Bond Enthalpies How does a chemical reaction have energy?
Bond Energy Energy required to make/break a chemical bond Endothermic reactions Products have more energy than reactants More energy to BREAK bonds Exothermic reactions Reactants have more energy than products More energy to FORM bonds
Bond Enthalpy Focuses on the energy/heat between products and reactants as it relates to chemical bonding Amount of energy absorbed to break a chemical bond--- amount of energy released to form a bond. Multiple chemical bonds take more energy to break and release more energy at formation Amount of energy absorbed = amount of energy released to break chemical bond to form a chemical bond
Calculating ΔH rxn. by bond enthalpies (4 th method) Least accurate method ΔH = ΣBE (bonds broken) - ΣBE (bonds formed)
Example 1: Using average bond enthalpy data, calcaulate ΔH for the following reaction. CH 4 + 2O 2 CO 2 + 2H 2 O ΔH = ? BondAverage Bond Enthalpy C-H413 kJ/mol O=O495 kJ/mol C-O358 kJ/mol C=O799 kJ/mol O-H467 kJ/mol
Entropy
Spontaneous vs. Nonspontaneous 1)Spontaneous Process Occurs WITHOUT help outside of the system, natural Many are exothermic—favors energy release to create an energy reduction after a chemical reaction Ex. Rusting iron with O 2 and H 2 O, cold coffee in a mug Some are endothermic Ex. Evaporation of water/boiling, NaCl dissolving in water
Spontaneous vs. Nonspontaneous 2) Nonspontaneous Process REQUIRES help outside system to perform chemical reaction, gets aid from environment Ex. Water cannot freeze at standard conditions (25°C, 1atm), cannot boil at 25°C **Chemical processes that are spontaneous have a nonspontaneous process in reverse **
Entropy (S) Measure of a system’s disorder Disorder is more favorable than order ΔS = S (products) - S (reactants) ΔS is (+) with increased disorder State function Only dependent on initial and final states of a reaction Ex. Evaporation, dissolving, dirty house
Thermodynamic Laws 1 st Law of Thermodynamics Energy cannot be created or destroyed 2 nd Law of Thermodynamics The entropy of the universe is always increasing. Naturally favors a disordered state
When does a system become MORE disordered from a chemical reaction? (ΔS > 0) 1)Melting 2)Vaporization 3)More particles present in the products than the reactants 4C 3 H 5 N 3 O 9 (l) 6N 2 (g) + 12CO 2 (g) + 10H 2 O (g) + O 2 (g) 4)Solution formation with liquids and solids 5)Addition of heat
When does a system become LESS disordered from a chemical reaction? (ΔS < 0) 1)Solution formation with liquids and gases
3 rd Law of Thermodynamics The entropy (ΔS) of a perfect crystal is 0 at a temperature of absolute zero (0°K). No particle motion at all in crystal structure All motion stops
How do we determine if a chemical reaction is spontaneous? 1)Change in entropy (ΔS) 2)Gibbs Free Energy (ΔG)
Change in entropy (ΔS) For a chemical reaction to be spontaneous (ΔS T > 0), there MUST be an increase in system’s entropy (Δs sys > 0) and the reaction MUST be exothermic (Δs surr > 0). Exothermic reactions are favored, NOT endothermic reactions. Exothermic (ΔH 0) Endothermic (ΔH > 0, ΔS < 0) ΔS T = Δs sys + Δs surr If ΔS T > 0, then the chemical reaction is spontaneous
Example 1: Will entropy increase or decrease for the following? a)N 2 (g) + 3H 2 (g) 2NH 3 (g) b)2KClO 3 (s) 2KCl (s) + 3O 2 (g) c)CO (g) + H 2 O (g) CO 2 (g) + H 2 (g) d)C 12 H 22 O 11 (s) C 12 H 22 O 11
How do we calculate the entropy change (ΔS) in a chemical reaction? Same method as using the enthalpies of formation to calculate ΔH and use the same table. aA + bB cC + dD ΔS° =[c (ΔS° C ) + d(ΔS° D )] - [a (ΔS° A ) + b (ΔS° B )]
Example 2: Calculate ΔS° for the following reaction at 25°C…. 4HCl (g) + O 2 (g) 2Cl 2 (g) + 2H 2 O (g)
Homework pp #69, pp #19, 27