Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–4) Then/Now New Vocabulary Example 1:Use a Replacement Set Example 2:Standardized Test Example.

Slides:

Advertisements

Similar presentations

Advertisements

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 2–4) Then/Now Example 1:Expressions with Absolute Value Key Concept: Absolute Value Equations.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 3–3) Then/Now New Vocabulary Key Concept: Nonvertical Line Equations Example 1:Slope and y-intercept.

Splash Screen. Then/Now I CAN solve radical equations. Learning Target.

Solve an equation with variables on both sides

Over Lesson 4–3 A.A B.B C.C D.D 5-Minute Check 1 x = -3 Solve x – 3 = –6. Check your solution. Solve y + 9 = 7. Check your solution. y = -2 Solve –13 =

Splash Screen. Lesson 1 Menu Five-Minute Check (over Chapter 6) Main Ideas and Vocabulary California Standards Example 1: Identify Monomials Key Concept:

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 2–1) Then/Now New Vocabulary Key Concept: Addition Property of Equality Example 1: Solve by.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–2) CCSS Then/Now New Vocabulary Example 1: The Distributive Property Key Concept: FOIL Method.

A B C D 10m x – 12 –3r + 63 Simplify the expression 4m + 6m + 3.

Solve Equations with Variables on Both Sides

Over Lesson 1–4. Then/Now You simplified expressions. Solve equations with one variable. Solve equations with two variables.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–4) Then/Now Key Concept: Product Property of Logarithms Example 1:Use the Product Property.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 10–6) Then/Now Example 1: Linear-Quadratic System Example 2: Quadratic-Quadratic System Example.

Warm-up Use the distributive property to rewrite the expression without parentheses. 1.) 8(x + 5)2.) 4(y – 7)3.) (x – 4)(2) 4.) –6(r – 1)5.) (m – 7)( –3)

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 4–3) Then/Now Key Concept: Division Property of Equality Example 1: Solve Equations by Dividing.

Splash Screen. Over Lesson 4–3 5-Minute Check 1 Solve x – 3 = –6. Check your solution. Solve y + 9 = 7. Check your solution. Solve 23 = m – 6. Check your.

Splash Screen. Concept Example 1 Simplify Expressions A. Simplify the expression. Assume that no variable equals 0. Original expression Definition.

Splash Screen. Example 1 Solve a Logarithmic Equation Answer: x = 16 Original equation Definition of logarithm 8 = 2 3 Power of a Power Solve.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–3) Then/Now New Vocabulary Example 1: Solve a Logarithmic Equation Key Concept: Property of.

Lesson 3 Menu Five-Minute Check (over Lesson 10-2) Main Ideas and Vocabulary Targeted TEKS Example 1: Variable in Radical Example 2: Radical Equation with.

Splash Screen. Example 1 Write an Equation Given Roots (x – p)(x – q)=0Write the pattern. Simplify. Replace p with and q with –5. Use FOIL.

1. Simplify 8n n. 2. Use the Distributive Property to evaluate 5(z – 3) + 4z.

Example 1 Solve an Equation with Variables on Each Side Solve 8 + 5c = 7c – 2. Check your solution c = 7c – 2Original equation Answer: c = 5Simplify.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–3) CCSS Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–1) Main Idea and Vocabulary Example 1:Solve Two-Step Equations Example 2:Solve Two-Step Equations.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 7–6) Then/Now New Vocabulary Key Concept: Solving Radical Equations Example 1:Solve Radical.

Over Lesson 1–1 A.A B.B C.C D.D 5-Minute Check 4 A.13 × 8 B C.13 > 8 D.13 – 8 1. Write a numerical expression for thirteen more than eight. A. B.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–4) CCSS Then/Now New Vocabulary Example 1:Use a Replacement Set Example 2:Standardized Test.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–4) CCSS Then/Now New Vocabulary Example 1:Use a Replacement Set Example 2:Standardized Test.

Solve an equation by combining like terms EXAMPLE 1 8x – 3x – 10 = 20 Write original equation. 5x – 10 = 20 Combine like terms. 5x – =

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 5–7) Main Idea and Vocabulary Example 1:Addition Equations Example 2:Subtraction Equations Example.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 2–2) Then/Now New Vocabulary Example 1:Solve Multi-Step Equations Example 2:Real-World Example:

Lesson 5 Menu Five-Minute Check (over Lesson 1-4) Main Ideas and Vocabulary Targeted TEKS Key Concept: Distributive Property Example 1: Distribute Over.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 2–3) Then/Now New Vocabulary Key Concept:Slope-Intercept Form Example 1:Write an Equation in.

