Worksheet: Acids, Bases & pH Key

1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 (b) pOH = 9 (c) pH = 3 (d) pOH = 4 (e) pH = 13 (f) pOH = 7

1. Label the substance below as an acid, base or neutral substance. (a)pH = 7 N(b) pOH = 9 A (c) pH = 3 A(d) pOH = 4 B (e) pH = 13 B(f) pOH = 7 N

2. How does the Arrhenius theory define an acid?

An acid produces H 3 O + ions when dissolved in water.

3. How does the Arrhenius theory define an base?

A base produces OH - ions when dissolved in water.

4. Differentiate between an electrolyte and a nonelectrolyte.

An electrolyte dissolves into ions when placed in water whereas a nonelectrolyte dissolves into molecules.

5. What type of substances are electrolytes?

Acids, Bases, Salts

6. When H+ ions are dissolved in water they become hydronium ions. What is the formula for a hydronium ion?

H3O+H3O+

7. What is the pH of a solution with a [H + ] = 4.32 x ?

pOH =

8. What is the pOH of a solution with a [OH - ] = 6.83 x ?

pOH = 2.166

9. What is the pOH of a solution with a pH = 3.8?

pOH = 10.2

10. What is the [H + ] in a solution with a pH = 7.3?

[H + ] = 5.0 x 10 -8

11. What is the [OH - ] in a solution with a pOH = 10.7?

[OH - ] = 2.0 x

12. What is the pH of a solution with a [OH - ] = 8.62 x ?

pH = 9.936

13a) Write the balanced equation for the acid-base neutralization of H 2 SO 4 and Ba(OH) 2.

H 2 SO 4 + Ba(OH) 2 → BaSO 4 + 2H 2 O

13b) Write the balanced equation for the acid-base neutralization of HF and NaOH.

HF + NaOH → NaF + H 2 O

13c) Write the balanced equation for the acid-base neutralization of HI and Sr(OH) 2.

2HI + Sr(OH) 2 → SrI 2 + 2H 2 O

13d) We often use the equation M acid x V acid = M base x V base. Which of the acid-base neutralization reactions above could we not use this formula for? Explain.

The reaction between HI and Sr(OH) 2 could not be used because the acid and the base do not react in a 1:1 ratio.

13e) In an acid-base neutralization reaction 26 ml of Ba(OH) 2 reacts with 16 ml of 0.48M H 2 SO 4. What is the molarity of the Ba(OH)2?

0.30M

13f) How many milliliters of 0.57M HF will react with 39 ml of 0.86M NaOH in an acid-base neutralization reaction?

59 ml