Stoichiometry The Mole - Study Questions

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Presentation transcript:

Stoichiometry The Mole - Study Questions   1.       What were Avogadro’s 2 major contributions to chemistry? 2.       What is the unit for mass used on the periodic table? 3.       How does molecular mass differ from molar mass? 4.       Convert 200 g of FeO to moles. 5.       Convert 3 mol of CO2 to grams. 6.       What is a conversion factor? 7.       If 25 g of a substance equals 1 mole, what conversion factor would you use to convert 1.5 mol to grams? 8.       What conversion factor would be used to convert 3 mol of the substance in question 10 to grams? 9.       What is the unit used for molecular and formula mass? 10.     What is the unit of molar mass? 11.     The oxidation of 50.0 g of Mn produces 79.1 g of an oxide. Calculate (a) the percent composition, and (b) the empirical formula of this oxide. 12.     What two things are conserved in a chemical reaction? 13.     Why aren’t moles conserved in a chemical reaction? For the next 4 questions balance the equation and calculate the indicated quantity. 14.       K(s) + H2O (g)  KOH(aq) + H2(g) How much KOH will be produced from 100 g of K? 15.       Fe2O3(s) + C  Fe(l) + CO(g) How much CO will be produced from 100 g of C? 16.       CaC2(s) + H2O(l)  Ca(OH)2(s) + CsH2(g) How much CaC2 is required to produce 100 g of C2H2? 17.       C4H10(g) + O2  CO2(g) + H2O(l) How much H2O can be produced using 100 g O2? 18.     What is a mole? 19.     How many particles are there in a mole? http://www.unit5.org/chemistry/Stoichiometry.html

Welcome to Mole Island 1 mol = molar mass 1 mole = 22.4 L @ STP 6.02 x 1023 particles

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mass Mountain Mass Mole Island Volume Mole Mole Volume V Liter Lagoon Particles Particles P Particle Place Stoichiometry Island Diagram

Stoichiometry Island Diagram Known Unknown Substance A Substance B Mass Mass 1 mole = molar mass (g) 1 mole = molar mass (g) Use coefficients from balanced chemical equation Volume Mole Mole Volume 1 mole = 22.4 L @ STP 1 mole = 22.4 L @ STP (gases) (gases) 1 mole = 6.022 x 1023 particles (atoms or molecules) 1 mole = 6.022 x 1023 particles (atoms or molecules) Particles Particles Stoichiometry Island Diagram

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mass Mountain Mass Volume Mole Mole Volume V Liter Lagoon Particles Particles P Particle Place Stoichiometry Island Diagram

Visualizing a Chemical Reaction 2 Na + Cl2 NaCl 2 ___ mole Na 10 10 ___ mole Cl2 5 5 ___ mole NaCl 10 10 ?

Visualizing a Chemical Reaction 2 Na + Cl2 NaCl 2 ___ mole Na 10 ___ mole Cl2 5 ___ mole NaCl 10

Proportional Relationships 2 1/4 c. flour 1 tsp. baking soda 1 tsp. salt 1 c. butter 3/4 c. sugar 3/4 c. brown sugar 1 tsp vanilla extract 2 eggs 2 c. chocolate chips Makes 5 dozen cookies. I have 5 eggs. How many cookies can I make? Ratio of eggs to cookies 5 eggs 5 doz. 2 eggs = 12.5 dozen cookies 150 cookies Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Proportional Relationships Stoichiometry mass relationships between substances in a chemical reaction based on the mole ratio Mole Ratio indicated by coefficients in a balanced equation A balanced chemical equation gives the identity of the reactants and products and the accurate number of molecules or moles of each that are consumed or produced. Stoichiometry is a collective term for the quantitative relationships between the masses, numbers of moles, and numbers of particles (atoms, molecules, and ions) of the reactants and products in a balanced reaction. A stoichiometric quantity is the amount of product or reactant specified by the coefficients in a balanced chemical equation. 2 Mg + O2  2 MgO Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Stoichiometry Steps Core step in all stoichiometry problems!! 1. Write a balanced equation. 2. Identify known & unknown. 3. Line up conversion factors. Mole ratio - moles  moles Molar mass - moles  grams Molarity - moles  liters soln Molar volume - moles  liters gas Mole ratio - moles  moles Core step in all stoichiometry problems!! 4. Check answer. Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Standard Temperature & Pressure Molar Volume at STP 1 mol of a gas=22.4 L at STP Standard Temperature & Pressure 0°C and 1 atm Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Molar Volume at STP MOLES LITERS OF GAS AT STP (22.4 L/mol) MASS IN GRAMS MOLES NUMBER OF PARTICLES Molar Mass (g/mol) 6.02  1023 particles/mol Molarity (mol/L) LITERS OF SOLUTION Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Stoichiometry Problems How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas? 2KClO3  2KCl + 3O2 ? mol 9 mol 9 mol O2 2 mol KClO3 3 mol O2 = 6 mol KClO3 Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