Over Lesson 5–1 A.A B.B C.C D.D 5-Minute Check 1 A.P = 14 m; A = 10 m 2 B.P = 10 m; A = 14 m 2 C.P = 14 m; A = 14 m 2 D.P = 10 m; A = 10 m 2 Find the perimeter.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–2) Then/Now New Vocabulary Example 1:Verbal to Algebraic Expression Example 2:Algebraic to.

Splash Screen. Over Lesson 1–4 5-Minute Check 2 A.24x + 5 B.24x + 30 C.10x + 5 D.10x + 30 Simplify 6(4x + 5).

Splash Screen. Lesson Menu Five-Minute Check Then/Now New Vocabulary Key Concept: Order of Operations Example 1:Evaluate Algebraic Expressions Example.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–4) Then/Now New Vocabulary Key Concept: Addition / Subtraction Property of Inequality Example.

Over Lesson 5–3 A.A B.B C.C D.D 5-Minute Check 1 Write an inequality for the sentence. A number decreased by 7 is at most 9. Write an inequality for the.

Splash Screen. Over Lesson 5–4 5-Minute Check 2 Solve the inequality. Show your work and 2 checks. 3t – 5 ≤ 13.

Splash Screen. Over Lesson 5–3 5-Minute Check 1 Over Lesson 5–3 5-Minute Check 2.

Lesson 5 Menu Five-Minute Check (over Lesson 2-4) Main Ideas and Vocabulary Targeted TEKS Example 1: Solve an Equation with Variables on Each Side Example.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 9–1) Then/Now Example 1:LCM of Monomials and Polynomials Key Concept: Adding and Subtracting.

Multiplication Properties of Exponents

Over Lesson 2–3. Splash Screen Then/Now You solved multi-step equations. Solve equations with the variable on each side. Solve equations involving.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 12–2) Main Idea and Vocabulary Example 1:Solve an Equation by Subtracting Example 2:Solve an.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–3) Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression with.

Lesson Menu Five-Minute Check (over Lesson 1–3) CCSS Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression with Absolute.

LESSON 5–6 Graphing Inequalities in Two Variables.

Splash Screen. Then/Now You multiplied polynomials by monomials. Multiply binomials by using the FOIL method. Multiply polynomials by using the Distributive.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 8–2) CCSS Then/Now New Vocabulary Example 1: The Distributive Property Key Concept: FOIL Method.

Splash Screen. Lesson Menu Five-Minute Check (over Lesson 1–3) CCSS Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression.

Over Lesson 5–3 A.A B.B C.C D.D 5-Minute Check 1 Solve and Graph x – 4 > -1 Solve and Graph y + 3 ≤ 6.

Splash Screen Unit 8 Quadratic Expressions and Equations EQ: How do you use addition, subtraction, multiplication, and factoring of polynomials in order.

Recapping Quiz Review your Quiz

Test Chapter 1 TENTATIVELY scheduled for Wednesday, 9/21.

Presentation transcript:

Splash Screen

Lesson Menu Five-Minute Check (over Lesson 1–4) Then/Now New Vocabulary Example 1:Use a Replacement Set Example 2:Standardized Test Example Example 3:Solutions of Equations Example 4:Identities Example 5:Equations Involving Two Variables

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 1 A.110 – 88 B – 8 C.198 D.22 Simplify 11(10 – 8).

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 2 A.24x + 5 B.24x + 30 C.10x + 5 D.10x + 30 Simplify 6(4x + 5).

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 3 A.2d + 16 B.2d + 63 C.18d + 16 D.18d + 63 Simplify (2d + 7)9.

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 4 A.11n + 9 B.9n + 11 C.20n D.20 Simplify 8n n.

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 5 A theater has 176 seats and standing room for another 20 people. Write an expression to determine the number of people who attended 3 performances if all of the spaces were sold for each performance. A.3(176) B.3(176) + 20 C.3( ) D.

