What is the formula for finding heat? What are the two units of heat? The temperature of a sample of iron with a mass of 10.0 g changed from 50.4 o C to 25.0 o C. If the specific heat of iron is J/g x o C, how much heat was released? A 4.50 g nugget of pure gold absorbed 276 J of heat. What was the final temperature of the gold if the initial temperature was 25 o C? The specific heat of gold is J/(g x o C).
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Calorimeter Uses insulated material to measure heat absorbed or released. Usually has water in it Can determine specific heats Whatever heat is gained by the water, it is lost by the substance in the water
Thermochemistry- study of heat changes that accompany chemical reactions and phase changes Two parts are changing in a reaction system and surroundings Universe = system + surroundings Ex. Hand warmers If exothermic, heat is a product If endothermic, heat is a reactant
the heat content of a system at constant pressure Cant actually measure the actual energy or enthalpy of a substance but you can measure change ΔH rxn = H products – H reactants Exothermic = negative (released to the surroundings) Endothermic (absorbed by the system) = postive Written: 4Fe + 3O 2 2Fe 2 O kJ 4Fe + 3O 2 2Fe 2 O 3 ΔH rxn = kJ q= ΔH rxn
Can not just rely on exo and endo to tell Ex. CH 4 +2O 2 CO 2 + H 2 O ΔH rxn = -891 kJ Molecules would rather exists in a high state of disorder (called entropy) Second law of thermodynamics entropy in spontaneous process will always increase Entropy = ΔS (products – reactants) If entropy increases, ΔS is positive Ex. Water changing from solid to liquid to gas Ex. Decrease in temperature
Can use the Gibbs free energy equation to determine if a reaction will be spontaneous ΔG system = ΔH system – TΔS system Temp in Kelvin, H in Joules If G is negative- reaction is spontaneous If G is positive- reaction is nonspontaneous Ex. For a process, ΔH sys = 145 kJ and ΔS sys = 322 J/K. Is the process spontaneous at 382 K?
Determine if the following process is spontaneous or nonspontaneous: ΔH sys = kJ, T = 273 K, ΔS sys = 138 J/K Is it an endothermic reaction or exothermic?
Atoms, ions, and molecules must collide in order to react Only a small fraction of particles actually collide Must collide in the correct orientation Once they collide, they make an intermediate molecule called an activated complex exist in the transition state Must also have the right amount of energy (called activation energy) If a reaction has a high E a, few collision low E a, high collisions
Exothermic- molecules collide with enough energy to overcome the E a and produce products at a lower energy level Endothermic- reactants lie at a low energy level and must absorb energy to overcome the E a.