2KClO3  2KCl + 3O2 9 mol O2 2 mol KClO3 3 mol O2 = 6 mol KClO3 How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas? 2KClO3  2KCl + 3O2 ? mol 9 mol 9 mol O2 2 mol KClO3 3 mol O2 = 6 mol KClO3 2 mol KClO3 6 mol x mol KClO3 = 9 mol O2 = 6 mol KClO3 3 mol O2 O2 KClO3 Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Stoichiometry Problems How many grams of KClO3 are required to produce 9.00 L of O2 at STP? 2KClO3  2KCl + 3O2 ? g 9.00 L 9.00 L O2 1 mol O2 22.4 L 2 mol KClO3 3 mol O2 122.55 g KClO3 1 mol KClO3 = 32.8 g KClO3 Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Stoichiometry Problems How many grams of KClO3 are required to produce 9.00 L of O2 at STP? 2KClO3  2KCl + 3O2 ? g 9.00 L 32.8 g 1 mol O2 2 mol KClO3 122.55 g KClO3 x g KClO3 = 9.00 L O2 = 32.8 g KClO3 22.4 L O2 3 mol O2 1 mol KClO3 O2 KClO3 Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

How many grams of KClO3 are required to produce 9.00 L of O2 at STP? 2KClO3  2KCl + 3O2 ? g 9.00 L 9.00 L O2 1 mol O2 22.4 L 2 mol KClO3 3 mol O2 122.55 g KClO3 1 mol KClO3 = 32.8 g KClO3 1 mol O2 2 mol KClO3 122.55 g KClO3 32.8 g x g KClO3 = 9.00 L O2 = 32.8 g KClO3 22.4 L O2 3 mol O2 1 mol KClO3 O2 KClO3 Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

How many grams of silver will be formed from 12.0 g copper? Cu + 2 AgNO3  2 Ag + Cu(NO3)2 12.0 g ? g 12.0 g Cu 1 mol Cu 63.55 g Cu 2 mol Ag 1 mol Cu 107.87 g Ag 1 mol Ag = 40.7 g Ag 1 mol Cu 2 mol Ag 107.87 g Ag 40.7 g x g Ag = 12.0 g Cu = 40.7 g Ag 63.55 g Cu 1 mol Cu 1 mol Ag Cu Ag Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem

Mole Calculations A graduated cylinder holds 25.4 cm3 of mercury. If the density of mercury at 25 oC is 13.534 g / cm3, how many moles of mercury are in the cylinder? How many atoms of mercury are there? HINT: Volume of solids/liquids and moles are not directly connected. You must first use the density to convert the volume to a mass, and then derive the quantity of mercury, in moles, from the mass. Finally, the number of atoms is obtained from the number of moles. g cm3 x mol g x atoms mol x Volume, cm3 Mass, g Moles Atoms use density use molar mass use Avogadro’s number Kotz & Treichel, Chemistry & Chemical Reactivity, 3rd Edition , 1996, page 93

A B C g cm3 x mol g x atoms mol x Volume, cm3 Mass, g Moles Atoms use density use molar mass use Avogadro’s number A Therefore, the mass of mercury is found to be equivalent to 344 g of mercury. 25.4 cm3 Hg . 13.534 g Hg 1 cm3 Hg = 344 g Hg 344 g Hg B Knowing the mass, you can now find the quantity in moles. 344 g Hg . 1 mol Hg . 200.6 g Hg = 1.71 mol Hg 1.71 mol Hg C Finally, because you know the relation between atoms and moles (Avogodro’s number), you can now find the number of atoms in the sample. A graduated cylinder holds 25.4 cm3 of mercury. If the density of mercury at 25 oC is 13.534 g / cm3, how many moles of mercury are in the cylinder? How many atoms of mercury are there? 1.71 mol Hg . 6.02 x 1023 atoms Hg . 1 mol Hg = 1.03 x 1024 atoms Hg Kotz & Treichel, Chemistry & Chemical Reactivity, 3rd Edition , 1996, page 93

