Capacitance Chapter 26

Electric Potential of Conductors The electric field E is zero within a conductor at equilibrium. E=0 V1V1 V2V2

Electric Potential of Conductors The electric field E is zero within a conductor at equilibrium. Consequently the conductor has the same electric potential V everywhere inside. E=0 V1V1 V2V2

Electric Potential of Conductors The electric field E is zero within a conductor at equilibrium. Consequently the conductor has the same electric potential V everywhere inside. E=0 V1V1 V2V2

Electric Potential of Conductors The electric field E is zero within a conductor at equilibrium. Consequently the conductor has the same electric potential V everywhere inside. The electric potential depends on how much excess charge has been added to the metal. The relationship between these quantities defines the capacitance. E=0 V1V1 V2V2

Capacitance A capacitor consists of two pieces of metal carrying equal and opposite charges Q and –Q.

Capacitance A capacitor consists of two pieces of metal carrying equal and opposite charges Q and –Q. An electric potential difference V develops between the two pieces of metal.

Capacitance A capacitor consists of two pieces of metal carrying equal and opposite charges Q and –Q. An electric potential difference V develops between the two pieces of metal. It turns out that Q and V are proportional. The constant of proportionality is called the capacitance C.

Q = CV [Units: Coulomb /Volt = Farad] Capacitance A capacitor consists of two pieces of metal carrying equal and opposite charges Q and –Q. An electric potential difference V develops between the two pieces of metal. It turns out that Q and V are proportional. The constant of proportionality is called the capacitance C.

Q = CV [Units: Coulomb /Volt = Farad] Capacitance A capacitor consists of two pieces of metal carrying equal and opposite charges Q and –Q. An electric potential difference V develops between the two pieces of metal. It turns out that Q and V are proportional. The constant of proportionality is called the capacitance C. The capacitance C depends on the size and shape of the capacitor, and the material (if any) between them.

Parallel Plate Capacitor -Q +Q d A

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Parallel Plate Capacitor -Q +Q d A

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Parallel Plate Capacitor -Q +Q d A E

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Gauss’s law Parallel Plate Capacitor -Q +Q d A E

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Gauss’s law Parallel Plate Capacitor -Q +Q d A E

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Gauss’s law gives EA=Q/  0 so E=Q/  0 A. Parallel Plate Capacitor -Q +Q d A E

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Gauss’s law gives EA=Q/  0 so E=Q/  0 A. The potential difference between the two plates is ∆V=∫E·dl = Ed or ∆V = Qd/  0 A. Parallel Plate Capacitor -Q +Q d A E

The charge on the top and bottom plates attract so that the it all ends up on the inner facing surfaces. These have surface charge density  with  =Q/A. Gauss’s law gives EA=Q/  0 so E=Q/  0 A. The potential difference between the two plates is ∆V=∫E·dl = Ed or ∆V = Qd/  0 A. Turning this about gives Q = (  0 A/d)∆V i.e. Q=C∆V with C=  0 A/d. Parallel Plate Capacitor -Q +Q d A E

Q=C∆V with C=  0 A/d The capacitance is like the capacity of the object to hold charge. Bigger C means the object can hold more charge (at a given ∆V). The capacitance is proportional to the area A (more capacity) and inversely proportional to the separation d (smaller ∆V=Ed for given Q). Parallel Plate Capacitor -Q +Q d A E

How Do You Get Q and -Q? Q-Q

Move Q from one plate to the other. How? How Do You Get Q and -Q? Q-Q

Move Q from one plate to the other. How? With a gadget that pushes charge – for instance, a battery. How Do You Get Q and -Q? + - Q-Q

Move Q from one plate to the other. How? With a gadget that pushes charge – for instance, a battery. Hooked to metal plates, a 1.5 Volt battery moves charge until the potential difference between the plates is also 1.5 V. How Do You Get Q and -Q? + - Q-Q

A battery is like a charge escalator. With just a wire between the plates, the charges making up Q would repel each other and run through the wire to neutralize -Q. But the battery pushes the charges “uphill.” How Do You Get Q and -Q? + - Q-Q Q

Thinking About Capacitors V The black lines are metal wires attached to metal rods. Suppose the battery has been hooked up for a long time so that it has finished pushing charge and the system has come to equilibrium.

