Optimal Design Problem Formulation Rudy J. Eggert, Professor Emeritus 1.

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Presentation transcript:

Optimal Design Problem Formulation Rudy J. Eggert, Professor Emeritus 1

Today’s lecture Homework Review – Design, Form from Function – Optimal design Opt. Des. Problem Formulation Examples 2

Review Design-decision making activities – Form from Function – Phases: Formulation Concept Configuration Parametric Detail Opt. Design-systematic parametric design 3

Design control hold move protect store decision making processes shape configuration size materials manufacturing processes Function Form Set of decision making processes and activities to determine: the form of an object, given the customer’s desired function.

Systematic Parametric Design 5

Opt. Design Problem Formulation Develop a mathematical model Include mathematical relations for : 1. A performance criterion or “cost function” (measures “goodness” of the candidate’s design) 2. Necessary behaviors (must do or have) (obey laws of man, or nature, i.e. safety, physics, chemistry etc) 6

Standard Design Optimzation Model 7

Design Problem Formulation (Arora) 8 Step 1. Project/problem description Step 2. Data and information collection Step 3. Definition of design variables Step 4. Optimization criterion Step 5. Formulation of constraints Let’s reword these as actions to perform…

Opt. Des. Problem Formulation (Eggert) 9 Step 1. Describe problem Step 2. Collect info Step 3. Define DVs Step 4. Determine objective function Step 5. Formulate constraints

Design of a can 10 Step 1. Describe problem (restate w/bullets) Must hold at least 400 ml Min mfg cost which is proportional to surface area Diameter no more than 8 cm Diameter no less than 3.5 Height no more than 18 cm Height no less than 8 cm

Design of a can 11 Step 1. Describe problem Step 2. Collect info Step 3. Define DVs Step 4. Determine objective function Step 5. Formulate constraints

Design of a can 12 Step 2. Collect info Draw diagram Relation for volume Relation for surface area Other? Volume = Area x height = (πD 2 /4)H Surface area = top + bottom + side Area top, bottom = πD 2 /4 Area side = πDH Total area = πD 2 /4 + πD 2 /4 + πDH (cm 3 )

Design of a can 13 Step 3. Define DVs Diameter, D, (cm) Height, H, (cm) x=[x 1, x 2 ] = [D, H] Note: volume and area are functions of the DVs

Design of a can 14 Step 4. Determine objective function Min f(x) = πD 2 /2 + πDH (cm 2 )

Design of a can 15 Step 5. Formulate constraints Volume ≥ 400 ml (cm 3 ), or (πD 2 /4)H ≥ 400 (cm 3 ) 3.5 ≤ D ≤ 8 8 ≤ H ≤ ≤ D 8 ≤ H D ≤ 8 H ≤ 18 Size limits

Design of a can - Summary 16 (πD 2 /4)H ≥ 400 (cm 3 ) 3.5 ≤ D 8 ≤ H D ≤ 8 H ≤ 18 Min f(D,H) = πD 2 /2 + πDH (cm 2 ) Subject to:

More on design variables (DVs) 17 Parameters that: 1.can be arbitrarily selected by the design engineer, AND that 2.influence the behavior of the product (or process) to be designed For discrete variables... determine set of permissible values DV Nameheight SymbolH Units(cm) Upper bound18 cm Lower bound8 cm

Likely DV’s – think FORM 18 Sizes L, W, H, D, t Shapes square, circular, cylindrical, slender, short Configurations left-handed, on-top, behind, over Materials metals, polymers, ceramics Manufacturing processes machined, stamped, molded

More on Constraints 19 How will the product “fail” to function/perform? Legally Mechanically Electrically Chemically Other?

Mechanical failure modes 20 Tensile/compressive failure, plastic, brittle Buckle Corrosion Excess deflection Excessive friction Thermal (melts, combusts…) Wear Vibration Unsatisfactory motion (i.e. 4-bar, x,v,a) Other?

Electrical failure modes 21 Short circuit Open circuit Excessive power, heat Poor filtering EM interference Other?

Legal failure modes 22 Violates codes/standards Causes unforeseen property damage Causes unforeseen injury Infringes existing patent Other?

Aids to math. modeling 23 Diagrams Class notebooks Handbooks Textbooks Test results CAD

Summary Spend time on formulating 5 Step process Resulting in math. model 24