Holt Geometry 5-6 Inequalities in Two Triangles 5-6 Inequalities in Two Triangles Holt Geometry Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson Quiz Lesson Quiz

Holt Geometry 5-6 Inequalities in Two Triangles Warm Up 1. Write the angles in order from smallest to largest. 2. The lengths of two sides of a triangle are 12 cm and 9 cm. Find the range of possible lengths for the third side. X, Z, Y 3 cm < s < 21 cm

Holt Geometry 5-6 Inequalities in Two Triangles Apply inequalities in two triangles. Objective

Holt Geometry 5-6 Inequalities in Two Triangles

Holt Geometry 5-6 Inequalities in Two Triangles Example 1A: Using the Hinge Theorem and Its Converse Compare mBAC and mDAC. Compare the side lengths in ∆ABC and ∆ADC. By the Converse of the Hinge Theorem, mBAC > mDAC. AB = AD AC = AC BC > DC

Holt Geometry 5-6 Inequalities in Two Triangles Example 1B: Using the Hinge Theorem and Its Converse Compare EF and FG. By the Hinge Theorem, EF < GF. Compare the sides and angles in ∆EFH angles in ∆GFH. EH = GH FH = FH mEHF > mGHF mGHF = 180° – 82° = 98°

Holt Geometry 5-6 Inequalities in Two Triangles Example 1C: Using the Hinge Theorem and Its Converse Find the range of values for k. Step 1 Compare the side lengths in ∆MLN and ∆PLN. By the Converse of the Hinge Theorem, mMLN > mPLN. LN = LN LM = LP MN > PN 5k – 12 < 38 k < 10 Substitute the given values. Add 12 to both sides and divide by 5.

Holt Geometry 5-6 Inequalities in Two Triangles Example 1C Continued Step 2 Since PLN is in a triangle, mPLN > 0°. Step 3 Combine the two inequalities. The range of values for k is 2.4 < k < 10. 5k – 12 > 0 k < 2.4 Substitute the given values. Add 12 to both sides and divide by 5.

Holt Geometry 5-6 Inequalities in Two Triangles Check It Out! Example 1a Compare mEGH and mEGF. Compare the side lengths in ∆EGH and ∆EGF. FG = HG EG = EG EF > EH By the Converse of the Hinge Theorem, mEGH < mEGF.

Holt Geometry 5-6 Inequalities in Two Triangles Check It Out! Example 1b Compare BC and AB. Compare the side lengths in ∆ABD and ∆CBD. By the Hinge Theorem, BC > AB. AD = DC BD = BD mADB > mBDC.

Holt Geometry 5-6 Inequalities in Two Triangles Example 2: Travel Application John and Luke leave school at the same time. John rides his bike 3 blocks west and then 4 blocks north. Luke rides 4 blocks east and then 3 blocks at a bearing of N 10º E. Who is farther from school? Explain.

Holt Geometry 5-6 Inequalities in Two Triangles Example 2 Continued The distances of 3 blocks and 4 blocks are the same in both triangles. The angle formed by John’s route (90º) is smaller than the angle formed by Luke’s route (100º). So Luke is farther from school than John by the Hinge Theorem.

Holt Geometry 5-6 Inequalities in Two Triangles Check It Out! Example 2 When the swing ride is at full speed, the chairs are farthest from the base of the swing tower. What can you conclude about the angles of the swings at full speed versus low speed? Explain. The  of the swing at full speed is greater than the  at low speed because the length of the triangle on the opposite side is the greatest at full swing.

Holt Geometry 5-6 Inequalities in Two Triangles Lesson Quiz: Part I 1. Compare mABC and mDEF. 2. Compare PS and QR. mABC > mDEF PS < QR

Holt Geometry 5-6 Inequalities in Two Triangles Lesson Quiz: Part II 3. Find the range of values for z. –3 < z < 7