Cost Issues Y.Sugimoto, A.Maki 2008.09.12. Estimation Procedure Get unit cost from the cost estimation for GLD(DOD) Estimate (relative) amount of return-yoke.

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Presentation transcript:

Cost Issues Y.Sugimoto, A.Maki

Estimation Procedure Get unit cost from the cost estimation for GLD(DOD) Estimate (relative) amount of return-yoke iron which gives same leakage field for 3T, 3.5T, and 4T models Calculate volume or weight of components (CAL and return yoke) of GLDc, and scale it to 3T and 4T model Derive the cost for 3 models, 3T, 3.5T,4T GLD  GLDc (3.5T)  3T and 4T models

Unit Cost of GLD Return-yoke iron –500 k\/ton Solenoid –50.3 M\/(MJ) ECAL –8.87 G\/20.8m 3 = 426 M\/m 3 HCAL –3.39 G\/222m 3 = 15.2 M\/m 3

Return-yoke Iron Good iron (S10C) is used for GLD –High saturation field –As strong as standard iron –Low remanence (Br) and coercivity (Hc)  Field in the gaps is very small at I=0A, and gaps can be partially filled with iron

Return-yoke Iron B-field calculation based on simple models for 3, 3.5, and 4T with various iron thickness Maximum stray field at R=Rdet+1m was obtained as a function of iron thickness Thickness which give the 300G stray field was obtained for each central B-field Relative volume of iron and relative stored energy with respect to 3.5T case are used for the cost estimation 4T3.5T3T Coil radius (m) Coil length (m) Barrel inner radius (m) End-cap Z (m)

Return-yoke Iron Maximum stray field at R=Rdet+1m Simplified model Necessary volume is almost same for 3 cases Iron thickness (m)

Detector Parameters GLD3T3.5T (GLDc) 4T BR ECAL Volume (m 3 ) HCAL Volume (m 3 ) Yoke Iron (ton)1.66e+41.13e+41.12e+41.11e+4 Stored Energy (GJ) Note R CAL =1.6, 1.85, 2.1m for 4T,3.5T,3T, respectively ECAL thickness: 20cm HCAL thickness: 1.2m for GLD, 1.1m for others

Cost (M\)GLD3T3.5T4T Vertex Det1700 Si Inner Tracker4902 TPC3036 ECAL HCAL Muon Det3992 Small Angle Det500 Solenoid Return Yoke MDI824 Total Relative cost DAQ system and off-line computing not included

Cost Cost normalized by BR 2 (M\)

Cost with different assumption Different unit cost for ECAL and HCAL –ECAL: 426 M\/m 3  700 M\/ m 3 –HCAL: 15.2 M\/ m 3  50 M\/ m 3 (M\)GLD3T3.5T4T Vertex Det1700 Si Inner Tracker4902 TPC3036 ECAL HCAL Muon Det3992 Small Angle Det500 Solenoid Return Yoke MDI824 Total Relative cost

Cost with different assumption Cost Cost normalized by BR 2 (M\)

Conclusions Very rough cost estimation is made for GLDc (~GLD’) 3.5T detector based on GLD cost estimate, and scaled to 3T and 4T GLDc-like models Difference between 3.5T model and 3 or 4T model is rather small ~+-5% with GLD assumption, and ~+-10% for more expensive CAL assumption If normalized by BR 2, larger R CAL detector is less expensive There are many discrepancies in cost estimation of each items. Once the ILD parameters are fixed, sub-detector experts of GLD and LDC should talk to each other to give agreed unit costs.

Backup Slides Slides from my talk at GLD/LDC meeting in LCWS2007

Why is GLD large? How much iron do we need? –B-field calculation based on a toy model using a FEA program was done –BR 2, t ECAL, t HCAL, G1, G2; fixed –Leakage field at Z=10 m was estimated as a function of B, and t Fe –t Fe to satisfy the leakage limit of 100G was obtained for each B

Leakage B-field GLD-like –BR 2 =13.23 –t ECAL =0.17m –t HCAL =1.23m –G1=G2=0.5m t Fe (m) B Z=10m Leakage limit Andrei put the limit to 50G, but 100G can be reduced to <50G by low cost Helmholtz coil

Leakage B-field LDC-like –BR 2 =10.24 –t ECAL =0.17m –t HCAL =1.13m –G1=0.46m –G2=0.49m t Fe (m) B Z=10m

Leakage B-field SiD-like –BR 2 =8.06 –t ECAL =0.13m –t HCAL =1.09m –G1=0.21m –G2=0.63m t Fe (m) B Z=10m

B and R R (m) B (T) GLD-likeLDC-likeSiD-like For a given BR 2, larger B (smaller R CAL ) gives larger detector size

B and Cost GLD-like detector model Unit cost assumption –ECAL: 6.8M$/m 3 –HCAL: 0.16M$/m 3 –Fe: 42k$/m 3 –Solenoid: 0.523x[Estore] M$ B (T) Cost (M$) B-field dependence of the total cost (CAL+Sol.+Fe) is very small

Summary GLD is the largest detector among the three PFA detectors GLD is the largest NOT because it has the largest inner radius of the calorimeter, but because it has the largest BR 2, the thickest HCAL, and the smallest leakage field