2 Na + Cl2 2 NaCl 1 mol Na 1 mol Cl2 22.4 L Cl2 x L Cl2 = 100 g Na 2 grams 1 gram 2 grams x L x g W R O N G Violates Law of Conservation of Matter 1 mol Na 1 mol Cl2 22.4 L Cl2 2 atoms 1 molecule 2 molecules* x L Cl2 = 100 g Na = 49 L Cl2 48.69 L 23 g Na 2 mol Na 1 mol Cl2 Na Cl2 2 moles 1 mole 2 moles Right side of room…calculate how many grams of NaCl will be produced from 100 g of Na. 1 mol Na 2 mol NaCl 58.5 g NaCl x g NaCl = 100 g Na = 254 g NaCl 23 g Na 2 mol Na 1 mol NaCl Na http://nobel.scas.bcit.ca/resource/ptable/ptblegif/na.gif http://www.rkm.com.au/imagelibrary/thumbnails/CHLORINE-Cl2-2-150.jpg http://www.scienceclarified.com/images/uesc_03_img0170.jpg NaCl Left side of room…calculate how many grams of NaCl will be produced from 48.69 L of Cl2. 1 mol Cl2 2 mol NaCl 58.5 g NaCl x g NaCl = 48.69 L Cl2 = 254 g NaCl 22.4 L Cl2 1 mol Cl2 1 mol NaCl Cl2 NaCl *Better name would be “formula unit”

Stoichiometry 2 KClO3 2 KCl + O2 3 1 mol KClO3 3 mol O2 22.4 L O2 500 g x g x L (196 g) 1 mol KClO3 3 mol O2 22.4 L O2 x L O2 = 500 g KClO3 = 137 L O2 137 L 122.5 g KClO3 2 mol KClO3 1 mol O2 KClO3 O2 1 mol O2 32 g O2 x g O2 = 137 L O2 = 196 g O2 22.4 L O2 1 mol O2 1 mol KClO3 2 mol KCl 74.5 g KCl x g KCl = 500 g KClO3 = 304 g KCl (304 g) 122.5 g KClO3 2 mol KClO3 1 mol KCl KClO3 KCl

Stoichiometry 2 TiO2 + 4 Cl2 + 3 C CO2 + 2 CO + 2 TiCl4 115 g x g x mol 4.55 mol x molecules How many moles of chlorine will react with 4.55 moles of carbon? 4 mol Cl2 x mol Cl2 = 4.55 mol C = 6.07 mol C 3 mol C C Cl2 How many grams of titanium (IV) oxide will react with 4.55 moles of carbon? 2 mol TiO2 80 g TiO2 x g TiO2 = 4.55 mol C = 243 g TiO2 3 mol C 1 mol TiO2 C TiO2 How many molecules of TiCl4 will react with 115 g TiO2? 1 mol TiO2 2 mol TiCl4 6.02x1023 molecules TiCl4 x molecules TiCl4 = 115 g TiO2 80 g TiO2 2 mol TiO2 1 mol TiCl4 = 8.66x1023 molecules TiCl4 TiO2 TiCl4

30 g aluminum metal or 18 mL distilled water? Which has more atoms: 30 g aluminum metal or 18 mL distilled water? How many atoms of aluminum are in 30 g of aluminum? 1 mol Al 6.02x1023 atoms Al x atoms Al = 30 g Al = 6.69x1023 atoms Al 27 g Al 1 mol Al Al 6.02x1023 atoms Al x atoms Al = 30 g Al = 6.69x1023 atoms Al 27 g Al Al W R O N G How many atoms are in 18 mL of water? H2O 1 L H2O 1 mol H2O 6.02x1023 atoms H2O 6.02x1023 molecules H2O 3 atoms x atoms = 18 mL H2O 1000 mL H2O 22.4 L H2O 1 mol H2O 1 molecule H2O LITERS is ONLY used for GASES @ STP = 1.45x1021 atoms How many atoms are in 18 mL of water? 1 g H2O 1 mol H2O 6.02x1023 molecules H2O 3 atoms x atoms = 18 mL H2O 1 mL H2O 18 g H2O 1 moL H2O 1 molecule H2O Recall, density of water = 1.81x1024 atoms