REDOX REACTIONS Oi L Oxidation is L osing electrons (becomes more positive) Ri G Reduction is G aining electrons (becomes less positive) Cu(s) + 2AgNO.

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Presentation transcript:

REDOX REACTIONS Oi L Oxidation is L osing electrons (becomes more positive) Ri G Reduction is G aining electrons (becomes less positive) Cu(s) + 2AgNO 3 (aq)  Cu(NO 3 ) 2 (aq) + 2Ag(s) Put in charges and look at changes 02+ more positive ( L ost e - s) Cu is oxidized from 0 to Less positive ( G ained e - s) Ag 1+ is reduced from 1+ to 0 Cu is the reducing agent and AgNO 3 is the oxidizing agent

MgC 2 O 4 H 2 SO 4 H 2 SO 3 Cr 2 O 7 2- Assign oxidation numbers for each element below Co(NO 3 ) 2

MgC 2 O 4 H 2 SO 4 H 2 SO 3 Cr 2 O 7 2- Assign oxidation numbers for each element below Co(NO 3 ) 2 x = +3 (the assigned charge for carbon in this compound) x = +6 (the assigned charge for sulfur in this compound) x = +4 (the assigned charge for sulfur in this compound) x = +6 (the assigned charge for chromium in this compound) x = +5 (the assigned charge for nitrogen in this compound)

2 MnO (s) + 5 PbO 2 (s) + 10 HNO 3 (aq) → 2 HMnO 4 (aq) + 5 Pb(NO 3 ) 2 (aq) + 4 H 2 O (l) ______ is oxidized from a ______ charge to a ________ charge. _______ is reduced from a ______ charge to a ________ charge. _______ ____ is the reducing agent. ____________ is the oxidizing agent.

2 MnO (s) + 5 PbO 2 (s) + 10 HNO 3 (aq) → 2 HMnO 4 (aq) + 5 Pb(NO 3 ) 2 (aq) + 4 H 2 O (l) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) ____________ is the reducing agent. ____________ is the oxidizing agent More positive (Lost electrons) OiL Mn Less positive (Gains electrons) RiG Pb MnO PbO 2

Fe (s) + FeCl 3 (aq) → FeCl 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. _______ is reduced from a ______ charge to a ________ charge ____________ is the reducing agent. ____________ is the oxidizing agent.

Fe (s) + FeCl 3 (aq) → FeCl 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) _______ ____ is the reducing agent. ____________ is the oxidizing agent Fe 0+2 Fe Fe FeCl 3

Cu (s) + 4 HNO 3 (aq) → 2 NO 2 (g) + 2 H 2 O (l) + Cu(NO 3 ) 2 (aq) ______ is oxidized from a ______ charge to a ________ charge. (OiL) _______ is reduced from a ______ charge to a ________ charge. (RiG) ____________ is the reducing agent. ____________ is the oxidizing agent Cu N Cu HNO 3