Ch. 1-5 Absolute Value Equations and Inequalities

Ex. 1: Solve | 15 – 3x | = 6 | 15 – 3x | = 6 15 – 3x = 6 15 – 3x = x = -9-3x = -21 x = 3 x = 7

Solve Check understanding 1 p. 33

Ex. 2: 4 – 2|x + 9| = -5 4 – 2|x + 9| = |x + 9| = -9

Ex. 3 cont. -9 x = -4.5 x = -13.5

Solve check understanding 2 p. 34

Ex. 3: Solve |3x – 4| = -4x - 1 3x – 4 = -4x – 1 3x – 4 = 4x x 7x – 4 = x = 3 -3x -4 = x + 1 x = -5

When there is a variable outside of the absolute value, you must check your answers. | 3(-5) – 4 | = -4(-5) -1 | -15 – 4 | = | -19 | = = 19 x = -5 Solution Not a solution

Solve check understanding 3A and 3B, p. 34

Ex. 4: Solve | 2x – 5 | > 3. Graph the solution. 2x – 5 > 3 2x – 5 < x > 8 x > x < 2 x < 1

Solve check understanding 4 p. 35

Ex. 5: Solve -2| x + 1 | + 5 > -3 -2| x + 1| + 5 > | x + 1| > -8 | x + 1| < 4

Ex. 5 cont. x + 1 < 4 x + 1 > -4 x < 3 x > -5

Solve check understanding 5 p. 35

Ex. 6: The area A in square inches of a square photo is required to satisfy 8.5 < A < 8.9. Write this requirement as an absolute value inequality. Find the tolerance. Find the average of the maximum and minimum values Write the inequality -.2 < A – 8.7 <.2 Rewrite as an absolute value inequality | A – 8.7 | <.2

Homework p. 36 – 37 # 1 – 53 eoo