Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide.

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Presentation transcript:

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases joules of energy. The Great Gummy Worm Sacrifice 1. Write a balanced chemical equation for the reaction: 2. The reaction releases joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation. 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases joules of energy. The Great Gummy Worm Sacrifice 1. Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O The reaction releases joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation kJ

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases joules of energy. The Great Gummy Worm Sacrifice Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O The reaction releases joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation kJ 3. Calculate the mass of oxygen needed to completely react the 2.1 g of sucrose in the gummy worm 2.1g C 12 H 22 O 11 gC 12 H 22 O 11 mol C 12 H 22 O mol C 12 H 22 O 11 mol O mol O 2 gO gO 2 =

Today, we will burn a gummy worm containing 2.1 g of sucrose (C 12 H 22 O 11 ). When one mole of sucrose burns in oxygen gas, it produces carbon dioxide gas, water vapor, releases joules of energy. The Great Gummy Worm Sacrifice Write a balanced chemical equation for the reaction: C 12 H 22 O 6 + O 2 --> CO 2 + H 2 O The reaction releases joules for each mole of sucrose consumed, add 5 640kJ to the product side of your equation kJ 4. Now use the same strategy to calculate how much energy is released by the combustion of 2.1 g of sucrose 2.1g C 12 H 22 O 11 gC 12 H 22 O 11 mol C 12 H 22 O mol C 12 H 22 O 11 kJ kJ or J = That’s a lot of energy from just 2.1 grams of sucrose! It sounds dangerous. Let’s try it!