Motion/Newtons Physics Review

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VELOCITY AND SPEED

Acceleration

Vectors

Momentum And Impulse

Newton’s 3 rd Law and Friction

Velocity and Speed Acceleration Vectors Momentum and Impulse Newton’s 3 rd and Friction $100 $300 $200 $400 $500

CATEGORY 1 - $100 An object moves a distance of 10 m in 5 seconds. The average speed of the object is a 0.5 m/s b 2.0 m/s c 40 m/s d 50 m/s

CATEGORY 1 - $200 A baseball Pitcher throws a fastball at 42 m/s. If the batter is 18 meters from the pitcher, approximately how much time does it take for the ball to reach the batter? a 1.9 sb 2.3 s c 0.86 sd 0.43 s

CATEGORY 1 - $300 As a cart travels around a horizontal circular track, the cart MUST undergo a change in a: velocityb: speed c: inertiad: weight

CATEGORY 1 - $400 What is the distance covered between the 2 nd and 6 th second? a 8mb 2m c 6 m d 4m

CATEGORY 1 - $500 The average speed of a plane was 600 kilometers per hour. How long did it take the plane to travel 120 km? a: 0.2 hb: 0.5 h c: 0.7 hd: 5 h

CATEGORY 2 - $100 As an object falls freely near the surface of the Earth, its velocity: a: decreases b: increases c : remains the same

CATEGORY 2 - $200 A car starts from rest at 4.0 m/s 2. The car will reach a speed of 28 m/s at the end of: a: 3.5 sb: 7.0 s c: 14 sd: 24 s

Acceleration - $300 A toy projectile is fired from the ground vertically upward with an initial velocity of +29 meters per second. The projectile arrives at its maximum altitude in 3.0 seconds. As the projectile rises and then falls back to the ground, its acceleration a: decreases, then increases b: increases, then decreases c: increase onlyd: remains the Same

Acceleration - $400 A car moving at a speed of 8.0 meters per second enters a highway and accelerates at 3.0 meters per second 2. How fast will the car be moving after it has accelerated for 56 meters? a: 24 m/sb: 20 m/s c: 18 m/sd: 4 m/s

Acceleration - $500 An object, initially at rest, falls freely near the Earth's surface. How long does it take the object to attain a speed of 98 meters per second? a:.1 sb: 10 s c: 98 sd: 980 s

Vectors - $100 Which is a scalar quantity? a: displacement b: velocity c: acceleration d: mass

Vectors - $200 The resultant of two concurrent forces is minimum when the angle between them is: a: 0b: 90 c: 180d: 270

Vectors - $300 Two concurrent forces of 40 newtons and X newtons have a resultant of 100 newtons. Force X could be a: 20b: 40 c: 80d: 150

Vectors - $400 In the diagram, the weight of a box on a plane inclined at 30.º is represented by the vector W. What is the magnitude of the component of the weight (W) that acts parallel to the incline? a:.5 Wb:.87 W c: 1.0 Wd: 1.5 W 30 0

Vectors - $500 The handle of a lawn roller is held at 45º from the horizontal. A force, F, of 28.0 newtons is applied to the handle as the roller is pushed across a level lawn, as shown in the diagram below. What is the magnitude of the force moving the roller forward? 45 0 a: 7.0 N b: 14.0 N c: 19.8 N d: 39.0 N F

Momentum and Impulse - $100 What is the momentum of a 30-kilogram cart moving with a speed of 10 meters per second? a: 20 kg-m/s b: 40 kg-m/s c: 3 kg-m/s d: 300 kg-m/s

Momentum and Impulse - $200 What is the momentum of a 1.5 x 10 3 kg car as it travels at 30 m/s due east for 60s? a: 4.5 x 10 4 kg-m/s, east b: 4.5 x 10 4 kg-m/s, west c: 4.5 x 10 6 kg-m/s, east d: 4.5 x 10 6 kg-m/s, west

Momentum and Impulse - $300 A mass with a momentum of 40. kg-m/s receives an impulse of 30N*s in the direction of its motion. The final momentum of the mass is a:1.3 kg-m/sb:10. kg-m/s c: 70 kg-m/sd:150 kg-m/s

Momentum and Impulse - $400 A 4.0-kilogram mass is moving at 3.0 meters per second toward the right and a 6.0-kilogram mass is moving at 2.0 meters per second toward the left on a horizontal frictionless table. If the two masses collide and remain together after the collision, their final momentum is a:12 kg-m/sb: 7 kg-m/s c: 4 kg-m/sd: 0 kg-m/s

Momentum and Impulse - $500 If the 1.0-kilogram object receives an impulse of newton-seconds, what impulse does the 2.0-kilogram object receive? a: 0 N*sb: - 10 N*s c: - 20 N*sd: - 40 N*s

Gravitational and Newton’s 3rd - $100 A 30-kilogram boy exerts a force of 100 newtons on a 50-kilogram object. The force that the object exerts on the boy is a: 500 Nb: 30 N c: 100 Nd: 0 N

