Equilibrium Systems ‘in balance’ o Static Equilibrium  Balanced Forces  Balanced Moments  Centre of Gravity o Dynamic Equilibrium  Constant Linear.

Slides:



Advertisements
Similar presentations
Angular Quantities Correspondence between linear and rotational quantities:
Advertisements

Chapter 9 Objectives Calculate the torque created by a force.
Mechanics of Rigid Body. C
Lecture 15 Rotational Dynamics.
Dynamics of Rotational Motion
Chapter 9 Rotational Dynamics.
Physics Montwood High School R. Casao
A 40-kg mass placed 1.25 m on the opposite side of the support point balances a mass of 25 kg, placed (x) m from the support point of a uniform beam. What.
Foundations of Physics
Rolling, Torque, and Angular Momentum Rolling: Translation and Rotation Friction and Rolling Yo-yo Torque: A Cross Product Angular Momentum Newton’s Second.
Chapter 9 Rotational Dynamics.
Torque and Equilibrium Lecture 8 Pre-reading : KJF §8.1 and 8.2.
Rotational Dynamics and Static Equilibrium. Torque From experience, we know that the same force will be much more effective at rotating an object such.
Chapter 8 Rotational Equilibrium and Rotational Dynamics.
Chapter 8 Rotational Equilibrium and Rotational Dynamics.
Rotational Dynamics Chapter 9.
MHS Physics Department AP Unit I E 2 Torque and rotational statics.
Objectives  Know the definition of torque  Know that torque is directly proportional to the magnitude of the force and the perpendicular distance.
Last Lecture Review 1 Two horizontal forces act on a block that is sliding on ice. Assume that a third horizontal force F also acts on the block. What.
Chapter 12: Rolling, Torque and Angular Momentum.
Chapter Eight Rotational Dynamics Rotational Dynamics.
Chapter 8 Rotational Equilibrium and Rotational Dynamics.
Rotational Dynamics Angular Momentum. Collisions. o Rotational Dynamics  Basic Concepts Rotation Angular speed Torque Angular Acceleration  Nature of.
Angular Momentum Angular momentum of rigid bodies
Rotation about a fixed axis
Chapter 8: Torque and Angular Momentum
Physics 1210/1310 Mechanics& Thermodynamics Thermodynamics Lecture R1-7 Rotational Motion.
Chapter 9: Rotational Dynamics
Torque Chap 8 Units: m N 2.
Copyright © 2010 Pearson Education, Inc. Lecture Outline Chapter 11 Physics, 4 th Edition James S. Walker.
KEY KNOWLEDGEKEY SKILLS  The different parts that make up levers including the axis, force and resistance arms and how they relate to movements  How.
Chapter 8 Rotational Dynamics and Static Equilibrium
When the axis of rotation is fixed, all particles move in a circle. Because the object is rigid, they move through the same angular displacement in the.
Equations for Projectile Motion
Two blocks (m 1 =2.5kg, m 2 =1.8kg) are hanging from a pulley as shown in the figure below. The moment of inertia through the axis of rotation passing.
Biomechanical Principles and Applications. Some Important Terms Equilibrium: a 'perfect' situation where more than one force acts on a body but, because.
Chapter 10 Chapter 10 Rotational motion Rotational motion Part 2 Part 2.
MOMENTUM l Momentum is a measure of motion =“magnitude of motion”, “impetus”, “impulse” p = m  v rate of change of momentum = force: if no force acts,
Rotational Motion. 6-1 Angular Position, Velocity, & Acceleration.
BB101 ENGINEERING SCIENCE
Rotational Dynamics and Static Equilibrium
Motion, Forces and Simple Machines Chapter 5. Section 1- Motion.
Chapter 9 Rotational Dynamics.
Rotational Motion About a Fixed Axis
Chapter 9 Rotational Dynamics
R F F F F MOMENT of FORCE = F x r.
AQUINAS DIOCESAN GRAMMAR Moments Double Award - Physics calculate the moment of a force as force times perpendicular distance form the pivot describe.
Torque and Equilibrium
Physics 207: Lecture 17, Pg 1 Lecture 17 (Catch up) Goals: Chapter 12 Chapter 12  Introduce and analyze torque  Understand the equilibrium dynamics of.
1/15/16Oregon State University PH 212, Class 61 Here are some of the direct analogies between (linear) translational and rotational motion: Quantity or.
Loads & Forces. L1 L2 F2 F1 F1 x L1 = F2 x L2 F1 = (L2 x F2) L1 Formula for calculating load.
Chapt. 10: Angular Momentum
Understand the principles of statics Graphical vectors Triangle of forces theorem Parallelogram of forces theorem Concept of equilibrium
Today: (Ch. 8)  Rotational Motion.
Chapter 8 Rotational Motion and Equilibrium. Units of Chapter 8 Rigid Bodies, Translations, and Rotations Torque, Equilibrium, and Stability Rotational.
UNIT 6 Rotational Motion & Angular Momentum Rotational Dynamics, Inertia and Newton’s 2 nd Law for Rotation.
Application of Forces Learning Objectives:
Goals for Chapter 10 To learn what is meant by torque
Forces Glossary The centre of gravity of an object is the point at which the weight of the object can be said to act. © Mike Benn, Graham George 2016.
College Physics, 7th Edition
Angular Momentum.
Rotational Inertia and Torque
Rotational Dynamics Chapter 9.
Wednesday: Review session
Lecture Outline Chapter 11 Physics, 4th Edition James S. Walker
Lecture Outline Chapter 11 Physics, 4th Edition James S. Walker
Dynamics of Rotational Motion
Moments.
Moment of a force or Torque
Biomechanical Principles and Applications
Presentation transcript:

Equilibrium Systems ‘in balance’ o Static Equilibrium  Balanced Forces  Balanced Moments  Centre of Gravity o Dynamic Equilibrium  Constant Linear Momentum  Constant Angular Momentum

o Aim of the lecture  Concepts in Static Equilibrium Force balance Moments Moment balance  Force Amplification Use of levers Simple Pulley  Concepts in Dynamic Equilibrium Constant momentum Constant angular momentum o Main learning outcomes  familiarity with  Moments  Levers  Centre of Mass for a system  Equilibrium Lecture 9

Moments To move the world, Archimedes needed a lever To move a large mass: o Use a large force OR o A small force + lever

Moments The force needed to lift the load (effort) x D = The load x d The pivot point is called a fulcrum d D

Moments F D The MOMENT of the force F about the pivot P is D x F Moment = DF P

This is a simple lever, it is used to Amplify a force

The same effect can be achieved in other ways: Note that in this case:  The force amplification is less than 1  The distance travelled by the load is greater than the force

d D F To lift 1kg: DdF 50cm30cm1kg  9.81  30 / 50 Newtons = 5.9N 1m20cm1kg  9.81  20 / 100 Newtons = 2.0N 2km1cm1kg  9.81  1 / Newtons = 4.9x10 -5 N Which is the lever a fruit fly would need! A 1kg weight makes a 9.81N force

But not much movement in mass And not very practical either A 2km lever would be very heavy Especially for a fruit fly Distance 1kg moves Distance fruit fly moves 1cm 2km = 0.1mm 20m

o Note that energy is conserved: Force x distance 1kg moves = Force fruit fly uses x distance fruit fly moves Work Done on 1kg mass = Work done by fruit fly Levers not always practical Same principle apply to pulleys

o In these  The A force moves 1m o L moves 1m/4 = 25cm o Max load = 4f  The B force moves 1m o L moves 1m/5 = 20cm o Max load = 5f The usual form is a ‘block and tackle’ o Several pulley wheels next to each other oThe amplification factor is The number of supporting ropes Excluding the one being pulled

Moments and Torques oTwo moments acting on one body such that: The total force is zero The total moment is not zero o Produce a torque [see earlier] F F d d This is a torque of value  = 2dF The pivot ‘does nothing’ BUT this is NOT a pure torque because the pivot point will also be applying a force to the lever. CAREFUL! This is not completely obvious

Centre of Gravity The 10 balls act as if they were a single mass Acting at one distance along the lever. The single distance is directly below the centre of gravity An extended mass, or a collection of masses can often be represented by a single mass equal to the total mass located at one point the point is called the centre of gravity.

Centre of gravity To balance the centre of gravity must be above the support point.

r1r1 r2r2 r3r3 R = (m 1 r 1 +m 2 r 3 +m 3 r 3 ) m 1 +m 2 +m 3 R is the position of the centre of gravity R

Static Equilibrium Is when The (vector) sum of forces is zero moments is zero momentum is zero angular momentum is zero

d 1 d 2 F1F1 F2F2 o d 1 F 1 = d 2 F 2 for equilibrium  Or lever will rotate  Even if the two forces are equal Equilibrium in Moments

d 1 d 2 F1F1 F2F2 o d 1 F 1 = d 2 F 2 for equilibrium Equilibrium in Torque (and Force) Consider the same situation FpFp o Also F p = F 1 + F 2 (to prevent translation of lever  F i =0) oAbout Rod centre of gravity  Anticlockwise moment is = F 1 (d 1 + d cog ) = F 2 d 2 + F 1 d cog  Clockwise moment = (F 1 + F 2 )d cog +(d 2 - d cog )F 2 = F 2 d 2 +F 1 d cog o So NO Torque – equilibrium in moments and in Torque are the same thing o (when any forces from the pivot are considered) Centre of gravity for the rod (same as centre of mass) d cog

Static Equilibrium DO NOT try this at home

Dynamic Equilibrium A spinning gyroscope has angular momentum But it does not change magnitude (no friction case) This is a form of dynamic equilibrium The axis of the gyroscope will precess around the direction of gravity, but the magnitude of the total angular momentum will not change. (this means the axis will rotate around at a constant angular speed) [a calculation is beyond the scope of this course] Momentum and angular momentum do not need to be zero

The term ‘dynamic equilibrium’ can also refer to any situation in which the properties relevant to describing the system do not change, even if the parts making up the system do, or are moving. o Eg Water vapour is in dynamic equilibrium with the liquid water it is above. Molecules are constantly exchanged between vapour and liquid But the total number in the liquid (and gas) remains constant o A rotating Ferris wheel is in dynamic equilibrium. o A static Ferris wheel is in static equilibrium. o As it accelerates from static to rotating it is neither.