Applications of Proportions

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Presentation transcript:

Applications of Proportions 1-9 Applications of Proportions Holt Algebra 1 Warm Up Lesson Presentation Lesson Quiz Holt McDougal Algebra 1

Warm Up Evaluate each expression for a = 3, b = –2, c = 5. 1. 4a – b 2. 3b2 – 5 3. ab – 2c Solve each proportion. 4. 5. 14 7 16 9 6.4

Similar figures have exactly the same shape but not necessarily the same size. Corresponding sides of two figures are in the same relative position, and corresponding angles are in the same relative position. Two figures are similar if and only if the lengths of corresponding sides are proportional and all pairs of corresponding angles have equal measures.

When stating that two figures are similar, use the symbol ~ When stating that two figures are similar, use the symbol ~. For the triangles above, you can write ∆ABC ~ ∆DEF. Make sure corresponding vertices are in the same order. It would be incorrect to write ∆ABC ~ ∆EFD. You can use proportions to find missing lengths in similar figures.

Example 1A: Finding Missing Measures in Similar Figures Find the value of x the diagram. ∆MNP ~ ∆STU M corresponds to S, N corresponds to T, and P corresponds to U. 6x = 56 Use cross products. Since x is multiplied by 6, divide both sides by 6 to undo the multiplication. The length of SU is cm.

Example 1B: Finding Missing Measures in Similar Figures Find the value of x the diagram. ABCDE ~ FGHJK 14x = 35 Use cross products. Since x is multiplied by 14, divide both sides by 14 to undo the multiplication. x = 2.5 The length of FG is 2.5 in.

You can solve a proportion involving similar triangles to find a length that is not easily measured. This method of measurement is called indirect measurement. If two objects form right angles with the ground, you can apply indirect measurement using their shadows.

If every dimension of a figure is multiplied by the same number, the result is a similar figure. The multiplier is called a scale factor.

Example 3B: Changing Dimensions Every dimension of a rectangular prism with length 12 cm, width 3 cm, and height 9 cm is multiplied by to get a similar rectangular prism. How is the ratio of the volumes related to the ratio of the corresponding dimensions? Prism A Prism B V = lwh (12)(3)(9) = 324 (4)(1)(3) = 12 The ratio of the volumes is the cube of the ratio of the corresponding dimensions.

Helpful Hint A scale factor between 0 and 1 reduces a figure. A scale factor greater than 1 enlarges it.