Newton’s 3 rd and Friction - $200 A 1-kilogram object rests on a horizontal table top. The force that the table top exerts on the object is a: 1Nb: 1 kg c:.1Nd: 9.8 N

Newton 3 rd and Friction - $300 In order to keep an object weighing 20 newtons moving at constant speed along a horizontal surface, a force of 10 newtons is required. The force of friction between the surface and the object is a: 10 Nb: 30 N c: 20 Nd: 0 N

Newton’s 3rd and Friction - $400 The diagram below which represents a 3.0-kilogram mass being moved at a constant speed by a force of 6.0 newtons.The magnitude of the force of friction acting on the mass is a: 3 Nb: 6 N c: 0 Nd: 18 N

Newton’s 3rd and Friction - $500 The diagram below which represents a 3.0- kilogram mass being moved at a constant speed by a force of 6.0If the surface were frictionless, the 6.0-newton force would produce an acceleration of a:.33 m/s 2 b: 2 m/s 2 c: 6 m/s 2 d: 33 m/s 2

Velocity and Speed - $100 b 2.0 m/s V= d/t =10m / 5s = 2.0 m/s

Velocity and Speed - $200 d 0.43s v = d / t 42 m/s = 18 m / t t =18 m / 42 m/s t = 0.43 s

Velocity and Speed - $300 a: Velocity Velocity has direction in its measurement, circle motion must have a constant change in direction $

Velocity and Speed - $400 d: 4m 6m-2m = 4m

Velocity and Speed - $500 a : 0.2 h v = d / t 600 km /h = 120 km / t t = 120 km / 600 km / h t =. 2 h

Acceleration - $100 b: increases The velocity increases at 9.81 m/s every second!

Acceleration - $200 b: 7.0 s a = v / t 4.0 m/s 2 = 28 m/s – 0 m/s / t t = 28 m/s / 4.0 m/s 2

Acceleration - $300 d: remains the same All objects fall at a constant acceleration of 9.81 m/s 2 unless friction is present

Acceleration - $400 b: 20 m/s V f 2 = V i 2 + 2ad = ( 8m/s ) ( 3m/s 2 ) ( 56m) = 400 m 2 /s 2 V f = 20 m/s $

Acceleration - $500 b: 10 s V f = V i + at 98 m/s = 0 m/s m/s 2 t 98 m/s = t 9.8 m/s 2 10 s = t

Vectors - $100 d: mass Mass has no direction!

Vectors - $200 c: The minimum vector addition direction results from opposite direction

Vectors - $300 c: 80 N Adding 80N + 40N =120N Subtracting 80N- 40N = 40N Range 40N-120N contains 100N

Vectors - $400 a:.5 W Ax = A sin  =W sin (30 0 ) =W sin (30 0 ) =.5 W

Vectors - $500 c : 19.8 N Ax = A cos  = 28 N cos (45 0 ) = 28 N (.707) = 19.8 N

Momentum and Impuse - $100 d: 300 kg-m/s P=mv = 30 kg ( 10 m/s )

Momentum and Impulse - $200 a: 4.5 x 10 4 kg-m/s, east p= mv = 1.5 x 10 3 kg ( 30 m/s ), east = 1.5 x 10 3 kg ( 30 m/s ), east = 45 x 10 3 kg-m/s, east = 45 x 10 3 kg-m/s, east = 4.5 x 10 4 kg-m/s, east = 4.5 x 10 4 kg-m/s, east

Momentum and Impulse - $300 C: 70 kg-m/s J=F(t) = m  v =  p 30 N*s =p 1 - (40 kg-m/s) 70 kg-m/s =p 1

Momentum and Impulse - $400 d: 0 kg-m/s Conservation of momentum P (total) = P 1 +P 2 = 0 m 1 v 1 +m 2 v 2 = 0 4kg*3m/s +6kg*-2m/s = 0 0 kg-m/s

Momentum and Impulse - $500 c: -20 N*s For every action there is an equal and opposite reaction

Gravitational and Newton’s 3rd - $100 c: 100 N For every action there is an equal and opposite reaction, Newton’s 3 rd Law

Newton’s 3 rd and Friction - $200 d: 9.8 N F = ma = (1kg) 9.8 m/s 2

Newton’s 3rd and Friction - $300 a: 10 N Friction is the force opposite the motion of the object. Constant speed means that the system is in equilibrium.

Newton’s 3rd and Friction - $400 b: 6N b: 6N Friction is the force opposite the motion of the object. Constant speed means that the system is in equilibrium.

Newton’s 3rd and Friction - $500 b: 2 m/s 2 F = ma 6N = 3kg ( a) 2 m/s 2 = a

FINAL CATEGORY: Momentum Place you Bet now

FINAL CATEGORY If a Baseball bat is reduced in mass by drilling out the center, List 3 momentum factors that are changed by swinging this new bat. Be specific on details.

1. Mass of the bat 2. Final velocity of the bat 3. Time of contact between the bat and ball FINAL CATEGORY $

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