Splash Screen

Lesson Menu Five-Minute Check (over Lesson 2–4) Then/Now New Vocabulary Key Concept: Scatter Plots Example 1:Real-World Example: Use a Scatter Plot and Prediction Equation Example 2:Real-World Example: Regression Line

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 1 A. B. C. D. Write an equation in slope-intercept form for the line with slope =, passing through (0, 1).

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 2 A. B. C. D. Write an equation in slope-intercept form for the line with slope = –1, passing through

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 3 What is the slope-intercept form of 4x + 8y = 11? A.4x + 8y – 11 = 0 B.y = 4x – 11 C. D.

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 4 A.6x – y = 7 B.y = –6x + 7 C.x – 7y = 1 D.y = x + 7 Write an equation in slope-intercept form of a line that passes through (1, 1) and (0, 7).

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 5 A.y = 35x + 65 B.65 = 35x + y C.y = 65x + 35 D.total = 35x + 65y A plumber charges a flat fee of $65, and an additional $35 per hour for a service call. Write an equation that represents the charge y for a service call that lasts x hours.

Over Lesson 2–4 A.A B.B C.C D.D 5-Minute Check 5 What is the equation of a line that passes through the point (6, –4) and is perpendicular to the equation A.e B.e C.e D.e

Then/Now You wrote linear equations. Use scatter plots and prediction equations. Model data using lines of regression.

Vocabulary bivariate dataregression line correlation coefficient scatter plot dot plot positive correlation negative correlation line of fit prediction equation

Concept

Example 1A Use a Scatter Plot and Prediction Equation A. EDUCATION The table below shows the approximate percent of students who sent applications to two colleges in various years since Make a scatter plot of the data and draw a line of fit. Describe the correlation.

Example 1A Use a Scatter Plot and Prediction Equation Graph the data as ordered pairs, with the number of years since 1985 on the horizontal axis and the percentage on the vertical axis. Answer: The data show a strong negative correlation. The points (3, 18) and (15, 13) appear to represent the data well. Draw a line through these two points.

Example 1B Use a Scatter Plot and Prediction Equation B. Find a prediction equation. What do the slope and y-intercept indicate? Find an equation of the line through (3, 18) and (15, 13). Begin by finding the slope. Slope formula Substitute. Simplify.

Example 1B Use a Scatter Plot and Prediction Equation Point-slope form Substitute. Distributive Property Simplify.

Example 1B Use a Scatter Plot and Prediction Equation The slope indicates that the percent of students sending applications to two colleges is falling about 0.4% each year. The y-intercept indicates that the percent in 1985 should have been about 19%. Answer: One prediction equation is

Example 1C Use a Scatter Plot and Prediction Equation C. Predict the percent of students who will send applications to two colleges in The year 2010 is 25 years after 1985, so use the prediction equation to find the value of y when x = 25. x = 25 Prediction equation Answer: The model predicts that the percent in 2010 should be about 8.83%. Simplify.

Example 1D Use a Scatter Plot and Prediction Equation D. How accurate is this prediction? Answer: Except for the point at (6, 15), the line fits the data well, so the prediction value should be fairly accurate.

Example 1A A. SAFETY The table shows the approximate percent of drivers who wear seat belts in various years since Which shows the best line of fit for the data?

A.A B.B C.C D.D Example 1A A.B. C.D.

A.A B.B C.C D.D Example 1B B. The table and scatter plot show the approximate percent of drivers who wear seat belts in various years since What is a good prediction equation for this data? Use the points (6, 71) and (12, 81). A. B. C. D.

A.A B.B C.C D.D Example 1C C. The table and scatter plot show the approximate percent of drivers who wear seat belts in various years since Predict the percent of drivers who will be wearing seat belts in A.83% B.87% C.90% D.95%

A.A B.B C.C D.D Example 1D D. The table and scatter plot show the approximate percent of drivers who wear seat belts in various years since How accurate is the prediction? A.There are no outliers so it fits very well. B.Except for the one outlier the line fits the data very well. C.There are so many outliers that the equation does not fit very well. D.There is no way to tell.

Example 2 Regression Line INCOME The table shows the median income of U.S. families for the period 1970–2002. Use a graphing calculator to make a scatter plot of the data. Find an equation for and graph a line of regression. Then use the equation to predict the median income in Use a graphing calculator to make a scatter plot of the data. Find an equation for and graph a line of regression. Then use the equation to predict the attendance in 2015.

Example 2 Regression Line Step 1 Make a scatter plot. Enter the years in L1 and the income in L2. Set the viewing window to fit the data. Use STAT PLOT to graph the scatter plot. Step 2 Find the equation of the line of regression. Find the regression equation by selecting LinReg(ax + b) on the STAT CALC menu. The regression equation is about y = x – 2,650, The slope indicates that the income increases at a rate of about 1350 people per year. The correlation coefficient r is 0.997, which is very close to 1. So, the data fit the regression line very well.

Example 2 Regression Line Step 3 Graph the regression equation. Copy the equation to the Y = list and graph. Notice that the regression line comes close to most of the data points. As the correlation coefficient indicated, the line fits the data well.

Example 2 Regression Line Step 4 Predict using the function. Find y when x = Use VALUE on the CALC menu. Reset the window size to accommodate the x-value of Answer:According to the function, the median income in 2015 will be about $69,220 people.

A.A B.B C.C D.D Example 2 A.y = –15.75x + 31,890.25; about 154 seconds B.y = –14.75x + 29,825.67; about 104 seconds C.y = –14.6x + 29,604.72; about 186 seconds D.y = –14.95x + 30,233.25; about 99 seconds The table shows the winning times for an annual dirt bike race for the period 2000–2008. Use a graphing calculator to make a scatter plot of the data. Find and graph a line of regression. Then use the function to predict the winning time in 2015.

End of the Lesson