (Boyle’s Law)
Aim: How to convert from moles to volume and vice versa
Temperature and Pressure
1 Chapter 6Gases 6.5 Temperature and Pressure (Gay Lussac’s Law) Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings.
1 Chapter 6Gases 6.4 Temperature and Volume (Charles’ Law) Copyright © 2005 by Pearson Education, Inc. Publishing as Benjamin Cummings.
1 Chapter 6 Gases 6.6 The Combined Gas Law. 2 The combined gas law uses Boyle’s Law, Charles’ Law, and Gay-Lussac’s Law (n is constant). P 1 V 1 =P 2.
COMBINED GAS LAW AND AVOGADRO’S PRINCIPLE. COMBINED GAS LAW P1V1P2V2T1T2P1V1P2V2T1T2 =
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
The Mole–Mass Relationship How do you convert the mass of a substance to the number of moles of the substance? 10.2.
Molar & atomic Mass Mole  > particles Mass  > Mole Molar Volume of Gas Gas Density
Grams to Moles to Molecules. How many molecules in 5.00g of hydrogen gas? 5.00g H 2 x 1mole x 6.02 x molecules = 2.02 g1 mole = 5.00 / 2.02 x 6.02.
Chemical Quantities.  Calculate the mass of compounds.  Calculate the molar volumes of gases.  Solve problems requiring conversions between mass, and.
Mole-Mass and Mole-Volume Relationships
1 Chapter 11 Gases 11.8 The Ideal Gas Law Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 11 Gases 11.8 The Ideal Gas Law Basic Chemistry Copyright © 2011 Pearson Education,
General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc.1 Chapter 7 Gases 7.7 Volume and Moles (Avogadro’s Law)
Chapter 11 - Gases Properties of Gases Gas Pressure Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Chemistry 103 Lecture 19. General Course structure - WEEK 5 Atoms ---> Compounds ---> Chemical Reactions GAS LAWS SOLUTIONS.
1 Chapter 6 Chemical Quantities 6.6 Molecular Formulas Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Ideal gases and molar volume
Ideal Gas Law & Gas Stoichiometry
End Show Slide 1 of 39 © Copyright Pearson Prentice Hall Mole–Mass and Mole– Volume Relationships > The Mole–Mass Relationship Mole-mass relationship:
Chemistry.
1 Chemistry 111 Chapter 13 2 Gases Revisited Ideal Gas Law Gas Density.
1 Chapter 11 Gases 11.9 Gas Laws and Chemical Reactions Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Copyright © 2004 Pearson Education Inc., publishing as Benjamin Cummings. 1 Chapter 8 Gases 8.1 Gases and Kinetic Theory 8.2 Gas Pressure 8.8 Ideal Gas.
Ideal Gas Law & Gas Stoichiometry. Ideal Gas Law P V = n R T P = Pressure (atm) V = Volume (L) T = Temperature (K) n = number of moles R is a constant,
Molecular Composition of Gases The Ideal Gas Law.
1 Chapter 6 Chemical Quantities 6.4 Calculations Using Molar Mass Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Molar Volume Avogadro’s Law: Equal volumes of gas at the same temperature and pressure contain equal numbers of particles. But the mass is different!!!
Chapter 9 Gases: Their Properties and Behavior. Gases and Gas Pressure Gas mixtures are homogeneous and compressible.
Chapter 11 - Gases Properties of Gases Gas Pressure Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Gases The Combined Gas Law Volume and Moles (Avogadro’s Law) Partial Pressures (Dalton’s Law)
Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.
GAS DENSITY AND AVAGODRO’S LAW ONE MOLE OF ANY GAS OCCUPIES A VOLUME OF 22.4 LITERS AT STP. 1.GAS PRESSURE IS A COLLIGATIVE PROPERTY AT STP. 2.COLLIGATIVE:
Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.
Chemistry An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Chapter 6 Gases 6.7.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 11 Gases 11.7 Volume and Moles (Avogadro’s Law) Balloons rise in the air because helium.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 11 Gases 11.9 Gas Laws and Chemical Reactions Under water, the pressure on a diver is.
1 Chapter 10 Chemical Quantities 10.4 Calculations Using Molar Mass Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Ideal gases and molar volume
Unit 1 Gases. Ideal Gases Objectives 1. Compute the value of an unknown using the ideal gas law. 2. Compare and contrast real and ideal gases.
Chapter 11 - Gases Properties of Gases Gas Pressure Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
UNIT 6: CHEMICAL QUANTITIES Chapter 10: Mole and Volume Relationships.
Chapter 19 Avogadro’s Principle. Avogadro's Principle states that equal volumes of gases at the same temperature and pressure contain an equal number.
Chapter 11 - Gases Properties of Gases Gas Pressure Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Chapter 7 Lesson 2 Chemical Quantities. Mass-Mole Calculations What is the mass of 1.33 moles of titanium, Ti? What is the mass of 1.33 moles of titanium,
10.2 Mole-Mass and Mole- Volume Relationships 1 > Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved.. Chapter 10 Chemical Quantities.
General, Organic, and Biological Chemistry
7.7 Volume and Moles (Avogadro’s Law)
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
8.6 Volume and Moles, Avogadro’s Law
Chapter 10 Chemical Quantities
10.5 NOTES Avogadro Molar Volumes
Chapter 10 Chemical Quantities
Ideal Gas Law.
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
Chapter 8 Chemical Quantities in Reactions
3.3 The Molar Volume Pages
Volume and Moles (Avogadro’s Law)
Temperature and Pressure (Gay Lussac’s Law)
Avogadro’s Law.
Chapter 19 Avogadro’s Principle.
Chapter 10 Chemical Quantities
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
Avogadro’s Law.
Moles and Gas Volume (3.4) Avogadro’s Hypothesis: equal volumes of different gases at the same temperature and pressure contain the same number of particles.
Moles, Volume and Density
Presentation transcript:

1 Chapter 11 Gases 11.7 Volume and Moles (Avogadro’s Law) Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

2 Avogadro's Law: Volume and Moles In Avogadro’s Law The volume of a gas is directly related to the number of moles of gas. T and P are constant. V 1 = V 2 n 1 n 2 Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

3 Learning Check If 0.75 mol of helium gas occupies a volume of 1.5 L, what volume will 1.2 mol of helium occupy at the same temperature and pressure? 1) 0.94 L 2)1.8 L 3) 2.4 L Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

4 Solution 3) 2.4 L Conditions 1Conditions 2 V 1 = 1.5 LV 2 = ??? n 1 = 0.75 mol Hen 2 = 1.2 mol He V 2 = V 1 n 2 n 1 V 2 = 1.5 L x 1.2 mol He = 2.4 L 0.75 mol He

5 The volumes of gases can be compared when they have the same conditions of temperature and pressure (STP, Standard Temperature and Pressure). Standard temperature (T) 0°C or 273 K Standard pressure (P) 1 atm (760 mm Hg) STP

6 Molar Volume At standard temperature and pressure (STP). 1 mol of a gas occupies a volume of 22.4 L, which is called its molar volume. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

7 The molar volume At STP Can be used to form conversion factors L and 1 mol 1 mol 22.4 L Molar Volume as a Conversion Factor

8 Guide to Using Molar Volume Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

9 A. What is the volume at STP of 4.00 g CH 4 ? 1) 5.59 L2) 11.2 L3) 44.8 L B. How many grams of He are present in 8.00 L as at STP? 1) 25.6 g2) g3) 1.43 g Learning Check

10 A. 1) 5.59 L 4.00 g CH 4 x 1 mol CH 4 x 22.4 L (STP) = 5.59 L g CH 4 1 mol CH 4 B. 3) 1.43 g 8.00 L x 1 mol He x g He = 1.43 g He 22.4 L 1 mol He Solution

11 AT STP, the density of gas can be calculated using the mass of the gas and its volume. Density = Molar mass Molar volume Density of a Gas at STP

12 Density of a Gas Calculate the density in g/L of O 2 gas at STP. At STP, we know that 1 mol O 2 (32.00 g) occupies a volume of 22.4 L. Density O 2 at STP = g O 2 = 1.43 g/L 22.4 L (STP)