Titrations Calculations

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Presentation transcript:

Titrations Calculations

What is Titration ? A titration experiment is a scientific procedure designed to determine how concentrated an acid or base is by using the opposite solution. By figuring out how much of the known solution to use, you can find the concentration of the unknown solution.

Titrations Calculations

Titration Calculations - Procedure Gather all the suspects in the one place. Step 1 – Write out the balanced equation for the neutralisation reaction. 2. Establish relationships between the suspects. Step 2 – Determine the “mole ratio” between the alkali and the acid. 3. Split the prime suspects and collect all the known” evidence on each ! Step 3 ACID ALKALI Split the page into two sections. Labelled acid and alkali. Look at the clues to determine the following factors for each side. N = Number of Moles C = Conc in Mol/l V = Volume in Litres.

C V N Titration Calculations - Procedure 4. Having gathered all the evidence it should now be obvious how to solve the case however some final interrogation could be required. ! Step 4 – Use the “mole ratio” to establish the N value for the unknown solution 5. With the final interrogation complete you are now ready to solve the case. Step 5 – Use the triangle to complete the calculation N C V

ALWAYS WRITE THE BALANCED EQUATION FIRST ! Titration Calculations - Example If 25cm3 of a solution of sodium hydroxide is exactly neutralised by 13.5 cm3 of 0.6 mol/l sulphuric acid, what is the concentration of the alkali? ALWAYS WRITE THE BALANCED EQUATION FIRST ! 2 + + 2 NaOH H2S04 Na2SO4 H20 Once you gather all the suspects - Now the “Detective” work starts !!! ACID ALKALI Split the page into two sections. Labelled acid and alkali. Look at the clues to determine the following factors for each side. N = Number of Moles C = Conc in Mol/l V = Volume in Litres.

ALWAYS WRITE THE BALANCED EQUATION FIRST ! Titration Calculations - Example If 25cm3 of a solution of sodium hydroxide is exactly neutralised by 13.5 cm3 of 0.6 mol/l sulphuric acid, what is the concentration of the alkali? ALWAYS WRITE THE BALANCED EQUATION FIRST ! 2 + + 2 NaOH H2S04 Na2SO4 H20 Once you gather all the suspects - Now the “Detective” work starts !!! ACID ALKALI V = 0.0135 Litres V = 0.025 Litres C = 0.6 mol / l C = ? N = ? = C x V = 0.6 x 0.135 = 0.0081 N alkali = 2 x N acid = 2 x 0.0081 = 0.0162

C V N Titration Calculations Concentration For Sodium Hydroxide = N / V 0.0162 = 0.025 = 0.648 Moles / Litre

Now It’s Your Turn to Solve a Few Mysteries C V

Well Done. The Case is Solved.