Over Lesson 1–4 A.A B.B C.C D.D 5-Minute Check 6 A.9z – 15 B.9z – 3 C.6z D.z – 3 Use the Distributive Property to evaluate 5(z – 3) + 4z.

Then/Now You simplified expressions. (Lesson 1–1through 1–4) Solve equations with one variable. Solve equations with two variables.

Vocabulary open sentence equation solving solution replacement set set element solution set identity

Example 1 Use a Replacement Set Find the solution set for 4a + 7 = 23 if the replacement set is {2, 3, 4, 5, 6}. Replace a in 4a + 7 = 23 with each value in the replacement set. Answer: The solution set is {4}.

A.A B.B C.C D.D Example 1 A.{0} B.{2} C.{1} D.{4} Find the solution set for 6c – 5 = 7 if the replacement set is {0, 1, 2, 3, 4}.

Example 2 Solve 3 + 4(2 3 – 2) = b. A 19B 27C 33D 42 Read the Test ItemYou need to apply the order of operations to the expression to solve for b. Solve the Test Item 3 + 4(2 3 – 2) = b Original equation 3 + 4(8 – 2) = b Evaluate powers (6) = b Subtract 2 from 8.

Example = b Multiply 4 by = b Add. Answer: The correct answer is B.

A.A B.B C.C D.D Example 2 A.1 B. C. D.6

Example 3A Solutions of Equations A. Solve 4 + ( ) ÷ n = ( ) ÷ n = 8 Original equation 4 + (9 + 7) ÷ n = 8 Evaluate powers. Answer: This equation has a unique solution of 4. 4n + 16=8n Multiply each side by n. 16=4n Subtract 4n from each side. 4=n Divide each side by 4. Add 9 and 7.

Example 3B Solutions of Equations B. Solve 4n – (12 + 2) = n(6 – 2) – 9. 4n – (12 + 2)=n(6 – 2) – 9 Original equation 4n – 12 – 2=6n – 2n – 9 Distributive Property 4n – 14 =4n – 9 Simplify. No matter what value is substituted for n, the left side of the equation will always be 5 less that the right side of the equation. So, the equation will never be true. Answer: Therefore, there is no solution of this equation.

A.A B.B C.C D.D Example 3A A.f = 1 B.f = 2 C.f = 11 D.f = 12 A. Solve (4 2 – 6) + f – 9 = 12.

A.A B.B C.C D.D Example 3B B. Solve 2n – 29 = (2 3 – 3 2)n A. B. C.any real number D.no solution

Example 4 Identities Solve (5 + 8 ÷ 4) + 3k = 3(k + 32) – 89. (5 + 8 ÷ 4) + 3k=3(k + 32) – 89 Original equation (5 + 2) + 3k=3(k + 32) – 89 Divide 8 by k=3(k + 32) – 89Add 5 and k=3k + 96 – 89Distributive Property 7 + 3k=3k + 7Subtract 89 from 96. No matter what real value is substituted for k, the left side of the equation will always be equal to the right side of the equation. So, the equation will always be true. Answer: Therefore, the solution of this equation could be any real number.

A.A B.B C.C D.D Example 4 A.d = 0 B.d = 4 C.any real number D.no solution Solve d – (2 8) = (3 2 – 1 – 2)d + 48.

Example 5 Equations Involving Two Variables GYM MEMBERSHIP Dalila pays $16 per month for a gym membership. In addition, she pays $2 per Pilates class. Write and solve an equation to find the total amount Dalila spent this month if she took 12 Pilates classes. The cost for the gym membership is a flat rate. The variable is the number of Pilates classes she attends. The total cost is the price per month for the gym membership plus $2 times the number of times she attends a Pilates class. c = 2p + 16

To find the total cost for the month, substitute 12 for p in the equation. Example 5 Equations Involving Two Variables c = 2p + 16Original equation c = 2(12) +16Substitute 12 for p. c = Multiply. c = 40Add 24 and 16. Answer: Dalila’s total cost this month at the gym is $40.

A.A B.B C.C D.D Example 5 A.c = ; $51.25 B.c = 9.25j + 42; $97.50 C.c = (42 – 9.25)j; $ D.c = 42j ; $ SHOPPING An online catalog’s price for a jacket is $ The company also charges $9.25 for shipping per order. Write and solve an equation to find the total cost of an order for 6 jackets.

End of the Lesson