Geometry Grab your clicker and get ready for the warm-up
The distance from a point to a line can be called the “” distance 1.Parallel 2.Vertical 3.Perpendicular 4.Circumcenter 5.Bisector
A point on a perpendicular bisector is from the two endpoints of the bisected segment 1.Equidistant 2.Perpendicular 3.Corresponding 4.Centroid 5.Midpoint
A point on an angular bisector is equidistant from the two of the angle 1.Angles 2.Vertices 3.Right Angles 4.Sides 5.Incenters
The point of concurrency for the perpendicular bisectors of a triangle is called the 1.Incenter 2.Orthocenter 3.Midpoint 4.Circumcenter 5.Centroid 6.Midsegment
The point of concurrency for the angular bisectors of a triangle is called the 1.Incenter 2.Orthocenter 3.Midpoint 4.Circumcenter 5.Centroid 6.Midsegment
A median of a triangle goes from the vertex to the of the opposite side 1.Circumcenter 2.Angle 3.Perpendicular 4.Centroid 5.Side 6.Midpoint 7.Orthocenter
The point of concurrency for the medians of a triangle is called the 1.Incenter 2.Orthocenter 3.Midpoint 4.Circumcenter 5.Centroid 6.Midsegment
An altitude goes from a vertex and is to the opposite side 1.Circumcenter 2.Angle 3.Perpendicular 4.Centroid 5.Side 6.Midpoint 7.Orthocenter
The point of concurrency for the altitudes of a triangle is called the 1.Incenter 2.Orthocenter 3.Midpoint 4.Circumcenter 5.Centroid 6.Midsegment
The circumcenter of a triangle is equidistant from the 1.Vertices 2.Incenter 3.Centroid 4.Perpendicular 5.Sides
The incenter of a triangle is equidistant from the 1.Vertices 2.Incenter 3.Centroid 4.Perpendicular 5.Sides
The Pythagorean Theorem for this right triangle would state: 1.a 2 + b 2 = c 2 2.f 2 + g 2 + h 2 = f 2 + g 2 = h 2 4.h 2 + g 2 = f 5.g 2 + h 2 = 90 6.g 2 + h 2 = f 2 7.g 2 – h 2 = f
Given C is the centroid and that XC = 8, determine CK
Given C is the centroid and that CZ = 3, determine CJ Not possible 7.None of the above
Given C is the centroid and that YI = 15, determine YC Not possible 10.None of the above