Dividing Polynomials Unit 6-5. Divide a polynomial by a monomial. Unit Objectives: Objective 1 Divide a polynomial by a polynomial of two or more terms.

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Dividing Polynomials Unit 6-5

Divide a polynomial by a monomial. Unit Objectives: Objective 1 Divide a polynomial by a polynomial of two or more terms. 1) 2)

Dividing a Polynomial by a Monomial To divide a polynomial by a monomial, divide each term in the polynomial by the monomial, and then write each quotient in lowest terms. Divide a polynomial by a monomial.

Divide. Check this answer by multiplying it by the divisor, 5. DivisorQuotient Original polynomial CLASSROOM EXAMPLE 1 Dividing a Polynomial by a Monomial Solution:

Check: DivisorQuotient Original polynomial CLASSROOM EXAMPLE 1 Dividing a Polynomial by a Monomial (cont’d) Divide. Solution:

CLASSROOM EXAMPLE 1 Dividing a Polynomial by a Monomial (cont’d) Divide. Solution:

Divide a polynomial by a polynomial of two or more terms. Objective 2

Divide. Write the problem as if dividing whole numbers, make sure that both polynomials are written in descending powers of the variables. Divide the first term of 2k 2 by the first term of k + 6. Write the result above the division line. CLASSROOM EXAMPLE 2 Dividing a Polynomial by a Polynomial Solution:

Multiply and write the result below. 2k(k + 6) 2k k Subtract. Do this mentally by changing the signs on 2k k and adding. 5k5k Bring down 30 and continue dividing 5k by k k + 30 Subtract. 0 You can check the result, 2k + 5, by multiplying k + 6 and 2k + 5. CLASSROOM EXAMPLE 2 Dividing a Polynomial by a Polynomial (cont’d)

Divide 4x 3 + 3x – 8 by x + 2. Write the polynomials in descending order of the powers of the variables. Add a term with 0 coefficient as a placeholder for the missing x 2 term. Missing term CLASSROOM EXAMPLE 3 Dividing a Polynomial with a Missing Term Solution: Remember to include as part of the answer. Don’t forget to insert a plus sign between the polynomial quotient and this fraction.

4x 3 + 8x 2 Subtract by mentally by changing the signs on 4x 3 + 8x 2 and adding. -8x 2 Bring down the next term. + 3x 4x24x2 -8x 2 – 16x x Start with Next, - 8x + 19 Multiply then subtract. Bring down the next term. 19x + 38 –46 19x/19 = 19 Multiply then subtract. Remainder The solution is: and you can check the result by multiplying. CLASSROOM EXAMPLE 3 Dividing a Polynomial with a Missing Term (cont’d)

Divide 4m 4 – 23m m 2 – 4m – 1 by m 2 – 5m. Write the polynomial m 2 – 5m as m 2 – 5m + 0. Missing term Since the missing term is the last term it does not need to be written. CLASSROOM EXAMPLE 4 Dividing a Polynomial with a Missing Term Solution:

4m 4 – 20m 3 -3m m 2 4m24m2 -3m m 2 m2m2 - 3m + 1 m 2 – 5m m – 1 Remainder – 4m CLASSROOM EXAMPLE 4 Dividing a Polynomial with a Missing Term (cont’d)

8x x 2 5x25x2 - 2x 2x22x2 5x x -12x +- 3 –12x – 24 0 – 24 Divide 8x x 2 – 2x – 24 by 4x + 8. The solution is: CLASSROOM EXAMPLE 5 Finding a Quotient with a Fractional Coefficient Solution: