Division of Polynomials Digital Lesson. Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 2 Dividing Polynomials Long division of polynomials.

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Presentation transcript:

Division of Polynomials Digital Lesson

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 2 Dividing Polynomials Long division of polynomials is similar to long division of whole numbers. dividend = (quotient divisor) + remainder The result is written in the form: quotient + When you divide two polynomials you can check the answer using the following:

Copyright © by Houghton Mifflin Company, Inc. All rights reserved Example: Divide & Check Example: Divide x 2 + 3x – 2 by x – 1 and check the answer. x x 2 + x 2x2x– 2 2x + 2 – 4– 4 remainder Check: correct (x + 2) quotient (x + 1) divisor + (– 4) remainder = x 2 + 3x – 2 dividend Answer: x – 4– 4

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 4 Example: Divide & Check Example: Divide 4x + 2x 3 – 1 by 2x – 2 and check the answer. Write the terms of the dividend in descending order. 1. x2x2 2. 2x 3 – 2x x22x2 + 4x 4. + x 5. 2x 2 – 2x 6. 6x6x – x – Check: (x 2 + x + 3)(2x – 2) + 5 = 4x + 2x 3 – 1 Answer: x 2 + x Since there is no x 2 term in the dividend, add 0x 2 as a placeholder.

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 5 Example: Division With Zero Remainder x x 2 – 2x – 3x + 6 – 3 – 3x Answer: x – 3 with no remainder. Check: (x – 2)(x – 3) = x 2 – 5x + 6 Example: Divide x 2 – 5x + 6 by x – 2.

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 6 Example: Division With Nonzero Remainder Example: Divide x 3 + 3x 2 – 2x + 2 by x + 3 and check the answer. x2x2 x 3 + 3x 2 0x20x2 – 2x – 2 – 2x – 6 8 Check: (x + 3)(x 2 – 2) + 8 = x 3 + 3x 2 – 2x + 2 Answer: x 2 – Note: the first subtraction eliminated two terms from the dividend. Therefore, the quotient skips a term. + 0x

Copyright © by Houghton Mifflin Company, Inc. All rights reserved Synthetic Division Synthetic division is a shorter method of dividing polynomials. This method can be used only when the divisor is of the form x – a. It uses the coefficients of each term in the dividend. Example: Divide 3x 2 + 2x – 1 by x – 2 using synthetic division. 3 2 – 1 2 Since the divisor is x – 2, a = Bring down 3 2. (2 3) = (2 + 6) = 8 4. (2 8) = (–1 + 16) = 15 coefficients of quotient remainder value of a coefficients of the dividend 3x + 8Answer: 15

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 8 Remainder Theorem Remainder Theorem: The remainder of the division of a polynomial f (x) by x – k is f (k). Example: Using the remainder theorem, evaluate f(x) = x 4 – 4x – 1 when x = – 4 – The remainder is 68 at x = 3, so f (3) = 68. You can check this using substitution:f(3) = (3) 4 – 4(3) – 1 = 68. value of x

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 9 Factor Theorem Factor Theorem: A polynomial f(x) has a factor (x – k) if and only if f(k) = 0. Example: Show that (x + 2) and (x – 1) are factors of f(x) = 2x 3 + x 2 – 5x – 5 2 – 2 2 – 4 – 31 – 2 0 The remainders of 0 indicate that (x + 2) and (x – 1) are factors. – 1 2 – – 10 The complete factorization of f is (x + 2)(x – 1)(2x – 1).