Applying Factoring Chapter 10. Solve.  (x – 3)(x – 4) = 0.

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Presentation transcript:

Applying Factoring Chapter 10

Solve.  (x – 3)(x – 4) = 0.

Solve.  (x – 3)(x – 4) = 0.

Solve  x 2 + 5x + 6 = 0

Solve  x 2 + 5x + 6 = 0

Solve.  x 2 – 3 = 2x

Solve.  x 2 – 3 = 2x

Solve.  (x + 2)(x + 3) = 12

Solve.  (x + 2)(x + 3) = 12

Simplify.  (2x 2 - 4) - (x 2 + 3x - 3)

Simplify.  (2x 2 - 4) - (x 2 + 3x - 3)

Factor.  9y

Factor.  9y

Solve.  x 2 – 5x = 0

Solve.  x 2 – 5x = 0

Simplify.  (3x 2 - 4x + 6) - (-2x 2 - 3x - 9)

Simplify.  (3x 2 - 4x + 6) - (-2x 2 - 3x - 9)

Solve.  x 2 – 4 = 0

Solve.  x 2 – 4 = 0

Simplify.  (4x 2 – 4x – 7)(x + 3)

Simplify.  (4x 2 – 4x – 7)(x + 3)

Factor  3x 2 - 5x - 2

Factor  3x 2 - 5x - 2

Solve.  (x – 5) 2 – 100 = 0

Solve.  (x – 5) 2 – 100 = 0

Simplify.  –3x(4x 2 – x + 10)

Simplify.  –3x(4x 2 – x + 10)

Factor.  5m m - 6

Factor.  5m m - 6

Solve.  The room that is shown in the figure below has a floor space of 2x² + x - 15 square feet. If the width of the room is (x + 3) feet, what is the length? x + 3

Solve.  The room that is shown in the figure below has a floor space of 2x² + x - 15 square feet. If the width of the room is (x + 3) feet, what is the length? x + 3

Solve.  x 2 +3x = 0

Solve.  x 2 +3x = 0

Simplify.  (3x 3 + 3x 2 – 4x + 5) + (x 3 – 2x 2 + x – 4)

Simplify.  (3x 3 + 3x 2 – 4x + 5) + (x 3 – 2x 2 + x – 4)

Solve.  2x 2 – 6 = x

Solve.  2x 2 – 6 = x

Solve.  2x(x+1) = 7x – 2

Solve.  2x(x+1) = 7x – 2

 Homework Homework