Bell Work Solve = a – n = 24 a = 7 n = 17

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Presentation transcript:

Bell Work Solve. 1. 5 = a – 2 2. 7 + n = 24 a = 7 n = 17 3. 3c – 7 = 32 4. 17y + 7 = 58 c = 13 y = 3

Learning Target: I can Determine if an ordered pair is a solution to an equation Create a table of Ordered Pair Solutions

a value for the variable that makes an equation true Vocabulary - an (x, y) point ordered pair a math sentence it has an = sign equation solution a value for the variable that makes an equation true

Do this one along with me: Determine whether each ordered pair is a solution of y = 4x – 1. (3, 11)‏ y = 4x – 1 11 = 4(3) – 1 ? Substitute 3 for x and 11 for y. Simplify. 11 = 11  (3, 11) is a solution.

Try this one and check with your partner: Determine whether each ordered pair is a solution of y = 4x – 1. (10, 3)‏ y = 4x – 1 3 = 4(10) – 1 ? Substitute 10 for x and 3 for y. Simplify. 3 ≠ 39  (10, 3) is not a solution.

Try this one by yourself: Determine whether each ordered pair is a solution of y = 5x + 3. (7, 38)‏ y = 5x + 3 38 = 5(7) + 3 ? Substitute 7 for x and 38 for y. 38 = 38 ?  (7, 38) is a solution.

Just in case we need another… Determine whether each ordered pair is a solution of y = 5x + 3. (9, 17)‏ y = 5x + 3 17 = 5(9) + 3 ? Substitute 9 for x and 17 for y. 17 = 48 ?  (9, 17) is not a solution.

Work out this example along with me: Use the given values to make a table of solutions. y = x + 3 for x = 1, 2, 3, 4 x x + 3 y (x, y)‏ 1 2 3 4 1 + 3 4 (1, 4)‏ 2 + 3 5 (2, 5)‏ 3 + 3 6 (3, 6)‏ 4 + 3 7 (4, 7)‏

Work out this example with your partner: Use the given values to make a table of solutions. n = 6m – 5 for m = 1, 2, 3 m 1 2 3 6m – 5 n (m, n)‏ 6(1) – 5 (1, 1)‏ 1 6(2) – 5 7 (2, 7)‏ 6(3) – 5 13 (3, 13)‏

Try doing this one by yourself: Use the given values to make a table of solutions. y = x + 6 for x = 1, 2, 3, 4 x x + 6 y (x, y)‏ 1 2 3 4 1 + 6 7 (1, 7)‏ 2 + 6 8 (2, 8)‏ 3 + 6 9 (3, 9)‏ 4 + 6 10 (4, 10)‏

Do you have the learning targets mastered?

In the last box of your note page: Determine whether each ordered pair is a solution of y = 4x – 7. 1. (2, 15) 2. (4, 9)‏ 3. Use the given values to make a table of solutions. y = 4x  6 for x = 2, 4, and 6 no yes ‏ (6, 18)‏ 18 4(6) – 6 6 (4, 10)‏ 10 4(4) – 6 4 (2, 2)‏ 2 4(2) – 6 (x, y)‏ y 4x – 6 x

Assignment: Hand out Please wait for instructions