Outline Intro to Population Ecology Estimating Patterns of Survival Survivorship Curves Age Distribution Rates of Population Change –Overlapping Generations Dispersal –In Response to Climate Change –In Response to Changing Food Supply
Readings Table 10.1, p. 263 Table 10.2, p. 264 Life Histories, pp
Population Dynamics Fundamental Equation: N (t+1) = N (t) + B – D + I – E N (t+1) - N (t) = B – D + I – E = N = B – D + I – E I E D B
Estimating Patterns of Survival Three main methods of estimation: –Cohort life table Identify individuals born at same time and keep records from birth.
Estimating Patterns of Survival Three main methods of estimation: –Static life table Record age at death of individuals.
Estimating Patterns of Survival Three main methods of estimation: –Age distribution Calculate difference in proportion of individuals in each age class. Assumes differences from mortality.
Cohort vs Static Life Tables
High Survival Among the Young Murie collected Dall Sheep skulls, Ovis dalli –Major Assumption: Proportion of skulls in each age class represented typical proportion of individuals dying at that age Reasonable given sample size of 608
High Survival Among the Young –Constructed survivorship curve Discovered bi-modal mortality –<1 yr –9-13 yrs
Survivorship Curves Type I: Majority of mortality occurs among older individuals. –Dall Sheep Type II: Constant rate of survival throughout lifetime. –American Robins Type III: High mortality among young, followed by high survivorship. –Sea Turtles
Survivorship Curves Plot Log 10 l x vs. X
Dall sheep (Ovis dalli) Life Table
Static life table for Dall Sheep x = age class n x = number alive d x = number dead l x = proportion surviving S 1000 = # per 1000 alive Ovis dalli dalli
Static life table for Dall Sheep Age class x = 0 = newborns = 100% survive Age class x = 1 only 623 in this age class = prop surviving (l 1 ) = 623/752 = Age class x = 2 only 509 survive = prop surviving (l 2 ) = 509/752 = 0.677
Age Distribution Age distribution of a population reflects its history of survival, reproduction, and growth potential Miller published data on age distribution of white oak (Quercus alba) –Determined relationship between age and trunk diameter –Age distribution biased towards young trees. Sufficient reproduction for replacement –Stable population
Age Distribution
Rio Grande Cottonwood populations (Populus deltoides wislizenii) are declining –Old trees not being replaced –Reproduction depends on seasonal floods Prepare seed bed Keep nursery areas moist –Because floods are absent, there are now fewer germination areas
Dynamic Population in a Variable Climate Grant and Grant studied Galapagos Finches. –Drought in 1977 resulted in no recruitment Gap in age distribution Additional droughts in 1984 and 1985 Reproductive output driven by exceptional year in 1983 –Responsiveness of population age structure to environmental variation
Age Structure
Creation of Stable Age Distribution Age 1 st Gen.2 nd Gen.3 rd Gen. Not Stable Stable % 30% 50%
Rates of Population Change Birth Rate: Number of young born per female Fecundity Schedule: Tabulation of birth rates for females of different ages
Frequency of Reproduction in Populations Time Number of offspring Discrete, non-overlapping Discrete, overlapping Continuous generation
Estimating Rates for an Annual Plant P. drummondii –R o = Net reproductive rate; Average number of seeds produced by an individual in a population during its lifetime –R o =Σl x m x X= Age interval in days l x = % pop. surviving to each age (x) m x = Average number seeds produced by each individual in each age category
Estimating Rates for an Annual Plant Because P. drummondii has non- overlapping generations, can estimate growth rate –Geometric Rate of Increase (λ): λ =N t+1 / N t N t+1 = Size of population at future time N t = Size of population at some earlier time
Estimating Rates when Generations Overlap Common Mud Turtle (K. subrubrum) –About half turtles nest each yr –Average generation time: T = Σ xl x m x / R o – X= Age in years –Per Capita Rate of Increase: r = ln R o / T –ln = Base natural logarithms
Fecundity (Fertility) Schedule
Life Table Calculations = Sum = 14.67
BIO 340 Exam 1 mean = 73%, sd = 15%