Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low 1 1 3-5 L.

Slides:

Advertisements

Similar presentations

Solving Equations Learning Outcomes  Manipulate and simplify simple expressions including removal of brackets  Solve linear equations, with or without.

Advertisements

For Educational Use Only © 2010 Benchmark 10 I can solve absolute value equations.

A BC D E Answer.

Problem Set # 4 Maximize f(x) = 3x1 + 2 x2 subject to x1 ≤ 4 x1 + 3 x2 ≤ 15 2x1 + x2 ≤ 10 Problem 1 Solve these problems using the simplex tableau. Maximize.

Technical Question Technical Question

EXAMPLE 4 Solve proportions SOLUTION a x 16 = Multiply. Divide each side by 10. a x 16 = = 10 x5 16 = 10 x80 = x8 Write original proportion.

EXAMPLE 4 Solve proportions SOLUTION a x 16 = Multiply. Divide each side by 10. a x 16 = = 10 x5 16 = 10 x80 = x8 Write original proportion.

Algebra Foundations Box Factoring or acb Method x 2 - 4x + 4 x2x2 4.

Introduction To Equation Solving. xx 2x + 1 = 4 Solve :

Solving quadratic equations Factorisation Type 1: No constant term Solve x 2 – 6x = 0 x (x – 6) = 0 x = 0 or x – 6 = 0 Solutions: x = 0 or x = 6 Graph.

EXAMPLE 3 Solve an equation by factoring Solve 2x 2 + 8x = 0. 2x 2 + 8x = 0 2x(x + 4) = 0 2x = 0 x = 0 or x + 4 = 0 or x = – 4 ANSWER The solutions of.

Prime Factors. What are they? All composite numbers can be written as the product of prime numbers. This product is known as the prime factorisation of.

EQUATIONS This presentation accompanies the worksheet: “Simple equations” available at:

7-5 Logarithmic & Exponential Equations

7.6 – Solve Exponential and Log Equations

Solving Quadratic Equations by Factoring

Algebra I Chapter 10 Review

Solving equations Section 1.4.

Notes - Solving Quadratic Equations in Factored Form If ab = 0, then a = 0 or b = 0 If the product of two factors is zero, then at least one of the factors.

Solving Quadratic Equations by Factoring. Solution by factoring Example 1 Find the roots of each quadratic by factoring. factoring a) x² − 3x + 2 b) x².

6.2 Polynomials and Linear Functions

5.4 – Solving Compound Inequalities. Ex. Solve and graph the solution.

Set Operations and Compound Inequalities. 1. Use A = {2, 3, 4, 5, 6}, B = {1, 3, 5, 7, 9}, and C = {2, 4, 6, 8} to find each set.

© T Madas Trial and Improvement. © T Madas Find the solution of x 2 + 2x = 39 to 1 decimal place, given that x lies between 5 and 6. too high

Algebra Solving Linear Equations 3 x = 6 x = 2 Change side,change sign.

Инвестиционный паспорт Муниципального образования «Целинский район»

6.6 Solving Radical Equations. Principle of power: If a = b then a n = b n for any n Question: Is it also true that if a n = b n then a = b? Explain in.

(x – 8) (x + 8) = 0 x – 8 = 0 x + 8 = x = 8 x = (x + 5) (x + 2) = 0 x + 5 = 0 x + 2 = x = - 5 x = - 2.

FACTOR to SOLVE 1. X 2 – 4x X 2 – 17x + 52 (x-10)(x + 6) x = 10, -6 (x-4)(x - 13) x = 4,13.

EXAMPLE 1 Solve by equating exponents Rewrite 4 and as powers with base Solve 4 = x 1 2 x – 3 (2 ) = (2 ) 2 x – 3x – 1– 1 2 = 2 2 x– x + 3 2x =

The Product Rule Jordan Hammond. Definition/Steps to Solving The Product Rule takes the derivative of a product. It is used with equations with two or.

EXAMPLE 1 Find a normal probability SOLUTION The probability that a randomly selected x -value lies between – 2σ and is the shaded area under the normal.

Solving a quadratic by factorisation 6x 2 + 7x – 3 = 0 ac = -18 b = 7 Factors are: , , +2 -9, , , Correct pair adding to.

(x+2)(x-2).  Objective: Be able to solve equations involving rational expressions.  Strategy: Multiply by the common denominator.  NOTE: BE SURE TO.

SECONDARY ONE 6.1a Using Substitution to Solve a System.

How do you check for extraneous solutions? -=. In this lesson you will learn to identify extraneous solutions in rational equations by checking solutions.

Properties of Addition and Multiplication. Commutative Property  Commute or move around  Changing the order of the numbers in the problem does not change.

x + 5 = 105x = 10  x = (  x ) 2 = ( 5 ) 2 x = 5 x = 2 x = 25 (5) + 5 = 105(2) = 10  25 = 5 10 = = 10 5 = 5.

3 ( x + 2 ) = 3 x ( 3 x - 5 ) = 6x - 10 x x x - 5 M May.

4.3 Solving Systems of Linear Inequalities 11/7/12.

照片档案整理一、照片档案的含义二、照片档案的归档范围三、卷内照片的分类、组卷、排序与编号四、填写照片档案说明五、照片档案编目及封面、备考填写六、数码照片整理方法七、照片档案的保管与保护.

공무원연금관리공단 광주지부 공무원대부등 공적연금 연계제도 공무원연금관리공단 광주지부. 공적연금 연계제도 국민연금과 직역연금 ( 공무원 / 사학 / 군인 / 별정우체국 ) 간의 연계가 이루어지지 않고 있 어 공적연금의 사각지대가 발생해 노후생활안정 달성 미흡 연계제도 시행전.

Жюль Верн ( ). Я мальчиком мечтал, читая Жюля Верна, Что тени вымысла плоть обретут для нас; Что поплывет судно громадней «Грейт Истерна»; Что.

Objective: Use factoring to solve quadratic equations. Standard(s) being met: 2.8 Algebra and Functions.

מאת: יעקב דדוש. פיסול –בין יחיד לרבים יחידה 1 לתלמיד המתבונן לפניך שתי יצירות פיסוליות. התבונן וכתוב (בשקופית הבאה) מהם ההבדלים בין הפסלים המוצגים לפניך?

Substitution Method: Solve the linear system. Y = 3x + 2 Equation 1 x + 2y=11 Equation 2.

Greatest Common Factor

Using Variable Domain Functions

Quadratic Equations.

8.6 Multiplying a Polynomial by a Monomial

Notes Over 9.6 An Equation with One Solution

Solving Equations by Factoring and Problem Solving

Absolute Value inequalities

First and last name D E P T O F L First and last name A B R Y M

Bellwork Solve by graphing y < x + 2 y > -1/2x + 5.

Notes Over 1.7 Solving Inequalities

Notes Over 1.7 Solving Inequalities

POWER CHALLENGES Several Ways To Solve 7 CHALLENGES.

One more Lection.

3.5 Solving Nonlinear Systems

Solving Systems by Substitution

Give the solution to each inequality.

Objective SWBAT solve polynomial equations in factored form.

Intersection Method of Solution

Hosted by Type your name here

Greatest Common Factor

Presentation transcript:

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L H

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L H L

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L H L L

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L H L L H

Solve x 2 +3x – 5 = 11 xx2x2 +3x-5X 2 +3x-5High/ Low L H L L H L Solution lies between 2.75 and 2.8X=2.8