: CATHY JONES Secondary Math Instruction Specialist Center for Mathematics and Science Education Arkansas NASA Education Resource Center 346 N. West Avenue, Room 202 Fayetteville, Arkansas (479) (479) (FAX) info/ Presented by: Related Activities for End-of-Course Algebra I
Part I Simplifying radicals: NUTSHELL MATH Independent & Dependent Variables: AIMS Proportional Reasoning…Mystery Mass Slope and Parallel & Perpendicular Line: Modeling Mathematics Perpendicular Lines on a Coordinate Plane Slope Activity Solving Quadratics: Solving Quadratic Equations with Algebra Tiles Geometric Patterns: Building Algebraic Thinking with Progressive Pattern
From AIMS Find the MASS of your objects using INDIRECT measurement. Complete your MYSTERY MASS table. Construct your graphs. Be sure to label and number the axes. Graph a line for each of the two pans. Be sure to show if the data is discrete or continuous. Complete the worksheets.
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Factor 2x 2 + 5x + 3 Using algebra tiles, build a rectangle containing the tiles specified in this problem: 2…x 2 -tiles, 5…x-tiles and 3…1-tiles. Here is one possible arrangement: After the pattern is established, it can be seen that the top edge of the pattern (the length) is composed of tiles with dimensions 2x + 3. The side edge of the pattern (the width) is composed of tiles with dimensions x + 1. Consequently, 2x 2 + 5x + 3 = (2x + 3)(x + 1). Factoring with Algebra Tiles Key: - x x
From Developing Concepts Using Algebra Tiles Solve x 2 – 6x – 4 = 3 Choose the tiles to set up the problem and place them in a square, if possible. Use 1…x 2 tile, 6…-x tiles, and 4…-1 tiles. Here is one arrangement: The square on the left is incomplete. The 4…-1 tiles do not complete the square model. Add 4…+1 tiles to both sides of the equation. The ones on the left now are ZERO, so remove them. Now add enough +1 tiles on the left to complete the square model. Add the same to the right of the equal sign to also make a square. Solving Quadratic Equations with Algebra Tiles - x - X = - x x Across the bottom see that –x + 3 = 4 and down the right side see that –x + 3 = 4. To the right of the equal sign is 4 2 but it could also be (-4) 2 so solve both equations: -x + 3 = 4 and –x + 3 = -4. Solution: x = -1 or x =