Narrow tank productivity in the 46 spectra. Henry Young 1982
35 kW / m x 400 km = 14 GW Installed capacity (2009) = 12.2 GW Planned 19 GW Peak demand ~ 6 GW 14 GW x 8760 hours = 122 TWH Annual Scottish demand = 29 TWH Ratio 4.2
Narrow tank freak wave tests 1978
Inflation from1998 to 2013 is 1.43
2013 – 1982 = 31 years Cable length 43 km = 1333 km years. At 10 km years per fault this is 133 faults. From Lords Select Committee on European Communities HL paper 88 May 1988
What’s wrong with wave energy? Control by nuclear people >False information Impatient investors >Unreliable components > Ignorance of stresses Waste of sea front by solo devices Inadequate installation equipment Preference for vertical motion.
No names, no pack drill.
Unswept flow passage ≡ leaky pipe
R.A. McAdam, G.T. Houlsby, M.L.G. Oldfield Structural and Hydrodynamic Model Testing of the Transverse Horizontal Axis Water Turbine EWTEC 2011
Edinburgh vertical-axis, variable-pitch with rim power take off. EWTEC Patras 1998
Edinburgh vertical-axis, variable-pitch with rim power take off. EWTEC Patras 1998
Cells are 1 minute of arc lat. 1.5 minutes long = km 2. Power = TW x Cf Courtesy Proudman Labs
From Black and Veatch Using values for the Pentland Firth U = 3m/s, ρ = 1025 kg/m3, channel length = 23 km, channel width = 10 km in combination with a more appropriate bed friction coefficient CD = energy dissipated due to bed friction averaged over a tidal cycle calculated is 4.05 GW.
Laminaria Hyperborea (kelp) are found along the edges of the Pentland Firth at depths up to 30 m. Length can reach 3.5 metres. Cf = ?
Pentland bed stills. P Hayes. Fisheries Research Aberdeen mm bob
What’s wrong with tidal stream designs? Ignorance of flow impedance. > Wrong energy input Open flow field equation in a ‘duct’ > Swept area too small Wrong blade support > Bearing load levered up Cramped power compartment Tip vortex losses
Google images
Speed up x 30 Range up x 6000 Payload up x 20,000 Cost per ton-mile down ÷ 100 Google images
Something for the simpletons