Objective The student will be able to: use the zero product property to solve equations SOL: A.4c Designed by Skip Tyler, Varina High School.

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Solving Quadratic Equations Using the Zero Product Property
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Objective The student will be able to: use the zero product property to solve equations SOL: A.4c Designed by Skip Tyler, Varina High School

Zero Product Property If a b = 0 then a=0, b=0, or both a and b equal 0.

Using the Zero Product Property, you know that either x + 3 = 0 or x - 5 = 0 Solve each equation. x = -3 or x = 5 {-3, 5} 1. Solve (x + 3)(x - 5) = 0

2. Solve (2a + 4)(a + 7) = 0 2a + 4 = 0 or a + 7 = 0 2a = -4 or a = -7 a = -2 or a = -7 {-2, -7}

3. Solve (3t + 5)(t - 3) = 0 3t + 5 = 0 or t - 3 = 0 3t = -5 or t = 3 t = -5/3 or t = 3 {-5/3, 3}

Solve (y – 3)(2y + 6) = 0 1.{-3, 3} 2.{-3, 6} 3.{3, 6} 4.{3, -6}

1.Set the equation equal to 0. 2.Factor the equation. 3.Set each part equal to 0 and solve. 4.Check your answer on the calculator. 4 steps for solving a quadratic equation Set = 0 Factor Split/Solve Check

4. Solve x x = 0 GCF = x x(x - 11) = 0 x = 0 or x - 11 = 0 x = 0 or x = 11 {0, 11} Set = 0 Factor Split/Solve Check

5. Solve. -24a +144 = -a 2 Put it in descending order. a a = 0 (a - 12) 2 = 0 a - 12 = 0 a = 12 {12} Set = 0 Factor Split/Solve Check

6. Solve 4m = 20m 4m m + 25 = 0 (2m - 5) 2 = 0 2m - 5 = 0 2m = 5 m = Set = 0 Factor Split/Solve Check

7. Solve x 3 + 2x 2 = 15x Set = 0 Factor Split/Solve Check x 3 + 2x x = 0 x(x 2 + 2x - 15) = 0 x(x + 5)(x - 3) = 0 x = 0 or x + 5 = 0 or x - 3 = 0 {0, -5, 3}

Solve a 2 – 3a = 40 1.{-8, 5} 2.{-5, 8} 3.{-8, -5} 4.{5, 8}

Solve 4r 3 – 16r = 0 1.{-16, 4} 2.{-4, 16} 3.{0, 2} 4.{0, 4} 5.{-2, 0, 2} The degree will tell you how many answers you have!

Maria told this puzzle to her friends. “The product of four times my age and 45 less than three times my age is zero. How old am I?” Find Maria’s age. Let m = Maria’s age. 4m(3m - 45) = 0 4m = 0 or 3m - 45 = 0 m = 0 or 3m = 45 m = 0 or m = 15 0 is not reasonable so Maria is 15 years old !!

Find two consecutive integers whose product is 240. Let n = 1st integer. Let n + 1 = 2nd integer. n(n + 1) = 240 n 2 + n = 240 n 2 + n – 240 = 0 (n – 15)(n + 16) = 0 Set = 0 Factor Split/Solve Check

(n – 15)(n + 16) = 0 n – 15 = 0 or n + 16 = 0 n = 15 or n = -16 The consecutive integers are 15, 16 or -16, -15.