Exponential Functions and Half-Lives Radioactive isotopes and geochronology methods use exponential functions to date rock samples. You're on an outcrop.

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Presentation transcript:

Exponential Functions and Half-Lives Radioactive isotopes and geochronology methods use exponential functions to date rock samples. You're on an outcrop wondering what is the age of this stratigraphic section.....Do you know your exponents ? Angular unconformity in Cody, Wyoming NE Hudson Bay Canada, 4.28 Ba

Exponential Functions and Half-Lives While structural principles of superposition and fossil identification can give you relative age dates Absolute ages are obtained by studying radioactive decay Angular unconformity in Cody, Wyoming

Exponential Functions and Half- Lives What is a half-life ? If you start with eight million atoms of a parent isotope (P), how many P isotopes will you have after decay of P to D (daughter isotopes) in one half-life of 1000 yrs ? After 2000 yrs, how many parent isotopes will you have ? Hudson Bay amphibole with abundant garnet

Exponential Functions and Half- Lives After 3000 years, you have 1 million parent isotopes This is 1/8 of the original amount After 9000 years, you have atoms, 1/1024 (or 0.1%) The succession of fractions are shown above.

Exponential Functions and Half- Lives What is the equation that corresponds to this graph ? P = P o (1/2) t t 1/2

Exponential Functions and Half- Lives P = P o (1/2) t t 1/2 P is the number of parent atoms remaining After elapsed time, t P o is the number of parent atoms at the start t 1/2 is the half-life for a particular isotope

Exponential Functions and Half- Lives P = P o (1/2) t t 1/2 What is in the exponent, ? This gives the number of half-lives which have ellapsed during the time, t. So for a half-life of 1000 yrs, after 1000 yrs have passed: = 1, which is one half-life. t t 1/2 t What is this exponent after 3000 years ?

Exponential Functions and Half- Lives P = P o (1/2) t t 1/2 The (1/2) in the parenthesis – represents “half-lives”. If we wanted to know when a third of the initial population of atoms decayed to a daughter atom, then this would be (1/3). In this case, the exponent would be: If you rearrange, P/Po is the remaining parents after one half- life. t t 1/3

The Exponential Function If we take the logarithm of both sides of this equation : P = P o (1/2) t t 1/2 ln P = ln P o + ln (1/2) t t 1/2 ln P = ln P o - ln (2) t t 1/2

The Exponential Function What in this equation is a constant ? ln P = ln P o - ln (2) t t 1/2 The constants are: ln (2) and t 1/2 Let's describe this ratio with one letter, = ln(2) / t 1/2 What are the units of  ? The dimensions of  are time -1.

The Exponential Function ln P = ln P o -  t. Then substituting, we get Can we now get rid of the ln ? Raise the left and right side the power of e : P = P o e - t Does this look more familiar ? This is the traditional expression for exponential decay.

The Exponential Decay P = P o e - t What about this equation describes decay ? Time (yrs) Population of Parent Isotopes

The Exponential Growth P = P o e t How could we describe exponential growth ? Time (yrs) Population of Parent Isotopes

The Exponential Growth Oil is usually pumped by natural pressure or water pressure More than 50% of known oil reserves cannot be recovered by these conventional means because water does not pump oil efficiently. Low viscosity water “fingers” through high viscosity oil fluids The theory of “viscous fingering” predicts exponential growth of fingering instabilities – and and can become chaotic Displacement of mineral oil by water

The Exponential Growth in the Earth's Mantle Linear gravity anomalies observed in the Pacific ocean Have been investigated as viscous fingers of plume material traveling through the asthenosphere. Sandwell, 2008 Weeraratne et al., 2003

Leonard Euler ( ) Leonard Euler was most prolific mathematician of all time (lived during the time of Benjamin Franklin ( ) Born in Basel, Switzerland, completed university at age 15 By 1771, Euler was nearly completely blind and dictated his calculations to a note taker and published 70 volumes! Euler established the branch of mathematics known as “analysis” (e.g. calculus, complex variables, potential theory)

Leonard Euler ( ) In three Latin texts and famous Introductio, he introduced the concept of a function. As well as the modern concept of a logarithm, and exponential function

Euler's e and e x Where does e come from ? Let x be an infinitely large number, e be infinitely small Then N = x / e is an infinitely large number. x = N e We know that a o = 1, then is e is just a number then, a e = 1 + k e We can expand and use binomial series to get a x = 1 + k x /1! + k 2 x 2 /2! + k 3 x 3 /3! +...

Euler's e and e x a x = 1 + k x /1! + k 2 x 2 /2! + k 3 x 3 /3! +... Summing 10 terms for “kx = 1” gives = “e” Coined by Euler himself

Euler's e and e x a x = 1 + k x /1! + k 2 x 2 /2! + k 3 x 3 /3! +... If we let a = e, when k = 1 we get: e x = 1 + x/1! + x 2 /2! + x 3 /3! What happens if we take the derivative of this function ? d/dx (e x ) = 1 + x/1! + x 2 /2! + x 3 /3!

Euler's e and e x d/dx (e x ) = 1 + x/1! + x 2 /2! + x 3 /3! becomes d/dx (e x ) = e x The derivative of the exponential becomes the exponential

Euler's e and e x d/dx (e x ) = e x The derivative of the exponential becomes the exponential What does this mean to us ? If y = Ae a x Then dy/dx = a Ae a x or dy/dx = a y This means that the rate of change of y is proportional to the amount y that is present

The Exponential Function P = P o e t Exponential growth is also a geometric progression These equations pair geometric and arithmetic progressions The independent variable, t, increases arithmetically While the dependent variable, P, increases geometrically Changes in P are controlled by incremental increase in t and the rate constant, l. arithmetic geometric

The Exponential Function P = P o e t These equations are variations of the general form y = e x This equation is unique among functions ! The derivative of e x returns itself, e x. How does this work ?