Five-Minute Check (over Lesson 10-4) Main Ideas and Vocabulary

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Presentation transcript:

Five-Minute Check (over Lesson 10-4) Main Ideas and Vocabulary Targeted TEKS Key Concept: The Distance Formula Example 1: Distance Between Two Points Example 2: Use the Distance Formula to Solve a Problem Example 3: Find a Missing Coordinate Lesson 5 Menu

Find the distance between two points on the coordinate plane. Find a point that is a given distance from a second point on a plane. Distance Formula Lesson 5 MI/Vocab

Key Concept 10-5a

Distance Between Two Points Find the distance between the points at (1, 2) and (–3, 0). Distance Formula (x1, y1) = (1, 2) and (x2, y2) = (–3, 0) Simplify. Evaluate squares and simplify. Answer: Lesson 5 Ex1

Find the distance between the points at (5, 4) and (0, –2). A. 29 units B. 61 units C. 7.81 units D. 10 units A B C D Lesson 5 CYP1

BIATHLON Julianne is sighting her rifle for an upcoming biathlon competition. Her first shot is 2 inches to the right and 7 inches below the bull’s- eye. What is the distance between the bull’s-eye and where her first shot hit the target? Model the situation. If the bull’s-eye is at (0, 0), then the location of the first shot is (2, –7). Use the Distance Formula. Lesson 5 Ex2

Distance Formula (x1, y1) = (0, 0) and (x2, y2) = (2, –7) Simplify. Answer: Lesson 5 Ex2

HORSESHOES Marcy is pitching a horseshoe in her local park HORSESHOES Marcy is pitching a horseshoe in her local park. Her first pitch is 9 inches to the left and 3 inches below the pin. What is the distance between the horseshoe and the pin? A. 9 in B. 3 in C. 12 in D. 9.49 in A B C D Lesson 5 CYP2

Find a Missing Coordinate Find the value of a if the distance between the points at (2, –1) and (a, –4) is 5 units. Distance Formula Let d = 5, x2 = a, x1 = 2, y2 = –4, and y1 = –1 Simplify. Evaluate squares. Simplify. Lesson 5 Ex3

Find a Missing Coordinate 25 = a2 – 4a + 13 Square each side. 0 = a2 – 4a – 12 Subtract 25 from each side. 0 = (a – 6)(a + 2) Factor. a – 6 = 0 or a + 2 = 0 Zero Product Property a = 6 a = –2 Solve. The value of a is –2 or 6. Answer: –2 or 6 Lesson 5 Ex3

Find the value of a if the distance between the points at (2, 3) and (a, 2) is units. A. –4 or 8 B. 4 or –8 C. –4 or –8 D. 4 or 8 A B C D Lesson 5 CYP3