 Pick up knowledge organizer and objectives  Attach objectives in notebook  Take out labs from Monday & Tuesday

Reaction Stoichiometry

 1 cake mix + 3 eggs + 1 cup water  1 cake  We can create ratios out of this:  These can be used as conversion factors 1 cake mix-to 1 cake 3 eggs-to-1 cake 1 cup water-to-3 eggs 1 cake mix 3 eggs 1 cup water 1 cake 1 cake 3 eggs (remember you can flip these conversion factors when necessary)

 To determine:  how much of the other reactants are needed  how much of each product should be produced  limiting reactants

 If you have 6 eggs how many cakes can you make?  If you add 4 cups of water how many cake mixes will you need?  If you have 2 cake mixes, 3 cups of water and 5 eggs, how many cakes can you make? Why not more? 6 eggs x 1 cake = 2 cakes 3 eggs 4 cups water x 1 cake mix = 4 cake mixes 1 cup water 1 and 2/3 cake. You are limited by the number of eggs you have. Only have enough for 1 2/3 cakes.

2 H 2 + O 2  2 H 2 O Coefficients can represent moles in balanced reactions. 2 moles of hydrogen burn with 1 mole of oxygen to form 2 moles of water.

2 H 2 + O 2  2 H 2 O Possible mole ratios/ conversion factors: 2 H 2 -to-1 O 2 2 mol H 2 1 mol O 2 2 H 2 O-to-2H 2 2 mol H 2 O 2 mol H 2 2 H 2 O-to-1 O 2 2 mol H 2 O 1 mol O 23 others exist

2 2 mol HgO 1 mol O 2 10 mol HgO X 1 mol O 2 = 5 mol O 2 2 mol HgO

 2HgO  2Hg + O 2 1) What is the mole ratio between HgO and Hg?  2) If you start with 10 moles of HgO, how many moles of Hg would you make? 2 mol HgO 2 mol Hg 10 mol HgO X 2 mol Hg = 10 mol Hg 2 mol HgO

 If you start with 100 g of HgO how many moles of O 2 would be formed in the reaction? 100 g HgO X 1 mol HgO X 1 mol O 2 = 0.23 mol O g HgO 2 mol HgO

 If you start with 20.7 g of HgO how many moles of Hg would be formed in the reaction?

g O 2 X 1 mol O 2 X 2 mol HgO X g HgO =135.4 g HgO 32 g O 2 1 mol O 2 1 mol HgO

 H 2 SO 4 + 2NaOH  Na 2 SO 4 + 2H 2 O  How many moles of NaOH do you need to react with 1.00 mole of H 2 SO 4 ?  How many moles of NaOH do you need to react with 32.7 moles H 2 SO 4 ? 32.7 mol H 2 SO 4 X 2 mol NaOH = 65.4 mol NaOH 1 mol H 2 SO mol H 2 SO 4 X 2 mol NaOH = 2.00 mol NaOH 1 mol H 2 SO 4

 H 2 SO 4 + 2NaOH  Na 2 SO 4 + 2H 2 O  How many moles of H 2 SO 4 do you need to react with 20.0 g NaOH?  How many grams of Na 2 SO 4 will be produced if 27.6 g NaOH is reacted with excess H 2 SO 4 ? 2O.0 g NaOH X 1 mol NaOH X 1 mol H 2 SO 4 = mol H 2 SO g NaOH 2 mol NaOH 27.6 g NaOH X 1 mol NaOH X 1 mol Na 2 SO 4 X g Na 2 SO 4 = 49.0 g Na 2 SO g NaOH 2mol NaOH 1 mol Na 2 SO 4