What is ∆V 12 ? What is ∆V 34 ? What is ∆V 23 ? Thinking About Capacitors V The black lines are metal wires attached to metal rods. Suppose the battery has been hooked up for a long time so that it has finished pushing charge and the system has come to equilibrium.

What is ∆V 12 ? Zero What is ∆V 34 ? Zero What is ∆V 23 ? 6V Thinking About Capacitors V The black lines are metal wires attached to metal rods. Suppose the battery has been hooked up for a long time so that it has finished pushing charge and the system has come to equilibrium.

More About Capacitors + - What is ∆V 12 ? What is ∆V 23 ? What is ∆V 34 ? V Now hook the battery to a parallel plate capacitor. 3 3 mm

More About Capacitors + - What is ∆V 12 ? Zero What is ∆V 23 ? Zero What is ∆V 34 ? 6V V Now hook the battery to a parallel plate capacitor. 3 3 mm

More About Capacitors + - What is ∆V 12 ? Zero What is ∆V 23 ? Zero What is ∆V 34 ? 6V What is E at point 5? V Now hook the battery to a parallel plate capacitor. 3 3 mm

More About Capacitors + - What is ∆V 12 ? Zero What is ∆V 23 ? Zero What is ∆V 34 ? 6V What is E at point 5? E = 6V/(3x10 -3 m) = 2000 V/m V Now hook the battery to a parallel plate capacitor. 3 3 mm

More About Capacitors V 3 3 mm Now suppose you pull the plates apart slightly while keeping the battery attached. What happens to ∆V, Q, and E?

More About Capacitors + - ∆V depends on the battery: it stays at 6V V 3 3 mm Now suppose you pull the plates apart slightly while keeping the battery attached. What happens to ∆V, Q, and E?

More About Capacitors + - ∆V depends on the battery: it stays at 6V. Use Q=C∆V. Here C=  0 A/d decreases so Q decreases V 3 3 mm Now suppose you pull the plates apart slightly while keeping the battery attached. What happens to ∆V, Q, and E?

More About Capacitors + - ∆V depends on the battery: it stays at 6V. Use Q=C∆V. Here C=  0 A/d decreases so Q decreases. E= ∆V / (new length) gets smaller V 3 3 mm Now suppose you pull the plates apart slightly while keeping the battery attached. What happens to ∆V, Q, and E?

What Does a Capacitor Do? Stores electrical charge. Stores electrical energy. Capacitors are used when a sudden release of energy is needed (such as in a photographic flash). Capacitors are basic elements of electrical circuits both macroscopic (as discrete elements) and microscopic (as parts of integrated circuits).

What Does a Capacitor Do? Stores electrical charge. Stores electrical energy. The charge is easy to see. If a certain potential, ∆V, is applied to a capacitor C, it must store a charge Q=C∆V: ∆V∆V -Q+Q C (Symbol for a capacitor)

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q.

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q. When the charge is q the potential is V=q/C.

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q. When the charge is q the potential is V=q/C. Now transfer a little more charge dq.

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q. When the charge is q the potential is V=q/C. Now transfer a little more charge dq. This requires a work dW = Vdq = (1/C) q dq.

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q. When the charge is q the potential is V=q/C. Now transfer a little more charge dq. This requires a work dW = Vdq = (1/C) q dq. Integrating q from 0 to Q gives the total stored (potential) electric energy:

Energy Stored in a Capacitor Build the charge up a little at a time, letting the charge q on the plate grow from 0 to Q. When the charge is q the potential is V=q/C. Now transfer a little more charge dq. This requires a work dW = Vdq = (1/C) q dq. Integrating q from 0 to Q gives the total stored (potential) electric energy:

Look at an energy density, i.e., energy per unit volume. For the parallel plate capacitor the volume is Ad, so u E = U/(Ad) = (1/2 C∆V 2 )/Ad Now also use C =   A/d. Then Energy Density +Q -Q ∆V u E = (    ∆V/d) 2 = (    

This leads to another way to understand the energy. We can think of the energy as stored in the FIELD, rather than in the plates. If an electric field exists, then you can associate an electric potential energy density of (      Energy Density +Q -Q V u E = (    ∆V/d) 2 = (    