ECEG Group

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Abstract Event Heap Solution: ECEG

Video

ECEG System Features Resource Discovery

ECEG System Features Resource Discovery Generic Application Platform

ECEG System Features Resource Discovery Generic Application Platform Remote Control

ECEG System Features Resource Discovery Generic Application Platform Remote Control Instant Messenger

ECEG System – How to Use

ECEG System forumispace/download/eceg.htm

System Overview Application P2P Communication Discovery JXTA TCP/IP Wave LAN

BlueTooth

Infrared

Wave LAN

Transport layer solutions Event Heap Jini Jxta Definition –Transport layer’s responsibility is to define how traffic should be sent over inter- networks

Event Heap A centeral event dispatcher, all the message goes through the event heap server.

Jini Establishes a distributed system by moving interfaces of objects around the network Looku p Service Looku p Service Provide r Service Provide r Client

Jini Looku p Service Looku p Service Provide r Service Provide r Client

Jini Looku p Service Looku p Service Provide r Service Provide r Client Service Object Service Attribute

Jini Looku p Service Looku p Service Provide r Service Provide r Client

Jini Looku p Service Looku p Service Provide r Service Provide r Client

Jini Advantages –Simplicity. –Robustness. Disadvantages –Platform dependency. –IP based.

JXTA ”A layered model solution for developing Peer 2 Peer applications, consisting of protocols that are independent from underlying topology” -SUN

JXTA Peer 2 Peer Dynamic Lightweight

Chosen Technology: JXTA Advantages –Interoperability. –Platform Independent. –Ubiquity Disadvantages –Under Development. –Inherently Chatty.

ECEG System Application P2P Communication Discovery

Source Code public void discoveryEvent(DiscoveryEvent ev) { Debug.trace("-> MyPeerGroupNeigborhood.discoveryEvent", 1); DiscoveryResponseMsg response = ev.getResponse(); int index = -1; Peer peerTemp = null; try { String aResponse = response.getPeerAdv(); /* First we can elicit what peer has published the advert, we can then determine which groups it belongs to */ InputStream is = new ByteArrayInputStream((aResponse).getBytes()); peerAdvert = (PeerAdvertisement)AdvertisementFactory.newAdvertisement( new MimeMediaType("text/xml"), is); Debug.trace("Number of responses received from: " + peerAdvert.getName() + " is " + response.getResponseCount(), 2); index = neighborhoodData.doesPeerExist(peerAdvert.getPeerID()); Debug.trace("Peer Description: " + peerAdvert.getDescription(), 2); Enumeration enum = response.getResponses(); if (index >= 0) // the peer exists { Debug.trace("Peer exists", 1); neighborhoodData.setPeerAliveFlag(peerAdvert.getPeerID()); ParsePeer.parse( (Peer)neighborhoodData.vectorManip.elementAt(index), peerAdvert, enum, this, true); Debug.writePeerHtmlFile(peerAdvert.getName()); ParsePeer.dealWithSubAdvertisements(enum, (Peer)neighborhoodData.vectorManip.elementAt(index), this); Debug.trace("End of peer exists", 1); } else if (index < 0) { Debug.trace("Peer does not exist", 3); peerTemp = new Peer(); neighborhoodData.addPeer(peerTemp); ParsePeer.parse(peerTemp, peerAdvert, enum, this, false); ParsePeer.dealWithSubAdvertisements(enum, peerTemp, this); Debug.trace("End of peer does not exist", 1); discovery.getRemoteAdvertisements (null, DiscoveryService.ADV, null, null, 30, this); discovery.publish(myPeer.pipeAdvertisement, DiscoveryService.ADV); discovery.remotePublish(myPeer.pipeAdvertisement, DiscoveryService.ADV); } catch (IOException ioe) { Debug.error("An IO error occured!!"); Debug.error(ioe.toString()); ioe.printStackTrace(); } catch (Exception e) { e.printStackTrace(); } Debug.trace("<- MyPeerGroupNeigborhood.discoveryEvent", 1); }

Project Issues Project Scope Project Plan Adherence Extra Frills: –Mouse Sender/Receiver –Instant Messenger –Dynamic IP Discovery –Inter iSpace Communication

Problems Faced Team Member Loss Tomorrow’s Technology Inter-Subnet Peer Groups

Conclusion Wave LAN JXTA Layered Model Developed Application Future

Acknowledgements Li Wei Erik Eliasson Fredrik Kilander Teaching Team

Questions & Answers ?